Chapter 2, Problem 2.28E

Explanation of Solution

MIPS instruction:

The corresponding MIPS instruction for the given C code is as follows:

#set i = 0

add $t0, $0, $0

#check i < a

Loop1: slt $t2, $t0, $s0

#if "$t2=0" go to "Exit"

beq $t2, $0, Exit

#set j = 0

add $t1, $0, $0

#check j < b

Loop2: slt $t2, $t1, $s1

#if "$t2=0" go to "Loop3"

beq $t2, $0, Loop3

#add the variable "i" and "j"

add $t2, $t0, $t1

#multiply the "j" with 4

sll $t4, $t1, 4

#storing the "&D[4 * j]" to the "$t3"

add $t3, $t4, $s2

#store the addition of "i" and "j" to the "D[4 * j] "

sw $t2, 0($t3)

#add "1" to the variable "j"

addi $t1, $t1, 1

#jump to the loop2

j Loop2

#add "1" to the variable "i"

Loop3: addi $t0, $t0, 1

#jump to the loop1

j Loop1

Exit:

Explanation:

• Initially set the register “$t0” as 0. The “Loop1” will check “i” less than “a”, if the condition is true then it will again check the register “$t2” is equal to 0, here the condition is true it will exit the loop otherwise set the “j” value as 0.
• The “Loop2” will check “j” less than “b”, if the condition is true then it will again check the register “$t2” is equal to 0, here the condition is true it will go to the “Loop3” otherwise add the variables “i” and “j”...