The balanced cell reaction, E° and Δ G° for the cell needs to be determined that is composed of by combining two of the given cell reactions with the smallest E° . Co 2+ ( a q ) + 2 e - → Co ( s ) E° = -0 .28 V I 2 ( s ) + 2 e - → 2 I − ( a q ) E° = 0 .54 V Cu 2+ ( a q ) + 2 e - → Cu ( s ) E° = 0 .34 V Concept introduction: In the electrochemical cell, the reactions at cathode and anode occur due to the difference in their reduction electrode potential value. The EMF of the cell can be calculated with the help of electrode reduction potential values. The reaction at each electrode is called half-reaction and the combination of both half-reactions gives the cell reaction of given electrochemical cell. The standard cell potential for an electrochemical cell can be calculated as: E cell ° = E cathode ° - E anode ° E cell ° = E reduction ° - E oxidation ° Cathode involves the reduction process whereas oxidation occurs at the anode. The spontaneity of the reaction can be determined with the help of Δ G r ° and E cell ° can be written as: ΔG r ° = -n × F × E cell ° Here n is the number of e- involve in half-reaction and F is 96458 C/mol e-. Hence the negative value of E cell ° indicates the non-spontaneity of reaction.
The balanced cell reaction, E° and Δ G° for the cell needs to be determined that is composed of by combining two of the given cell reactions with the smallest E° . Co 2+ ( a q ) + 2 e - → Co ( s ) E° = -0 .28 V I 2 ( s ) + 2 e - → 2 I − ( a q ) E° = 0 .54 V Cu 2+ ( a q ) + 2 e - → Cu ( s ) E° = 0 .34 V Concept introduction: In the electrochemical cell, the reactions at cathode and anode occur due to the difference in their reduction electrode potential value. The EMF of the cell can be calculated with the help of electrode reduction potential values. The reaction at each electrode is called half-reaction and the combination of both half-reactions gives the cell reaction of given electrochemical cell. The standard cell potential for an electrochemical cell can be calculated as: E cell ° = E cathode ° - E anode ° E cell ° = E reduction ° - E oxidation ° Cathode involves the reduction process whereas oxidation occurs at the anode. The spontaneity of the reaction can be determined with the help of Δ G r ° and E cell ° can be written as: ΔG r ° = -n × F × E cell ° Here n is the number of e- involve in half-reaction and F is 96458 C/mol e-. Hence the negative value of E cell ° indicates the non-spontaneity of reaction.
Solution Summary: The author explains that the balanced cell reaction, E°, and Delta
Definition Definition Study of chemical reactions that result in the production of electrical energy. Electrochemistry focuses particularly on how chemical energy is converted into electrical energy and vice-versa. This energy is used in various kinds of cells, batteries, and appliances. Most electrochemical reactions involve oxidation and reduction.
Chapter 19, Problem 19.87SP
Interpretation Introduction
Interpretation:
The balanced cell reaction, E° and ΔG° for the cell needs to be determined that is composed of by combining two of the given cell reactions with the smallest E°.
In the electrochemical cell, the reactions at cathode and anode occur due to the difference in their reduction electrode potential value. The EMF of the cell can be calculated with the help of electrode reduction potential values. The reaction at each electrode is called half-reaction and the combination of both half-reactions gives the cell reaction of given electrochemical cell. The standard cell potential for an electrochemical cell can be calculated as:
Cathode involves the reduction process whereas oxidation occurs at the anode. The spontaneity of the reaction can be determined with the help of ΔGr° and Ecell° can be written as:
ΔGr°= -n ×F × Ecell°
Here n is the number of e- involve in half-reaction and F is 96458 C/mol e-. Hence the negative value of Ecell° indicates the non-spontaneity of reaction.
Could you please turn this into a complete Lewis dot structure formula for me so I can visualize it more clearly? and then do the explaining for the resonance structures that were given please.
Could you please turn this into a complete Lewis dot structure formula for me so I can visualize it more clearly? and then do the explaining for the question.
please solve. If the answer is "no error" and it asks me to type something, and i typed a-helix, its always wrong.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell