Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN: 9781305251052
Author: Michael Cummings
Publisher: Cengage Learning
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Chapter 19.8, Problem 1GR
Why don’t genetic markers on the Y chromosome undergo recombination? Why is this lack of recombination a necessity for these markers to be used in tracing migrations?
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In linkage mapping, how do we measure the distance between genes on a chromosome?
options:
A) The number of gametes used is proportional to the percent recombination in offspring.
B) The number of offspring produced is equal to the percent recombination during crossover.
C) The number of chromosomes resulting from crossover is equal to the distance the genes are apart in any one gamete.
D) The percentage of recombinant offspring is directly proportional to how far apart the genes are on the chromosome.
A chromosome of genotype C D recombines with a homolog of genotype c d during meiosis when Spo11 produces a double-strand break between genes C and D. If anticrossover helicase disentangles the invading strand, the likely outcome would be
A) two C D and two c d gametes. B) two C d and two c D gametes. C) one C D, one C d, one c D, and one c d gamete. D) four C D gametes. E) four c d gametes
Because of the relatively high frequency of meiotic errors that lead to developmental abnormalities in humans, many research efforts have focused on identifying correlations between error frequency and chromosome morphology and behavior. Tease et al. (2002) studied human fetal oocytes of chromosomes 21, 18, and 13 using an immunocytological approach that allowed a direct estimate of the frequency and position of meiotic recombination. Below is a summary of information [modified from Tease et al. (2002)] that compares recombination frequency with the frequency of trisomy for chromosomes 21, 18, and 13. (Note: You may want to read appropriate portions of Chapter 8 for descriptions of these trisomic conditions.) Trisomic Mean Recombination Frequency Live-born Frequency Chromosome 21 1.23 1/700 Chromosome 18 2.36 1/3000–1/8000 Chromosome 13 2.50 1/5000–1/19,000 (a) What conclusions can be drawn from these data in terms of recombination and nondisjunction frequencies? How might…
Chapter 19 Solutions
Human Heredity: Principles and Issues (MindTap Course List)
Ch. 19.8 - Why dont genetic markers on the Y chromosome...Ch. 19.8 - Prob. 2GRCh. 19 - If you suspected that heterozygous carriers of a...Ch. 19 - If allele frequencies in the hemoglobin gene are...Ch. 19 - Prob. 1QPCh. 19 - How Can We Measure Allele Frequencies in...Ch. 19 - How Can We Measure Allele Frequencies in...Ch. 19 - Prob. 4QPCh. 19 - Prob. 5QPCh. 19 - How Can We Measure Allele Frequencies in...
Ch. 19 - How Can We Measure Allele Frequencies in...Ch. 19 - How Can We Measure Allele Frequencies in...Ch. 19 - Using the HardyWeinberg Law in Human Genetics...Ch. 19 - Prob. 10QPCh. 19 - Using the HardyWeinberg Law in Human Genetics In a...Ch. 19 - Prob. 12QPCh. 19 - Measuring Genetic Diversity in Human Populations...Ch. 19 - Measuring Genetic Diversity in Human Populations...Ch. 19 - Prob. 15QPCh. 19 - Measuring Genetic Diversity in Human Populations...Ch. 19 - Prob. 17QPCh. 19 - Prob. 18QPCh. 19 - Measuring Genetic Diversity in Human Populations...Ch. 19 - Natural Selection Affects the Frequency of Genetic...Ch. 19 - Prob. 21QPCh. 19 - Prob. 22QPCh. 19 - The Evolutionary History and Spread of Our Species...Ch. 19 - Prob. 24QPCh. 19 - Genomics and Human Evolution The Denisovan genome...
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- Are two genes linked if not linked to the same marker on a chromosome.? Let's say we want to figure out whether two genes are linked on a particular chromosome so we cross-test them to a marker gene on that chromosome. Gene A is found to have an approximate 50% recombinant frequency so we say it's not linked to the marker. The other gene B however is found to have 40% recombinant frequency with our marker so we say it's linked. Now the question is are the two Genes A and B linked or not? Please explain your reasoning.arrow_forwardWhich of these two mechanisms might be promoted by thepresence of the same transposable element in many places in a species’ genome?arrow_forward12) An individual with genotype AaBbCCDdEE can make many kinds of gametes. Which of the following correctly describes why this situation is possible? A) recurrent mutations form new alleles B) crossing over during prophase I leads to genetic variety C) different possible assortment of chromosomes/alleles into gametes occurs D) there is a tendency for dominant alleles to segregate together 13) Let P = purplearrow_forward
- In the diagram in the box below the horizontal line represents a chromosome and A, B, C, D and E represent the position of genes on the chromosome. You would expect the highest frequency of recombination of genes to occur between? A BC D E Lll S a) Between genes B and D b) Between genes B and C c) Between genes A and B d) Between genes A and Carrow_forwardTHE GENES A, B AND C ARE LINKED ON CHROMOSOME 2 OF S. CEREVISIAE. IN A SERIES OF TWO-POINT MAPPING CROSSES, THE GENETIC DISTANCES SHOWN BELOW WERE DETERMINED. WHAT IS THE GENE ORDER? A-C: 28 A-B: 16 B-C: 41 A-B-C B-A-C A-C-Barrow_forwardThe answer is "D" but can you explain in a short summary why D is the answer pleasearrow_forward
- What is a molecular marker? Elaborate physical chromosome mapping with the help of molecular markersarrow_forwardWhat does a recombination frequency of 50% indicate? (choose one answer only) a) All of the offspring have combinations of traits that match one of the two parents. b) The genes are located on sex chromosomes. c) The two genes are likely to be located on different chromosomes. D0 Abnormal meiosis has occurred.arrow_forwardAn individual is heterozygous for a reciprocal translocation, with the following chromosomes: A • B C D E F A • B C V W X R ST • U D E F R ST • U V W X Q. Explain why the fertility of this individual is likely to be less than the fertility of an individual without a translocation.arrow_forward
- Based on the data in Table 1, which individual(s) is/are heterozygous? Select all that apply a) B IV-8 b) C IV-3 c) B IV-9 d) A IV-3arrow_forwardHow would the process of the double holiday junction model differ if identical DNA molecules were used in place of homologous ones? A.) Crossing over would NEVER be observed B.) No change the entire process would be the same C.) Gene conversion would never occur D.) Crossing over would ALWAYS be observed do not copy from othersarrow_forwardChoose which of the following is true: a) Haploid cells have one allele per gene b) Haploid cells have two alleles per genearrow_forward
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