Computer Organization and Design MIPS Edition, Fifth Edition: The Hardware/Software Interface (The Morgan Kaufmann Series in Computer Architecture and Design)
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Chapter 2, Problem 2.19.2E

Explanation of Solution

The value of $t2:

The given is:

$t0 = 0xAAAAAAAA

$t1 = 0x12345678

sll $t2, $t0, 4

andi $t2, $t2, -1

  • The “sll” instruction is used to shift one position left to the bit. Here the register value “$t0” is shifted 4 positions left to the bit and finally store the result in the “$t2”.
  • The “andi” instruction is used to “AND” the constant value to the register “$t2” and store the result in the “$t2”.

Step1: Convert the hexadecimal value into the binary value

0xAAAAAAAA = 1010 1010 1010 1010 1010 1010 1010 1010           0x12345678 = 0001 0010 0011 0100 0101 0110 0111 1000

Step2: Left shift the “$t0” value

1010 1010 1010 1010 1010 1010 1010 0000   

Step2:

Here the first four bits removed and “0s” are added in the last 4 position.

Step3: Take 2’s complement for “-1” value.

1 = 0000 0000 0000 0000 0000 0000 0000 0001interchange given binary number:1111 1111 1111 1111 1111 1111 1111 1110add "1" to the interchange binary number1111 1111 1111 1111 1111 1111 1111 1110                   �

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