Explanation of Solution
The value of $t2:
The given is:
$t0 = 0xAAAAAAAA
$t1 = 0x12345678
Let consider the given question as:
sll $t2, $t0, 4
or $t2, $t2, $t1
- The “sll” instruction is used to shift one position left to the bit. Here the register value “$t0” is shifted 4 positions left to the bit and finally store the result in the “$t2”.
- The “or” instruction is used to “OR” the constant value to the register “$t2” and store the result in the “$t2”.
Step1: Convert the hexadecimal value into the binary value.
The corresponding binary value of “A” = 1010
The corresponding binary value of “1” = 0001
The corresponding binary value of “2” = 0010
The corresponding binary value of “3” = 0110
The corresponding binary value of “4” = 0100
The corresponding binary value of “5” = 0101
The corresponding binary value of “6” = 0110
The corresponding binary value of “7” = 0111
The corresponding binary value of “8” = 1000
Step2: Left shift the “$t0” value
Here the first four bits removed and “0s” are added in the last 4 position
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Computer Organization and Design MIPS Edition, Fifth Edition: The Hardware/Software Interface (The Morgan Kaufmann Series in Computer Architecture and Design)
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