Chapter 19, Problem 70GP

(a)

To determine

The current passes through the body.

Answer to Problem 70GP

The current trough the person’s body is $0.116\text{A}$ .

Explanation of Solution

Given info:

The resistance of the person’s body is, $R=950\Omega$ .

The voltage connected to person is, $V=110\text{V}$ .

Formula Used:

The expression to calculate the current trough the person’s body is,

  $I=\frac{V}{R}$

Calculation:

Substitute all the values in the above expression.

  $\begin{array}{c}I=\frac{110\text{V}}{950\Omega }\\ =0.116\text{A}\end{array}$

Conclusion:

Thus, the current trough the person’s body is $0.116\text{A}$ .

(b)

To determine

The resistance through the person’s body with alternative path.

Answer to Problem 70GP

The current through the person’s body with alternative path is $0.116\text{A}$ .

Explanation of Solution

Introduction:

The current through the each resistor in the series connection remains same.

The resistance of the alternative path $45\Omega$ connects in the series with resistance of the person’s body, so the current through the person’s body remain same. The value of the current in the person’s body without alternative resistance and with alternative resistance is $0.116\text{A}$ .

Conclusion:

Thus, the current through the person’s body with alternative path is $0.116\text{A}$ .

(c)

To determine

.The current passes through the person with

Answer to Problem 70GP

The current passes through the person with alternative path is $1.38\text{A}$ .

Explanation of Solution

Given info:

The at most current through the voltage source is, $I_a=1.5\text{A}$ .

Formula Used:

The expression to calculate the current passes through the person with alternative path is,

  $I_1=I_a-I$

Calculation:

Substitute all the values in the above expression.

  $\begin{array}{c}{I}_1=1.5\text{A}-0.116\text{A}\\ =1.38\text{A}\end{array}$

Conclusion:

Thus, the current passes through the person with alternative path is $1.38\text{A}$ .