Human Heredity: Principles and Issues (MindTap Course List)
Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN: 9781305251052
Author: Michael Cummings
Publisher: Cengage Learning
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Chapter 19, Problem 13QP

Measuring Genetic Diversity in Human Populations

Why is it that mutation, acting alone, has little effect on gene frequency?

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Mutation O Silent mutation from one allele to another ■ Suppose one allele (A1) mutates to another (A2) at some rate, μ, each generation within a population, and A2 mutates to A1 at some other rate, v. Suppose also that A1 and A2 are selectively neutral - they confer equal fitness. what is the equilibrial frequency of each of the two alleles (p* and q*)? You can think of the mathematical result as p* being the mutation rate towards A1 divided by the sum of the mutation rates. OR, p* is the proportion of all mutation rates (µ+v) that is mutation in the A1 direction (v). See box 7.7. ● ● ● μ = mutation from A1 to A2 v = mutation from A2 to A1 p* = v/(μ+v) Example: A1 mutates to A2 in 0.0004 of all offspring per generation. In other words the probability of mutation from A1 to A2 is 0.0004. A2 mutates to A1 in 0.0001 of all offspring per generation. What is the expected equilibrial abundance A1 and A2? μ = mutation from A1 to A2 = 0.0004 v = mutation from A2 to A1 = 0.0001 p* = v/(μ+v) =…
O Mutation-selection balance Suppose that one allele A₁ mutates to another allele A2 at some rate, μ. Suppose as well that A₁ is dominant over A2 such that A₁A1 and A₁A2 both have the same fitness, but that individuals that are homozygous recessive (A2A2) for the mutant allele A2 are less fit than the dominant genotype by some amount s, the selection coefficient. In this case, A2 mutant alleles come into the population at rate µ, and are removed from the population only when the show up in homozygous genotypes. The gory mathematical proof can be found in Box 7.8, which tells us that: O ■ Example: Suppose A₁ mutates to A2 at rate 0.005, but A₂A2 homozygous recessives are 50% less fit (s = 0.5) than either A₁A1 or A₁A2. What are the expected equilibrial abundances of A₁ and A2? μ = 0.005 S = 0.5 p* = 1-sqrt(µ/s) = 1-sqrt(0.005/0.5) = 0.9 = sqrt(µ/s) = sqrt(0.005/0.5) = 0.1 ● * p = = 1-sqrt(µ/s) q* = sqrt(μ/s) ● Question: Suppose A₁ mutates to A2 at rate 0.01, but A₂A2 homozygous…
Which one of the following options most accurately describes the process that generates the signature of a selective sweep in DNA sequence data? suppression of mutation over a long haplotype centered on a positively selected allele genetic hitchhiking of neutral alleles flanking the favored allele at the nucleotide site under positive selection O higher than average recombination around the core allele under positive selection
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Genetic Variation and Mutation | 9-1 GCSE Science Biology | OCR, AQA, Edexcel; Author: SnapRevise;https://www.youtube.com/watch?v=bLP8udGGfHU;License: Standard YouTube License, CC-BY