![OWLv2 with Student Solutions Manual eBook for Masterton/Hurley's Chemistry: Principles and Reactions, 8th Edition, [Instant Access], 4 terms (24 months)](https://www.bartleby.com/isbn_cover_images/9781305863170/9781305863170_largeCoverImage.jpg)
(a)
Interpretation:
The name of the complex
Concept introduction:
Coordination compounds are those in which a transition metal atom is bonded to a ligand which can be neutral cation or anion. The

Answer to Problem 22QAP
The name of this complex cation will be hexaaquairon(III).
Explanation of Solution
A ligand is an atom or a group of atoms or an anion that has an unshared pair of electrons and thus it can act as a Lewis base. It can donate its pair of electrons to the metal atom to form a coordinate bond with the transition metal atom. The formula of the given compound is
The total charge on complex cation is +3. Let ‘x’ be the oxidation state of ‘Fe’ in the complex cation.
This complex cation consists of only water molecules as ligands. Water molecules are written as ‘aqua’ while naming in coordination compounds. Since it consists of six water ligands, therefore the number of ligands in a given coordination compound is given by Greek prefix −‘hexa’.The naming of the cation is done as such, therefore the name of the compound will be hexaaquairon(III).
(b)
Interpretation:
The name of the complex
Concept introduction:
Coordination compounds are those in which a transition metal atom is bonded to a ligand which can be neutral cation or anion. The transition metal element is enclosed within a bracket and a charge is present on the ion to balance the charge present on the ligands. The total charge present on any complex ion is equal to the sum of the oxidation number of the central metal atom and the total charge on the ligand present in it.

Answer to Problem 22QAP
The name of this complex anion is amminetribromoplatinate(II).
Explanation of Solution
A ligand is an atom or a group of atoms or an anion that has an unshared pair of electrons and thus it can act as a Lewis base. It can donate its pair of electrons to the metal atom to form a coordinate bond with the transition metal atom. The formula of the given compound is
‘
For naming this compound, we can see that it consists of threebromine ligands. It is an anionic ligand as it carries a charge of -1 and the number of such anionic ligands is denoted by adding prefix such as -di, -tri depending upon the number of the ligands. It also consists of one ammonia molecule which is a neutral ligand and is denoted by ‘ammine’. Naming of the ligands in a given coordination compound takes place in an alphabetical order. For naming complex ions, the oxidation state of the central metal atom is written at the end of the name in roman numerals in round brackets. Since the given compound is a complex anion, therefore while naming the central metal atom, a suffix -ate is added to the name of the central metal atom. The total charge on the complex cation is -1. Let ‘x’ be the oxidation state of ‘Pt’.
The name of the coordination compound will be amminetribromoplatinate(II).
(c)
Interpretation:
The name of the complex
Concept introduction:
Coordination compounds are those in which a transition metal atom is bonded to a ligand which can be neutral cation or anion. The transition metal element is enclosed within a bracket and a charge is present on the ion to balance the charge present on the ligands. The total charge present on any complex ion is equal to the sum of the oxidation number of the central metal atom and the total charge on the ligand present in it.

Answer to Problem 22QAP
The name of this complex anion is tetrachloro(ethylenediamine)vanadate(II).
Explanation of Solution
A ligand is an atom or a group of atoms or an anion that has an unshared pair of electrons and thus it can act as a Lewis base. It can donate its pair of electrons to the metal atom to form a coordinate bond with the transition metal atom. The formula of the given compound is
For naming this compound, we can see that it consists of one ethylenediamine ligand. It is a neutral ligand and is denoted by ‘en’. Chloride ion is also an anionic ligand and is written as ‘chloro’ while naming coordination compounds and the oxidation state of the central metal atom is written at the end of the name in roman numerals in round brackets. Since the given compound is a complex anion therefore while naming the central metal atom, a suffix -ate is added to the name of the central metal atom. The total charge on the complex anion is -2. Let ‘x’ be the oxidation state of ‘V’.
The name of the coordination compound will be tetrachloro(ethylenediamine)vanadate(II).
(d)
Interpretation:
The name of the complex
Concept introduction:
Coordination compounds are those in which a transition metal atom is bonded to a ligand which can be neutral cation or anion. The transition metal element is enclosed within a bracket and a charge is present on the ion to balance the charge present on the ligands. The total charge present on any complex ion is equal to the sum of the oxidation number of the central metal atom and the total charge on the ligand present in it.

