1 .546 g Sample of magnesium metal is heated in sufficient air at high temperature. The reaction forms 2.512 g MgO and a small quantity of another magnesium-containing compound that is 72.24 % magnesium by mass. The formula of the other magnesium containing compound has to be determined.
1 .546 g Sample of magnesium metal is heated in sufficient air at high temperature. The reaction forms 2.512 g MgO and a small quantity of another magnesium-containing compound that is 72.24 % magnesium by mass. The formula of the other magnesium containing compound has to be determined.
Solution Summary: The author explains the formula of the other magnesium-containing compound. Nitrogen and oxygen are the two most abundant components in the atmosphere.
1.546g Sample of magnesium metal is heated in sufficient air at high temperature. The reaction forms 2.512gMgO and a small quantity of another magnesium-containing compound that is 72.24% magnesium by mass. The formula of the other magnesium containing compound has to be determined.
(b)
Interpretation Introduction
Interpretation:
1.546g Sample of magnesium metal is heated in sufficient air at high temperature. The reaction forms 2.512gMgO and a small quantity of another magnesium-containing compound that is 72.24% magnesium by mass. The name of the compound has to be given.
(c)
Interpretation Introduction
Interpretation:
1.546g Sample of magnesium metal is heated in sufficient air at high temperature. The reaction forms 2.512gMgO and a small quantity of another magnesium-containing compound that is 72.24% magnesium by mass. The fraction of the original magnesium is in the second compound has to be calculated.
CHEMICAL KINETICS. One of the approximation methods for solving the rate equation is the limiting or determining step approximation method. Explain what it consists of.
CHEMICAL KINETICS. Indicate the approximation methods for solving the rate equation.
TRANSMITTANCE
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Please identify the one structure below that is consistent with the 'H NMR and IR spectra
shown and draw its complete structure in the box below with the protons alphabetically labeled as
shown in the NMR spectrum and label the IR bands, including sp³C-H and sp2C-H stretch, indicated by
the arrows.
D
4000
OH
LOH
H₂C
CH3
OH
H₂C
OCH3
CH3
OH
3000
2000
1500
HAVENUMBERI-11
1000
LOCH3
Draw your structure below and label its equivalent protons according to the peak labeling that is used
in the NMR spectrum in order to assign the peaks.
Integrals indicate number of equivalent protons. Splitting patterns are: s=singlet, d=doublet, m-multiplet
8
3Hb s
m
1Hd s
3Hf
m 2Hcd
2Had
1He
鄙视
m
7
7
6
5
4
3
22
500
T
1
0
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