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(a)
Interpretation:
The abbreviated electronic configuration for metal ion
Concept introduction:
A transition metal cation has no outer s-electrons available for bonding, rather the inner d-electrons (in case of 3d transition metal elements) are available for making coordinate bonds with the ligands. Electrons are distributed in the five d-orbitals according to Hund’s rule which results in a maximum number of unpaired electrons. The abbreviated electronic configuration of an element depicts the electronic configuration of the elements by making use of noble gas configuration as they have fully-filled electron shells.
(b)
Interpretation:
The abbreviated electronic configuration for metal ion
Concept introduction:
A transition metal cation has no outer s-electrons available for bonding, rather the inner d-electrons (in case of 3d transition metal elements) are available for making coordinate bonds with the ligands. Electrons are distributed in the five d-orbitals according to Hund’s rule which results in a maximum number of unpaired electrons. The abbreviated electronic configuration of an element depicts the electronic configuration of the elements by making use of noble gas configuration as they have fully-filled electron shells.
(c)
Interpretation:
The abbreviated electronic configuration for metal ion
Concept introduction:
A transition metal cation has no outer s-electrons available for bonding, rather the inner d-electrons (in case of 3d transition metal elements) are available for making coordinate bonds with the ligands. Electrons are distributed in the five d-orbitals according to Hund’s rule which results in a maximum number of unpaired electrons. The abbreviated electronic configuration of an element depicts the electronic configuration of the elements by making use of noble gas configuration as they have fully-filled electron shells.
(d)
Interpretation:
The abbreviated electronic configuration for metal ion
Concept introduction:
A transition metal cation has no outer s-electrons available for bonding, rather the inner d-electrons (in case of 3d transition metal elements) are available for making coordinate bonds with the ligands. Electrons are distributed in the five d-orbitals according to Hund’s rule which results in a maximum number of unpaired electrons. The abbreviated electronic configuration of an element depicts the electronic configuration of the elements by making use of noble gas configuration as they have fully-filled electron shells.
(e)
Interpretation:
The abbreviated electronic configuration for metal ion
Concept introduction:
A transition metal cation has no outer s-electrons available for bonding, rather the inner d-electrons (in case of 3d transition metal elements) are available for making coordinate bonds with the ligands. Electrons are distributed in the five d-orbitals according to Hund’s rule which results in a maximum number of unpaired electrons. The abbreviated electronic configuration of an element depicts the electronic configuration of the elements by making use of noble gas configuration as they have fully-filled electron shells.

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Chapter 19 Solutions
OWLv2 with Student Solutions Manual eBook for Masterton/Hurley's Chemistry: Principles and Reactions, 8th Edition, [Instant Access], 4 terms (24 months)
- Pls help.arrow_forwardPls help.arrow_forward16) A 2.0 L flask containing 2.0 x 10-3 mol H2(g), 3.0 x 10-3 mol Cl2(g), and 4.0 x 10-3 mol HCl(g) at equilibrium. This system is represented by the following chemical equation: H2 (g) + Cl2 (g) → 2HCl(g) Calculate the equilibrium constant for this reaction.arrow_forward
- 7) The pH of a 0.05M solution of HCl(aq) at 25°C is a. 1.3 b. 2.3 c. 3.3 d. 12.7arrow_forward11) The Ksp expression for copper (II) sulfate is: a. [Cu2+][SO4²¯] b. [Cu²+]² [SO4²]² c. [Cu²+]²[SO4²] d. [CuSO4] 12) Which of the following is true about a chemical system in equilibrium? a. All chemical reactions have stopped b. The concentration of reactants is equal to the concertation of products c. The forward and reverse reaction rates become equal d. The system will remain at equilibrium regardless of any external factorsarrow_forward21) Explain the difference between the rate of a reaction and the extent of a reaction. Why are both of these concepts important, if you are a chemical engineer that is trying to develop a process to produce a large volume of a specific type of chemical compound?arrow_forward
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