Answer to Problem 22QAP
The name of this complex cation will be dicyanogold(III).
Explanation of Solution
A ligand is an atom or a group of atoms or an anion that has an unshared pair of electrons and thus it can act as a Lewis base. It can donate its pair of electrons to the metal atom to form a coordinate bond with the transition metal atom. The formula of the given compound is
For naming this compound, we can see that it consists of two cyanide ligands. It is an anionic ligand as it carries a charge of -1 and the number of such anionic ligands is denoted by adding prefix such as -di, -tri depending upon the number of the ligands. For naming complex ions, the oxidation state of the central metal atom is written at the end of the name in roman numerals in round brackets. Since the given compound is a complex cation therefore it will be named as such. The total charge on the complex cation is +1. Let ‘x’ be the oxidation state of ‘Au’.
The name of the coordination compound will be dicyanogold(III).
Want to see more full solutions like this?
Chapter 19 Solutions
OWLv2 with Student Solutions Manual eBook for Masterton/Hurley's Chemistry: Principles and Reactions, 8th Edition, [Instant Access], 4 terms (24 months)
- On the next page is an LC separation of the parabens found in baby wash. Parabens are suspected in a link to breast cancer therefore an accurate way to quantitate them is desired. a. In the chromatogram, estimate k' for ethyl paraben. Clearly indicate what values you used for all the terms in your calculation. b. Is this a "good" value for a capacity factor? Explain. c. What is the resolution between n-Propyl paraben and n-Butyl paraben? Again, indicate clearly what values you used in your calculation. MAU | Methyl paraben 40 20 0 -2 Ethyl paraben n-Propyl paraben n-Butyl paraben App ID 22925 6 8 minarrow_forwardd. In Figure 4, each stationary phase shows some negative correlation between plate count and retention factor. In other words, as k' increases, N decreases. Explain this relationship between k' and N. Plate Count (N) 4000 3500 2500 2000 1500 1000 Figure 4. Column efficiency (N) vs retention factor (k') for 22 nonionizable solutes on FMS (red), PGC (black), and COZ (green). 3000 Eluent compositions (acetonitrile/water, A/W) were adjusted to obtain k' less than 15, which was achieved for most solutes as follows: FMS (30/70 A/W), PGC (60/40), COZ (80/20). Slightly different compositions were used for the most highly retained solutes. All columns were 50 mm × 4.6 mm id and packed with 5 um particles, except for COZ, which was packed with 3 um particles. All other chromatographic conditions were constant: column length 5 cm, column j.§. 4.6 mm, flow rate 2 mL/min, column temperature 40 °C, and injection volume 0.5 μL Log(k'x/K'ethylbenzene) FMS 1.5 1.0 0.5 0.0 ཐྭ ཋ ཤྩ བྷྲ ; 500 0 5 10…arrow_forwardf. Predict how the van Deemter curve in Figure 7 would change if the temperature were raised from 40 °C to 55 °C. Figure 7. van Desmter curves in reduced coordinates for four nitroalkane homologues (nitropropane, black; nitrobutane, red; nitropentane, blue; and nitrohexane, green) separated on the FMS phase. Chromatographic conditions: column dimensions 50 mm × 4.6 mm id, eluent 30/70 ACN/water, flow rates 0.2-5.0 mL/min, injection volume 0.5 and column temperature 40 °C. No corrections to the plate heights have been made to account for extracolumn dispersion. Reduced Plate Height (h) ° 20 40 60 Reduced Velocity (v) 8. (2) A water sample is analyzed for traces of benzene using headspace analysis. The sample and standard are spiked with a fixed amount of toluene as an internal standard. The following data are obtained: Ppb benzene Peak area benzene Peak area toluene 10.0 252 376 Sample 533 368 What is the concentration of benzene in the sample?arrow_forward
- Liquid chromatography has been used to track the concentration of remdesivir (a broad-spectrum antiviral drug, structure shown at right) in COVID patients undergoing experimental treatments. Intensity The authors provide the following details regarding standard solutions preparation: HN CN HO OH NH2 Remdesivir (RDV) stock solution (5000 µg/mL) was prepared by dissolving RDV drug powder using the mixture of DMSO: MeOH (30:70 v/v). The RDV working standard solutions for calibration and quality controls were prepared using methanol in concentrations of 100, 10, 1, 0.1, 0.01 µg/mL. 1, 2.5, 5, 7.5, 10, 25, 50, 75, 100, 250, 500, 1000, and 5000 ng/mL sample solutions were