![Genetic Analysis: An Integrated Approach (2nd Edition)](https://www.bartleby.com/isbn_cover_images/9780321948908/9780321948908_largeCoverImage.gif)
Genetic Analysis: An Integrated Approach (2nd Edition)
2nd Edition
ISBN: 9780321948908
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 2, Problem 20P
Experimental Insight 2.1 describes data, collected by a genetics class like yours, on the numbers of kernels of different colors in bicolor corn. To test the hypothesis that the presence of kernels of different colors in each ear is the result of the segregation of two alleles of a single gene, the class counted 12,356 kernels and found that 9304 were yellow and 3052 were white. Use chi-square analysis to evaluate the fit between the segregation hypothesis and the class results.
Expert Solution & Answer
![Check Mark](/static/check-mark.png)
Want to see the full answer?
Check out a sample textbook solution![Blurred answer](/static/blurred-answer.jpg)
Students have asked these similar questions
Give typed full explanation
The Genes you are examining exhibit a continuous pattern of variation. For these Genes, a Dominant Allele represents a 1 foot increase in overall height. If you cross the following individuals, AaBb and AaBb, what percentage of the offspring will be 7 feet tall. Assume an individual with no Dominant Alleles (aabb) is 4 feet tall. Report your answer as a percentage i.e., 22.1%.
While studying the genetics of the "Cute Faced Bat" face structure gene, three alleles ) are identified that produce 6 genotypes and 4 phenotypes “Cute”, “Super Cute Nose”, “Super Cute Face”, and “Super, Duper Cute” (equally expressing both Super Cute Face and Super Cute Nose). Given these observations, what can you conclude about the allele interactions?
Part 1
With use of Punnett diagrams discuss how the results of experiments
carried out by Austrian monk Gregor Mendel on pea plants brought about
the Law of Dominance, the Law of Segregation, and the Law of
Independent assortment.
Part 2
In humans, the gene that produces the disease Sickle Cell Anaemia is
recessive to the gene for healthy haemoglobin production.
a) How can two phenotypically healthy parents have a child who
suffers from Sickle cell Anaemia?
In your answer use suitable letters to show the genotypes of the
parents and construct a Punnett diagram to show all the
possibilities of the children's genotypes.
b) Based on the outcome of your Punnett diagram, state and
explain the probability of a child being a sufferer of Sickle Cell
Anaemia and the probability of a child not suffering from the
disease.
c) If an individual who suffers from Sickle cell disease has a child
with someone who is healthy (and not carrying the sickle cell
gene), what is the probability that the child…
Chapter 2 Solutions
Genetic Analysis: An Integrated Approach (2nd Edition)
Ch. 2 -
1. Compare and contrast the following terms:
a....Ch. 2 - For the cross , what is the expected genotype...Ch. 2 - 37. Galactosemia is an autosomal recessive...Ch. 2 - In mice, black coat color is dominant to white...Ch. 2 - Two parents plan to have three children. What is...Ch. 2 - Consider the cross AaBbCCAABbCc. a. How many...Ch. 2 - If a chi-square test produces a chi-square value...Ch. 2 -
8. Determine whether the statements below are...Ch. 2 - In the datura plant, purple flower color is...Ch. 2 - 10. The dorsal pigment pattern of frogs can be...
