Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 19, Problem 30P
To determine

The magnitudes and direction of current across each resistor in the given circuit if each batter has internal resistance of 1 ohm.

Expert Solution & Answer
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Answer to Problem 30P

The magnitudes and direction of current across each resistor in the given circuit are I1=0.1316A , I2=0.3099A , and I3=0.1783A .

Explanation of Solution

Given information:

Consider the given circuit.

Physics: Principles with Applications, Chapter 19, Problem 30P

Formula used:

Apply Kirchhoff’s voltage law in the circuit to determine the currents.

Calculation:

Apply Kirchhoff’s voltage law in the upper loop.

  25I118I21I1+9=026I1+18I2=9    … (1)

Apply Kirchhoff’s voltage law in the lower loop.

  18I2+35I3+1I312=018I2+36I3=12    … (2)

At node (a), apply Kirchhoff’s current law.

  I2=I1+I3    … (3)

Substitute the value from equation (3) to equation (1).

  18I2+36(I2I1)=1218I2+36I236I1=1236I1+54I2=12    … (4)

On solving equation (1) and (4),

  I1=0.1316AI2=0.3099A

Substitute the values in equation (3).

  0.3099=0.1316+I3I3=0.1783A

Therefore, the magnitudes and direction of current across each resistor in the given circuit are I1=0.1316A , I2=0.3099A , and I3=0.1783A .

Chapter 19 Solutions

Physics: Principles with Applications

Ch. 19 - Prob. 11QCh. 19 - Prob. 12QCh. 19 - Prob. 13QCh. 19 - Prob. 14QCh. 19 - Prob. 15QCh. 19 - Prob. 16QCh. 19 - Given the circuit shown in Fig. 19-38, use the...Ch. 19 - Prob. 18QCh. 19 - Prob. 19QCh. 19 - 19. What is the main difference between an analog...Ch. 19 - What would happen if you mistakenly used an...Ch. 19 - Prob. 22QCh. 19 - Prob. 23QCh. 19 - Prob. 24QCh. 19 - Prob. 1PCh. 19 - Prob. 2PCh. 19 - Prob. 3PCh. 19 - Prob. 4PCh. 19 - Prob. 5PCh. 19 - Prob. 6PCh. 19 - Prob. 7PCh. 19 - Prob. 8PCh. 19 - Prob. 9PCh. 19 - Prob. 10PCh. 19 - Prob. 11PCh. 19 - Prob. 12PCh. 19 - Prob. 13PCh. 19 - Prob. 14PCh. 19 - Prob. 15PCh. 19 - Prob. 16PCh. 19 - Prob. 17PCh. 19 - Prob. 18PCh. 19 - Prob. 19PCh. 19 - Prob. 20PCh. 19 - Prob. 21PCh. 19 - Prob. 22PCh. 19 - Prob. 23PCh. 19 - Prob. 24PCh. 19 - Prob. 25PCh. 19 - Prob. 26PCh. 19 - Prob. 27PCh. 19 - Prob. 28PCh. 19 - Prob. 29PCh. 19 - Prob. 30PCh. 19 - Prob. 31PCh. 19 - Prob. 32PCh. 19 - Prob. 33PCh. 19 - Prob. 34PCh. 19 - Prob. 35PCh. 19 - Prob. 36PCh. 19 - Prob. 37PCh. 19 - Prob. 38PCh. 19 - Prob. 39PCh. 19 - Prob. 40PCh. 19 - Prob. 41PCh. 19 - Prob. 42PCh. 19 - Prob. 43PCh. 19 - Prob. 44PCh. 19 - Prob. 45PCh. 19 - Prob. 46PCh. 19 - Prob. 47PCh. 19 - Prob. 48PCh. 19 - Prob. 49PCh. 19 - Prob. 50PCh. 19 - Prob. 51PCh. 19 - Prob. 52PCh. 19 - Prob. 53PCh. 19 - Prob. 54PCh. 19 - Prob. 55PCh. 19 - Prob. 56PCh. 19 - Prob. 57PCh. 19 - Prob. 58PCh. 19 - Prob. 59PCh. 19 - Prob. 60PCh. 19 - Prob. 61PCh. 19 - Prob. 62PCh. 19 - Prob. 63PCh. 19 - Prob. 64GPCh. 19 - Prob. 65GPCh. 19 - Prob. 66GPCh. 19 - Prob. 67GPCh. 19 - Prob. 68GPCh. 19 - Prob. 69GPCh. 19 - Prob. 70GPCh. 19 - Prob. 71GPCh. 19 - Prob. 72GPCh. 19 - Prob. 73GPCh. 19 - Prob. 74GPCh. 19 - Prob. 75GPCh. 19 - Prob. 76GPCh. 19 - Prob. 77GPCh. 19 - Prob. 78GPCh. 19 - Prob. 79GPCh. 19 - Prob. 80GPCh. 19 - Prob. 81GPCh. 19 - Prob. 82GPCh. 19 - Prob. 83GPCh. 19 - Prob. 84GPCh. 19 - Prob. 85GPCh. 19 - Prob. 86GPCh. 19 - Prob. 87GP
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