Genetic Analysis: An Integrated Approach (2nd Edition)
2nd Edition
ISBN: 9780321948908
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Videos
Textbook Question
Chapter 2, Problem 7P
If a chi-square test produces a chi-square value of 7.83 with 4 degrees of freedom,
a. In what interval range does the P value fall?
b. Is the result sufficient to reject the chance hypothesis?
c. Above what chi-square value would you reject the chance hypothesis for an experiment with 7 degrees of freedom?
Expert Solution & Answer
Learn your wayIncludes step-by-step video
schedule05:07
Students have asked these similar questions
You perform a chi-square test to compare observed and expected values and obtain a chi-square value of 9.4 with 3 degrees of freedom. What do you conclude?
it is not likely that the difference between observed and expected values is due to random chance, since p>0.05
it is impossible to conclude anything from this information
it is likely that the difference between observed and expected values is due to random chance, since p>0.05
it is likely that the difference between observed and expected values is due to random chance, since p<0.05
the experiment was done incorrectly and must be repeated
it is not likely that the difference between observed and expected values is due to random chance, since p<0.05
Could you please highlight the correct answer. and explain it
What does P-value indicate? In statistical analysis the results for two sets of data are presented with P < 0.01 and P<0.005. What does it mean?
Chapter 2 Solutions
Genetic Analysis: An Integrated Approach (2nd Edition)
Ch. 2 -
1. Compare and contrast the following terms:
a....Ch. 2 - For the cross , what is the expected genotype...Ch. 2 - 37. Galactosemia is an autosomal recessive...Ch. 2 - In mice, black coat color is dominant to white...Ch. 2 - Two parents plan to have three children. What is...Ch. 2 - Consider the cross AaBbCCAABbCc. a. How many...Ch. 2 - If a chi-square test produces a chi-square value...Ch. 2 -
8. Determine whether the statements below are...Ch. 2 - In the datura plant, purple flower color is...Ch. 2 - 10. The dorsal pigment pattern of frogs can be...
Ch. 2 - 11. Black skin color is dominant to pink skin...Ch. 2 - A male mouse with brown fur color is mated to two...Ch. 2 - 13. Figure 2.12 shows the results of Mendel’s...Ch. 2 - 14. An experienced goldfish breeder receives two...Ch. 2 -
15. The accompanying pedigree shows the...Ch. 2 -
16. A geneticist crosses a pure-breeding strain...Ch. 2 - Suppose an F1 plant from Problem 16 is crossed to...Ch. 2 - 18. In pea plants, the appearance of flowers along...Ch. 2 - 19. If two six-sided dice are rolled, what is the...Ch. 2 - Experimental Insight 2.1 describes data, collected...Ch. 2 -
21. The accompanying pedigree shows the...Ch. 2 - 22. The seeds in bush bean pods are each the...Ch. 2 - List all the different gametes that are possible...Ch. 2 - Organisms with the genotypes AABbCcDd and AaBbCcDd...Ch. 2 -
52. In humans, the ability to bend the thumb...Ch. 2 - In the fruit fly Drosophila, a rudimentary wing...Ch. 2 - In pea plants, plant height, seed shape, and seed...Ch. 2 - A variety of pea plant called Blue Persian...Ch. 2 - 29. In tomato plants, the production of red fruit...Ch. 2 - A male and a female are each heterozygous for both...Ch. 2 - 31. In a sample of families with children each,...Ch. 2 - Prob. 32PCh. 2 - A woman expressing a dominant phenotype is...Ch. 2 - Two parents who are each known to be carriers of...Ch. 2 - 33. An organism having the genotype AaBbCcDdEe is...Ch. 2 - 34. A man and a woman are each heterozygous...Ch. 2 - For a single dice roll, there is a 16 chance that...Ch. 2 - You have four guinea pigs for a genetic study. One...Ch. 2 - 37. Galactosemia is an autosomal recessive...Ch. 2 - Sweet yellow tomatoes with a pear shape bring a...Ch. 2 - A cross between a spicy variety of Capsicum annum...Ch. 2 - Alkaptonuria is an infrequent autosomal recessive...Ch. 2 - 41. Humans vary in many ways from one another....Ch. 2 - 42. In chickens, the presence of feathers on the...Ch. 2 -
43. A pure-breeding fruit fly with the...Ch. 2 - 44. Situs inversus is a congenital condition in...Ch. 2 - 45. Domestic dogs evolved from ancestral grey...Ch. 2 - Alleles of the IGF-1 gene in dogs, encoding...Ch. 2 - 49. The Basalt Seed Lending Library run by the...
Additional Science Textbook Solutions
Find more solutions based on key concepts
Raw Oysters and Antacids: A Deadly Mix? The highly acidic environment of the stomach kills most bacteria before...
Microbiology with Diseases by Body System (4th Edition)
How do you think a cell performing cellular respiration rids itself of the resulting CO2?
Campbell Biology in Focus (2nd Edition)
4. Three groups of nonvascular plants are _______, ______, and _______. Three groups of seedless vascular plant...
Biology: Life on Earth (11th Edition)
All of the following processes are involved in the carbon cycle except: a. photosynthesis b. cell respiration c...
Human Biology: Concepts and Current Issues
21-Year-Old Female with Skeletal Injuries
While riding her bike to campus, 21-year-old Liliana Rose was struck...
Human Anatomy & Physiology (11th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Assume that a Chi-square test was conducted to test the goodness of fit to a 9:3:3:1 ratio and a Chi-square value of 10.62 was obtained. Should the null hypothesis be accepted?arrow_forwardExample 3.5.7 Fish Vertebrae Consider the distribution of vertebrae given in Table 3.5.1. In Exam- ple 3.5.5 we found that the mean of Y is µy = 21.49. The variance of Y is VAR(Y) = of = (20 – 21.49) x Pr{Y = 20} 21) %3D + (21 – 21.49)? x Pr{Y + (22 – 21.49)? x Pr{Y = 22} + (23 – 21.49) x Pr{Y = 23} = (-1.49) x 0.03 + (-.49) x 0.51 + (0.51) x 0.40 + (1.51)² × 0.06 = 2.2201 x 0.03 + .2401 x 0.51 + .2601 x 0.40 + 2.2801 x 0.06 = 0.066603 + 0.122451 + 0.10404 + 0.136806 = 0.4299. The standard deviation of Y is ay = V0.4299 - 0.6557. %3Darrow_forwardThe confidence interval is reported as follows: Lower 95% CI < p < Upper 95% CI For this question you will be calculating the confidence interval but only reporting the Upper 95% CI using the Agresti-Coull Method. ( (you'll need to know the whole 95% CI for a future question) Do NOT use calculations from previous questions, this is a new scenario. In the Invisible Gorilla Experiment, 24 students were watching the video, only 7 noticed the gorilla. Calculate the 95% CI using the Agresti-Coull method, but only report the Upper 95% CI. Report your answer to 3 decimals.arrow_forward
- If you perform a Chi-Squared analysis and determine that your result is greater than the critical value, what would you do? a. Reject H0, accept HA b. Accept H0 c. neitherarrow_forward1). The p-value for this test is . 072. Do we reject the null hypothesis?2). Is there sufficient evidence to conclude that there is a statistically significant difference in mean weight between the different NYHA groups?3). Pretend for a moment that the resulting p-value was 0.02. Do we reject the null hypothesis in this case? Why or why not? If we were to reject the null hypothesis, we would conclude that there is sufficient evidence to suggest a statistically significant difference in mean weight between the NYHA groups. The NYHA variable has four levels: would we know which of the four NYHA group means gave the statistically significant result?arrow_forwardIf the chi-square value is 0 under the degree of freedom 1. What could be the interpretation and does it fit in the population of Hardy-Weinberg equilibrium?arrow_forward
- Considering that I have a chi-square test critical value of 3.84 what is the minimum X2 value for me to reject the null hypothesis? Is it 3.84 or 3.85?arrow_forward17) In chi-squared analysis... A. If the observed data exactly agree with the predictions of the hypothesis, then we expect the p-value to be (1.0, 100, less than 0.05, 0, greater than 0.05) B. If the observed data closely agree with the predictions of the hypothesis, then we expect the p-value to be (1.0, 100, less than 0.05, 0, greater than 0.05) C. If the observed data do not at all agree with the predictions of the hypothesis, then we expect the p-value to be (1.0, 100, less than 0.05, 0, greater than 0.05) Chose one from the parenthesis for each question.arrow_forwardWhich conclusion is supported by the results shown by the Punnett square?arrow_forward
- The two-tailed p-value associated with this test is 0.860. Should the null hypothesis be rejected? Is there sufficient evidence to suggest that there is a statistically significant difference between the two means in question? If we now wanted to know whether there was a difference in weight between those with a low NYHA class (1 and 2) and those with a high NYHA class (3 and 4), what p-value would you report?arrow_forward1) Chi-square analysis generates a p value, an important indicator of statistical support for a hypothetical outcome. If a p value = 0.05 > p > 0.01, the tested hypothesis fails to be falsified. Agree/Disagree? Answer with explanation here:arrow_forwardCould you please highlight the correct answer. and explain itarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Introduction to the NIOSH Manual of Analytical Methods Fifth edition; Author: Centers for Disease Control and Prevention (CDC);https://www.youtube.com/watch?v=B5rUrKLMoas;License: Standard Youtube License