Foundations of College Chemistry, Binder Ready Version
Foundations of College Chemistry, Binder Ready Version
15th Edition
ISBN: 9781119083900
Author: Morris Hein, Susan Arena, Cary Willard
Publisher: WILEY
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 19, Problem 29PE

(a)

Interpretation Introduction

Interpretation:

IUPAC name of given below compound has to be given.

    Foundations of College Chemistry, Binder Ready Version, Chapter 19, Problem 29PE , additional homework tip  1

Concept introduction:

IUPAC Nomenclature:

IUAC gives rules for the naming of chemical compounds. These rules are,

For unsaturated hydrocarbons, longest chain is the parent chain of the compound and remaining groups and atoms are consider as substituent.

In the nomenclature, Find the parent chin first then number the carbon atoms in the parent chain by giving lest number to the unsaturated double/triple bonded carbon followed by designate the substituent in its position in parent chain.

If more than one same substituent were occurs, add a prefix (di-, tri-, tetra-, ect..) in front of parent chain name.

If compound contains double bond means, name end with suffix of ene or if compound contains triple bond means name end with suffix of yne.

Finally the systematic name was written as, the substituent position number with prefix (di-, tri-, tetra-, ect..) of number of substituents followed by name of the substituent then write the parent chain name (which contains large number of carbon atoms in the chain) with suffix of suffix ene/yne.

The parent chain names based on the carbon atoms are,

AlkenesCH2=CH2 EtheneCH2=CH-CH3PropeneCH2=CH-CH2-CH3ButeneCH2=CH-CH2-CH2-CH3Pentene, etc...          AlkyneCHCH EthyneCHC-CH3PropyneCHC-CH2-CH3ButyneCHC-CH2-CH2-CH3Pentyne, ect...

The substituent names based on the carbon atoms are,

CH3-methylCH3-CH2ethylCH3-CH2-CH2-propyl

(a)

Expert Solution
Check Mark

Explanation of Solution

IUPAC name of given compound is,

Parent chain name of given compound is 2-hexene,

Foundations of College Chemistry, Binder Ready Version, Chapter 19, Problem 29PE , additional homework tip  2

From the structure given structure, methyl group is present at third carbon so substitution name is 3-methyl.

Foundations of College Chemistry, Binder Ready Version, Chapter 19, Problem 29PE , additional homework tip  3

Combine the substituent name followed by parent name to get complete name of the compound.

Hence, the complete IUPAC name of the compound is,

Foundations of College Chemistry, Binder Ready Version, Chapter 19, Problem 29PE , additional homework tip  4

(b)

Interpretation Introduction

Interpretation:

IUPAC name of given below compound has to be given.

    Foundations of College Chemistry, Binder Ready Version, Chapter 19, Problem 29PE , additional homework tip  5

Concept introduction:

Refer part (a).

(b)

Expert Solution
Check Mark

Explanation of Solution

IUPAC name of given compound is,

Parent chain name of given compound is 2-butene,

Foundations of College Chemistry, Binder Ready Version, Chapter 19, Problem 29PE , additional homework tip  6

From the given structure, two methyl groups are present at 2 and 3 carbon atom of parent chain so substitution name is 2,3-dimethyl.

Foundations of College Chemistry, Binder Ready Version, Chapter 19, Problem 29PE , additional homework tip  7

Combine the substituent name followed by parent name to get complete name of the compound.

Hence, the complete IUPAC name of the compound is,

Foundations of College Chemistry, Binder Ready Version, Chapter 19, Problem 29PE , additional homework tip  8

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
יווי 10 20 30 40 50 60 70 3.5 3 2.5 2 1.5 1 [ppm] 3.5 3 2.5 2 1.5 1 6 [ppm] 1 1.5 -2.5 3.5
2H2S(g)+3O2(g)→2SO2(g)+2H2O(g) A 1.2mol sample of H2S(g) is combined with excess O2(g), and the reaction goes to completion. Question   Which of the following predicts the theoretical yield of SO2(g) from the reaction?     Responses 1.2 g Answer A: 1.2 grams A 41 g Answer B: 41 grams B 77 g Answer C: 77 grams C 154 g Answer D: 154 grams D
Part VII. Below are the 'HNMR, 13 C-NMR, COSY 2D- NMR, and HSQC 2D-NMR (similar with HETCOR but axes are reversed) spectra of an organic compound with molecular formula C6H1003 - Assign chemical shift values to the H and c atoms of the compound. Find the structure. Show complete solutions. Predicted 1H NMR Spectrum 4.7 4.6 4.5 4.4 4.3 4.2 4.1 4.0 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 f1 (ppm) Predicted 13C NMR Spectrum 100 f1 (ppm) 30 220 210 200 190 180 170 160 150 140 130 120 110 90 80 70 -26 60 50 40 46 30 20 115 10 1.0 0.9 0.8 0 -10

Chapter 19 Solutions

Foundations of College Chemistry, Binder Ready Version

Ch. 19.10 - Prob. 19.11PCh. 19.11 - Prob. 19.12PCh. 19.12 - Prob. 19.13PCh. 19 - Prob. 1RQCh. 19 - Prob. 2RQCh. 19 - Prob. 3RQCh. 19 - Prob. 4RQCh. 19 - Prob. 5RQCh. 19 - Prob. 6RQCh. 19 - Prob. 7RQCh. 19 - Prob. 8RQCh. 19 - Prob. 9RQCh. 19 - Prob. 10RQCh. 19 - Prob. 11RQCh. 19 - Prob. 12RQCh. 19 - Prob. 13RQCh. 19 - Prob. 14RQCh. 19 - Prob. 15RQCh. 19 - Prob. 16RQCh. 19 - Prob. 17RQCh. 19 - Prob. 18RQCh. 19 - Prob. 19RQCh. 19 - Prob. 20RQCh. 19 - Prob. 21RQCh. 19 - Prob. 23RQCh. 19 - Prob. 24RQCh. 19 - Prob. 25RQCh. 19 - Prob. 26RQCh. 19 - Prob. 27RQCh. 19 - Prob. 28RQCh. 19 - Prob. 29RQCh. 19 - Prob. 30RQCh. 19 - Prob. 31RQCh. 19 - Prob. 32RQCh. 19 - Prob. 33RQCh. 19 - Prob. 34RQCh. 19 - Prob. 35RQCh. 19 - Prob. 36RQCh. 19 - Prob. 37RQCh. 19 - Prob. 1PECh. 19 - Prob. 2PECh. 19 - Prob. 3PECh. 19 - Prob. 4PECh. 19 - Prob. 5PECh. 19 - Prob. 6PECh. 19 - Prob. 7PECh. 19 - Prob. 8PECh. 19 - Prob. 9PECh. 19 - Prob. 10PECh. 19 - Prob. 11PECh. 19 - Prob. 12PECh. 19 - Prob. 13PECh. 19 - Prob. 14PECh. 19 - Prob. 15PECh. 19 - Prob. 16PECh. 19 - Prob. 17PECh. 19 - Prob. 18PECh. 19 - Prob. 19PECh. 19 - Prob. 20PECh. 19 - Prob. 21PECh. 19 - Prob. 22PECh. 19 - Prob. 23PECh. 19 - Prob. 24PECh. 19 - Prob. 25PECh. 19 - Prob. 26PECh. 19 - Prob. 27PECh. 19 - Prob. 28PECh. 19 - Prob. 29PECh. 19 - Prob. 30PECh. 19 - Prob. 31PECh. 19 - Prob. 32PECh. 19 - Prob. 33PECh. 19 - Prob. 34PECh. 19 - Prob. 35PECh. 19 - Prob. 36PECh. 19 - Prob. 37PECh. 19 - Prob. 38PECh. 19 - Prob. 39PECh. 19 - Prob. 40PECh. 19 - Prob. 41PECh. 19 - Prob. 42PECh. 19 - Prob. 43PECh. 19 - Prob. 44PECh. 19 - Prob. 45PECh. 19 - Prob. 46PECh. 19 - Prob. 47PECh. 19 - Prob. 48PECh. 19 - Prob. 49PECh. 19 - Prob. 50PECh. 19 - Prob. 51PECh. 19 - Prob. 52PECh. 19 - Prob. 53PECh. 19 - Prob. 54PECh. 19 - Prob. 55PECh. 19 - Prob. 56PECh. 19 - Prob. 57PECh. 19 - Prob. 58PECh. 19 - Prob. 59PECh. 19 - Prob. 60PECh. 19 - Prob. 61PECh. 19 - Prob. 62PECh. 19 - Prob. 63PECh. 19 - Prob. 64PECh. 19 - Prob. 65AECh. 19 - Prob. 66AECh. 19 - Prob. 67AECh. 19 - Prob. 68AECh. 19 - Prob. 69AECh. 19 - Prob. 70AECh. 19 - Prob. 71AECh. 19 - Prob. 72AECh. 19 - Prob. 73AECh. 19 - Prob. 74AECh. 19 - Prob. 75AECh. 19 - Prob. 76AECh. 19 - Prob. 77AECh. 19 - Prob. 78AECh. 19 - Prob. 79AECh. 19 - Prob. 80AECh. 19 - Prob. 81AECh. 19 - Prob. 82AECh. 19 - Prob. 83AECh. 19 - Prob. 84AECh. 19 - Prob. 85AECh. 19 - Prob. 86AECh. 19 - Prob. 87AECh. 19 - Prob. 89AECh. 19 - Prob. 90AE
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Living By Chemistry: First Edition Textbook
Chemistry
ISBN:9781559539418
Author:Angelica Stacy
Publisher:MAC HIGHER
Text book image
Introductory Chemistry: An Active Learning Approa...
Chemistry
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Cengage Learning
Text book image
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Nomenclature: Crash Course Chemistry #44; Author: CrashCourse;https://www.youtube.com/watch?v=U7wavimfNFE;License: Standard YouTube License, CC-BY