From the relation between E ∘ , Δ G ∘ and K, this is to be shown that the value of Δ G ∘ is negative and K > 1 for the reaction with a positive E ∘ value. Concept introduction: The substances that have a higher reduction potential will undergo reduction at the cathode while the substances that have a lower reduction potential will undergo oxidation at the anode. The expression to calculate the equilibrium constant is shown below: Δ G cell o = − RT ln K Here, R is Universal gas constant, T is temperature and K is equilibrium constant. The expression to calculate the standard Gibbs free energy of the cell is shown below: Δ G cell o = − nFE cell o Here, n is the number of electrons transferred, F is Faraday’s constant and E cell o is standard electrode potential of the cell.
From the relation between E ∘ , Δ G ∘ and K, this is to be shown that the value of Δ G ∘ is negative and K > 1 for the reaction with a positive E ∘ value. Concept introduction: The substances that have a higher reduction potential will undergo reduction at the cathode while the substances that have a lower reduction potential will undergo oxidation at the anode. The expression to calculate the equilibrium constant is shown below: Δ G cell o = − RT ln K Here, R is Universal gas constant, T is temperature and K is equilibrium constant. The expression to calculate the standard Gibbs free energy of the cell is shown below: Δ G cell o = − nFE cell o Here, n is the number of electrons transferred, F is Faraday’s constant and E cell o is standard electrode potential of the cell.
Solution Summary: The author analyzes the relation between Ecirc & Delta. The expression to calculate the standard Gibbs free energy of the cell is shown below.
From the relation between E∘, ΔG∘ and K, this is to be shown that the value of ΔG∘ is negative and K>1 for the reaction with a positive E∘ value.
Concept introduction:
The substances that have a higher reduction potential will undergo reduction at the cathode while the substances that have a lower reduction potential will undergo oxidation at the anode.
The expression to calculate the equilibrium constant is shown below:
ΔGcello=−RTlnK
Here, R is Universal gas constant, T is temperature and K is equilibrium constant.
The expression to calculate the standard Gibbs free energy of the cell is shown below:
ΔGcello=−nFEcello
Here, n is the number of electrons transferred, F is Faraday’s constant and Ecello is standard electrode potential of the cell.
1. Calculate the accurate monoisotopic mass (using all 1H, 12C, 14N, 160 and 35CI) for your product using the table in
your lab manual. Don't include the Cl, since you should only have [M+H]*. Compare this to the value you see on
the LC-MS printout. How much different are they?
2. There are four isotopic peaks for the [M+H]* ion at m/z 240, 241, 242 and 243. For one point of extra credit,
explain what each of these is and why they are present.
3. There is a fragment ion at m/z 184. For one point of extra credit, identify this fragment and confirm by
calculating the accurate monoisotopic mass.
4. The UV spectrum is also at the bottom of your printout. For one point of extra credit, look up the UV spectrum
of bupropion on Google Images and compare to your spectrum. Do they match? Cite your source.
5. For most of you, there will be a second chromatographic peak whose m/z is 74 (to a round number). For one
point of extra credit, see if you can identify this molecule as well and confirm by…
Please draw, not just describe!
can you draw each step on a piece of a paper please this is very confusing to me
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell