Chapter 2, Problem 2.37E

Explanation of Solution

MIPS instructions:

The MIPS instruction for the given scenario as follows:

    #load $t5 = +

conversion: li $t5, 0x2B

    #load $t5 = 0

    li $t5, 0x30

    #load $t5 = 9

    li $t5, 0x39

    #$v0 = 0

    li $v0, 0

    #$t0 = $0 + $a0

    add $t0, $0, $a0

    #load $t1 = $t0

    lbu $t1, 0($t0)

    #$t3 = $t1 + $0

    add $t3, $t1, $0

    #$t0 = $t0 + 1

    addiu $t0, $t0, 1

    #load $t1 = $t0

    lbu $t1, 0($t0)

    #check char < '0'

Test:    slt $t2, $t1, $t6

    #if $t0 > $a0, go to noDig

    bne $t0, $a0, noDig

    #check char < '9'

        slt $t2, $t1, $t7

    #if $t2 = $0, go to noDig

    beq $t2, $0, noDig

    #$t1 = $t1 - $t6

    subu $t1, $t1, $t6

    #$v0 = $v0 * 10

    mul $v0, $v0, 10

    #$v0 = $v0 + $t1

    add $v0, $v0, $t1

    #$t0 = $t0 + 1

    addiu $t0, $t0, 1

    #load $t1 = $t0

    lbu $t1, 0($t0)

    #if $t1 > $0, go to Test

    bne $t1, $0, Test

    #if $t3 > $t5, go to Neg

    bne &#...