Ch. 2 - 11. Black skin color is dominant to pink skin...Ch. 2 - A male mouse with brown fur color is mated to two...Ch. 2 - 13. Figure 2.12 shows the results of Mendel’s...Ch. 2 - 14. An experienced goldfish breeder receives two...Ch. 2 -
15. The accompanying pedigree shows the...Ch. 2 -
16. A geneticist crosses a pure-breeding strain...Ch. 2 - Suppose an F1 plant from Problem 16 is crossed to...Ch. 2 - 18. In pea plants, the appearance of flowers along...Ch. 2 - 19. If two six-sided dice are rolled, what is the...Ch. 2 - Experimental Insight 2.1 describes data, collected...Ch. 2 -
21. The accompanying pedigree shows the...Ch. 2 - 22. The seeds in bush bean pods are each the...Ch. 2 - List all the different gametes that are possible...Ch. 2 - Organisms with the genotypes AABbCcDd and AaBbCcDd...Ch. 2 -
52. In humans, the ability to bend the thumb...Ch. 2 - In the fruit fly Drosophila, a rudimentary wing...Ch. 2 - In pea plants, plant height, seed shape, and seed...Ch. 2 - A variety of pea plant called Blue Persian...Ch. 2 - 29. In tomato plants, the production of red fruit...Ch. 2 - A male and a female are each heterozygous for both...Ch. 2 - 31. In a sample of families with children each,...Ch. 2 - Prob. 32PCh. 2 - A woman expressing a dominant phenotype is...Ch. 2 - Two parents who are each known to be carriers of...Ch. 2 - 33. An organism having the genotype AaBbCcDdEe is...Ch. 2 - 34. A man and a woman are each heterozygous...Ch. 2 - For a single dice roll, there is a 16 chance that...Ch. 2 - You have four guinea pigs for a genetic study. One...Ch. 2 - 37. Galactosemia is an autosomal recessive...Ch. 2 - Sweet yellow tomatoes with a pear shape bring a...Ch. 2 - A cross between a spicy variety of Capsicum annum...Ch. 2 - Alkaptonuria is an infrequent autosomal recessive...Ch. 2 - 41. Humans vary in many ways from one another....Ch. 2 - 42. In chickens, the presence of feathers on the...Ch. 2 -
43. A pure-breeding fruit fly with the...Ch. 2 - 44. Situs inversus is a congenital condition in...Ch. 2 - 45. Domestic dogs evolved from ancestral grey...Ch. 2 - Alleles of the IGF-1 gene in dogs, encoding...Ch. 2 - 49. The Basalt Seed Lending Library run by the...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Data set A summarizes F2 numbers from an F1 cross arising from two, true-breeding Drosophila strains (P generation), which differ with respect to two mutant traits. The traits of legs shows an autosomal incomplete dominance pattern and the traits for wings shows an X-linked regular dominance pattern. a) Produce a genetic hypothesis about the mode of inheritance of each of the alleles from your data set. You must come up with a hypothesis that both makes sense and will not be rejected, in other words, you need a hypothesis that will corroborate the experimental observations. b) Explain/describe how the data set seems to support your genetic hypothesis for each trait. For example, explain why you think a trait is recessive vs dominant or X-linked vs autosomal. To do this, you could comment on the observed ratios and/or differences or similarities in male and female numbers and explain how these provide support for your hypotheses. c) Assign genetic symbols to the four alleles involved.…arrow_forwardGene mapping using the Three-point Testcross a) Given the following alleles that control seed traits:W = wrinkled G = green R = roundw = smooth g = yellow r = oval b) Results of a cross with a triple heterozygote revealed the following phenotypes:30 smooth yellow round4 smooth green round958 wrinkled green round2 wrinkled yellow oval18 wrinkled yellow round946 smooth yellow oval16 smooth green oval26 wrinkled green oval c) Determine the order of the genes and the distance between them in centiMorgan (cM).Construct a gene map to show your results. TIP: Based on the phenotypes, determine the alleles in the gametesarrow_forwardstion 6 of 18 Suppose that a geneticist discovers a new mutation in Drosophila melanogaster that causes the flies to shake and quiver. She calls this mutation quiver, qu, and determines that it is due to an autosomal recessive gene. She wants to determine whether the gene encoding quiver is linked to the recessive gene for vestigial wings, vg. She crosses a fly homozygous for quiver and vestigial traits with a fly homozygous for the wild-type traits, and then uses the resulting F, females in a testcross. She obtains the flies from this testcross. Phenotype Number of flies vg* qu+ 230 vg qu 224 vg qut vg* qu 97 99 Test the hypothesis that the genes quiver and vestigial assort independently by calculating the chi-squared, X², for this hypothesis. Provide the X2 to one decimal place. X2 = Does the X value support the hypothesis that the quiver and vestigial genes assort independently? Why or why not? the partial table of critical values for X2 calculations to test this hypothesis.arrow_forward
