Chapter 2, Problem 2.23E

Explanation of Solution

The value of “$t2”:

The given value of “$t0” is 0x00101000.

slt $t2, $0, $t0

The instruction “slt” is used to compare the values in the registers and sets the value to 1 if the value in first register is less than the second value. Otherwise, it sets the value to 0. Since “0” is less than the value of “$t0” then finally the value “1” is set into “$t2” register.

bne $t2, $0, ELSE

The value of “$t2” is 1 so it will execute the else instruction.

ELSE: addi $t2, $t2, 2

Here, the value in the register “$t2” and “2” are added and store the result in the “$t2” register...