Computer Organization and Design MIPS Edition, Fifth Edition: The Hardware/Software Interface (The Morgan Kaufmann Series in Computer Architecture and Design)
5th Edition
ISBN: 9780124077263
Author: David A. Patterson, John L. Hennessy
Publisher: Elsevier Science
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Expert Solution & Answer
Chapter 2, Problem 2.19.1E
Explanation of Solution
The value of $t2:
The given is:
$t0 = 0xAAAAAAAA
$t1 = 0x12345678
Let consider the given question as:
sll $t2, $t0, 4
or $t2, $t2, $t1
- The “sll” instruction is used to shift one position left to the bit. Here the register value “$t0” is shifted 4 positions left to the bit and finally store the result in the “$t2”.
- The “or” instruction is used to “OR” the constant value to the register “$t2” and store the result in the “$t2”.
Step1: Convert the hexadecimal value into the binary value.
The corresponding binary value of “A” = 1010
The corresponding binary value of “1” = 0001
The corresponding binary value of “2” = 0010
The corresponding binary value of “3” = 0110
The corresponding binary value of “4” = 0100
The corresponding binary value of “5” = 0101
The corresponding binary value of “6” = 0110
The corresponding binary value of “7” = 0111
The corresponding binary value of “8” = 1000
Step2: Left shift the “$t0” value
Here the first four bits removed and “0s” are added in the last 4 position
Expert Solution & Answer
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Chapter 2 Solutions
Computer Organization and Design MIPS Edition, Fifth Edition: The Hardware/Software Interface (The Morgan Kaufmann Series in Computer Architecture and Design)
Ch. 2 - Prob. 2.1ECh. 2 - Prob. 2.2ECh. 2 - Prob. 2.3ECh. 2 - Prob. 2.4ECh. 2 - Prob. 2.5ECh. 2 - Prob. 2.6.1ECh. 2 - Prob. 2.6.2ECh. 2 - Prob. 2.7ECh. 2 - Prob. 2.8ECh. 2 - Prob. 2.9E
Ch. 2 - Prob. 2.10ECh. 2 - Prob. 2.11ECh. 2 - Prob. 2.12.1ECh. 2 - Prob. 2.12.2ECh. 2 - Prob. 2.12.3ECh. 2 - Prob. 2.12.4ECh. 2 - Prob. 2.12.5ECh. 2 - Prob. 2.12.6ECh. 2 - Prob. 2.13.1ECh. 2 - Prob. 2.13.2ECh. 2 - Prob. 2.13.3ECh. 2 - Prob. 2.14ECh. 2 - Prob. 2.15ECh. 2 - Prob. 2.16ECh. 2 - Prob. 2.17ECh. 2 - Prob. 2.18.1ECh. 2 - Prob. 2.18.2ECh. 2 - Prob. 2.18.3ECh. 2 - Prob. 2.19.1ECh. 2 - Prob. 2.19.2ECh. 2 - Prob. 2.19.3ECh. 2 - Prob. 2.20ECh. 2 - Prob. 2.21ECh. 2 - Prob. 2.22ECh. 2 - Prob. 2.23ECh. 2 - Prob. 2.24ECh. 2 - Prob. 2.25.1ECh. 2 - Prob. 2.25.2ECh. 2 - Prob. 2.26.1ECh. 2 - Prob. 2.26.2ECh. 2 - Prob. 2.26.3ECh. 2 - Prob. 2.27ECh. 2 - Prob. 2.28ECh. 2 - Prob. 2.29ECh. 2 - Prob. 2.30ECh. 2 - Prob. 2.31ECh. 2 - Prob. 2.32ECh. 2 - Prob. 2.33ECh. 2 - Prob. 2.34ECh. 2 - Prob. 2.35ECh. 2 - Prob. 2.36ECh. 2 - Prob. 2.37ECh. 2 - Prob. 2.38ECh. 2 - Prob. 2.39ECh. 2 - Prob. 2.40ECh. 2 - Prob. 2.41ECh. 2 - Prob. 2.42ECh. 2 - Prob. 2.43ECh. 2 - Prob. 2.44ECh. 2 - Prob. 2.45ECh. 2 - Prob. 2.46.1ECh. 2 - Prob. 2.46.2ECh. 2 - Prob. 2.47.1ECh. 2 - Prob. 2.47.2ECh. 2 - Prob. 2.47.3E
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