- Consider the first category of test-cross offspring shown in figure 8.2 (+b, LS). Consider also that the parents of the heterozygous female flies in the test cross had the following genotypes: bb, SS, and +, LL. A. What would be the physical phenotype of these flies? B. If PC was conducted with the DNA of one of these flies using the primers for the molecular marker, what would be the appearance of the bands on an electrophoresis gel with the PC products? C. If the gene for black body and the locus for the molecular marker (L long or S short) were unlinked, what proportion of the test-cross progeny would be black flies that are heterozygous for the molecular marker? What proportion would be flies with normal body color, which are homozygous for one form of the molecular marker? D. If the gene for black body and the locus for the molecular marker were linked, how would the proportion of flies be different?arrow_forwardGiven the following testcross data for corn in which the genes for fine stripe (f), bronze aleurone (bz) and knotted leaf (Kn) are involved: PhenotypeNumber Kn + +451 Kn f +134 + + + 97 + f bz436 Kn + bz18 + + bz119 + f +24 Kn f bz86 Total:1,365 Maize geneticists tend to be like Drosophila geneticists utilizing a + to indicate the wild type allele (which also is dominant) and a lower case letter for the mutant allele (which is recessive). The first thing I suggest in attacking this problem is to use the typical convention of upper case letters for dominant alleles and lower case letters for recessive alleles as follows: F = wild type, f = fine stripe; B = wild type, b = bronze aleurone K = wild type, k = knotted leaf Then we can rewrite the phenotypes in a “language” that is more easily understood: PhenotypeNumber k F B451 k f B134 K F B97 K f b436 k F b18 K F b119 K f B24 k f b86 Total:1,365 a) Determine the sequence (order) of the…arrow_forwardThe data set attached presents the results of a testcross using female flies heterozygous for three traits and male flies, which are homozygous recessive. For simplicity, mutant alleles are shown with letters a, b, and c and wildtype alleles are indicated by a “+” symbol. For this part of the report do the following in order: a) Determine the gene order (which gene is in the middle?)d) Construct a genetic map for the three genes, including the map distances between them. Clearly indicate the logic you followed and show all your calculations. Include the full distance calculations for the two most distanced genes (do not just add the other 2 distances). Ensure the work is neat and clear and does not contain spelling or grammatical errors so that it is understandable. Make sure to double check the solution provided.arrow_forward
- Give typing answer with explanation and conclusionarrow_forwardProblem) A university student is studying the inheritance of 2 genes of pea plants. Color of plant: Blue is dominant (B), and yellow is recessive (b) Spikes or no spikes: Having spikes is dominant (G), and having no spikes is recessive (g). Which of the following findings would indicate to the student that these two traits are located close together on the same chromosome? a) The traits show independent assortment b) All gametes of a double heterozygous individual (BbGg) are either BG or bg c) A double heterozygous individual has four types of gametes in approximately equal proportions: BG, Bg, bG, and bg d) Student finds that there is frequent crossing over between the 2lociarrow_forwardMultiple crosses were made between true-breeding lines of black and yellow Labrador retrievers. All the F1 progeny were yellow. When these progeny were intercrossed, they produced an F2 consisting of 121 yellow, 9 black and 30 chocolate. What epistatic ratio and what kind of epistasis is approximated in the F2? Propose a biochemical pathway for coat color in Labrador retrievers based on the type of epistasis. Correlate each genotype with the phenotype that would occur in your pathway. Also show the frequency of each genotype. A-B- A-bb aaB- aabbarrow_forward
- True-breeding diabetes-resistant male monkeys were bred to true-breeding wildtype female monkeys. All the F1 monkeys are phenotypically wildtype. The F1 monkeys are bred to each other, producing eight F2 babies. Only one of the eight F2 monkeys has the diabetes resistance. Is it possible for this condition to be controlled by a single autosomal gene? Use chi-square analysis to test the hypothesis, show your work, and explain your conclusion.arrow_forwardYour task will ultimately be to generate a hypothesis and test this hypothesis using a chi square test. There are four possible phenotypes for these kernels:Purple and Smooth Purple and Shrunken Yellow and Smooth Yellow and Shrunken The purple colour results from the formation of a purple pigment in the skin of the kernel. The gene locus for the colour trait is designated “R”. The wrinkled phenotype arises from a decrease in the amount starch produced within the kernel. The gene locus for the texture trait is designated “S”. Create a Punnett square for this cross and present the expected phenotypic ratio. Present the results in a table as dihybrids and determine the observed phenotypic ratio of purple/smooth to purple/shrunken to yellow/smooth to yellow/shrunken. Consider the plant as a whole rather than the individual cobs. Generate a null hypothesis and perform a chi square test on the data. Report the equation used, the chi square value, the degrees of freedom, and the resulting…arrow_forwardA complementation analysis was performed using pea plants which normally have purple flowers. Twenty-five mutants for white flower colour were discovered across 10 populations. The mutants were bred in a complementation test which showed two complementation groups with 10 mutants in one group and 15 in the other. (a) How many genes contribute to flower colour in pea plants based on this data? (b) Is it likely that more genes contribute to pea plant flower colour? Explainarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305251052/9781305251052_smallCoverImage.gif)
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
How to solve genetics probability problems; Author: Shomu's Biology;https://www.youtube.com/watch?v=R0yjfb1ooUs;License: Standard YouTube License, CC-BY
Beyond Mendelian Genetics: Complex Patterns of Inheritance; Author: Professor Dave Explains;https://www.youtube.com/watch?v=-EmvmBuK-B8;License: Standard YouTube License, CC-BY