prepared freshly by spiking calibration standard solutions into the blank human plasma samples for method calibration. a) What type of calibration method is being described? Why do you think the authors chose this method as opposed to another? b) Based on the details provided in part a, describe an appropriate method blank…arrow_forwardRecent advancements in liquid chromatography include the development of ultrahigh pressure liquid chromatography (UHPLC) and an increased use of capillary columns that had previously only been used with gas chromatography. Both of these advances have made the development of portable LC systems possible. For example, Axcend Corp. makes a portable system that uses a capillary column with an internal diameter of 150-μm-that is packed with 1.7-um stationary phase particles. In contrast, a traditional LC column has a 4.6 mm internal diameter and utilizes 5-um stationary phase particles. a) Explain one advantage that is afforded by the use of a capillary column in liquid chromatographic separation. Explain one disadvantage of capillary columns. b) Explain how the use of smaller stationary phase particles can improve the resolution of a separation. Include any relevant equations that support your explanation. c) A scientist at Rowan University is using the Axcend LC to conduct analyses of F…arrow_forwardThis paper describes the use of fullerene molecules, also known as buckyballs, as a stationary phase for liquid chromatography. The performance of the fullerene-modified stationary phase (FMS) is compared to that of a more common C18 stationary phase and to two other carbon-based stationary phases, PGC and COZ. A. 10A OM B. - Figure 1. Idealized drawing of the cross-section of a pore inside a silica particle, showing the relative densities of aminopropylsilyl (red/green) and fullerene (blue) groups: (A) full cross- section; (B) detailed view of covalent bonding of fullerene to the silica surface. Surface densities of silyl and fullerene groups were inferred from elemental composition results obtained at each stage of the synthesis (see Table 1). Absorbance (mAU, 220 nm) 700 600 500 400 300 200 100 a. Define selectivity, a, with words and an equation. b. Explain how the choice of stationary phase affects selectivity. c. Calculate the resolution of the nitrobenzene and toluene peaks in…arrow_forward
- Normalized Intensity (a. u.) 0.5 1.0 A 3D-printed GC column (shown below) was created for use with "micro" gas chromatography applications. To prove its utility, it was used to separate a mixture of alkanes (C9-C18, C22, C24). For the separation shown below, the column temperature was ramped from 40 °C to 250 °C at a rate of 30 °C per minute. (a) 9 10 = 1 mm 12 13 15 22 0.0 0 100 200 300 400 Time (sec) a) What detector would you use for this analysis? Justify your selection. b) Explain how the chromatogram would change if the separation was run isothermally. c) Explain how the chromatogram would change if the temperature ramp were increased to 50 °C per minute.arrow_forwardDevise a synthesis of each compound from the indicated starting material. You may also use any organic compounds with one or two carbons and any needed inorganic reagents. a. Brarrow_forwardPlease help me with #2b & #3 using the data.arrow_forward
- Heparin is used as an anti-coagulant. A risk of heparin use is thrombocytopenia, or low platelet count. This risk is minimized with the use of low molecular weight heparins (LMWH), therefore it is desirable to separate LMWH from higher molecular weight heparins. The method of choice to do this is molecular exclusion chromatography. Below is a chromatogram from a molecular exclusion chromatographic run. Peaks ranging from A to J are clearly distinguishable. The heparin mixture that was analyzed had anywhere from 6 to 30 repeat units of monomer (where the heparin with 30 repeat units would be roughly five times the size of the heparin with six repeat units). a. Which letter most likely represents the peak with 6 repeat units given these heparin polymers were separated with molecular exclusion chromatography? b. Explain your reasoning describing the mechanism of retention in molecular exclusion chromatography. 100 80 60 60 Relative Abundance 40 40 E GH 20 20 B A 36 38 40 42 44 46 48 50 50…arrow_forwardHELP NOW PLEASE ! URGENT!arrow_forwardHELP NOW PLEASE ! URGENT!arrow_forward
- General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
- Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning





