Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 19, Problem 19.6P
To determine
Find the maximum load that can be allowed on the drilled shaft.
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no chatgpt, show solution. thx^^
P
20 mm
15 mm
100 mm
200 mm
100 mm
15 mm
-450.0 mm-
-300.0 mm
300.0 mm
-300.0 mm
-450.0 mm-
300.0 mm
The butt connection shows 8-24mm bolts. Spacing and dimensions are shown in figure
PSAD-020. The plate is made of A36 steel.
Allowable tensile stress on gross area = 0.6Fy
Allowable tensile stress on net area = 0.5Fu
Allowable shear stress on net area = 0.3Fu
Bolt hole diameter = 26mm
Determine the allowable tensile load P based on net area rupture.
Determine the allowable tensile load P based on gross area yielding.
Determine the allowable tensile load P based on block shear strength.
P
300 mm
P
75 mm
-75 mm
P
I
75 mm
100 mm
-125 mm
Shown in figure PSAD-022 is a splice connection made of 8-22mm A325 bolts and a PL
300 x 12 mm made of A36 steel, connected back-to-back. The connection joins together
two A992 W410X67 (Fy = 50 ksi, Fu = 65 ksi) carrying a tension load P. Assume U =
0.70. Ignore bolt shear failure.
Determine the design capacity of the connection based on yielding of the plate.
Determine the design capacity of the section based on yielding of the wide flange section.
Determine the design capacity of the section based on rupture of the plate.
Determine the design capacity of the section based on block shear of the plate.
Chapter 19 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 19 - Prob. 19.1PCh. 19 - Prob. 19.2PCh. 19 - Redo Problem 19.2. Use Eq. (19.4) and Es = 600 pa....Ch. 19 - For the drilled shaft described in Problem 19.2,...Ch. 19 - Prob. 19.5PCh. 19 - Prob. 19.6PCh. 19 - Prob. 19.7PCh. 19 - For the drilled shaft described in Problem 19.7,...Ch. 19 - For the drilled shaft described in Problem 19.7,...Ch. 19 - Prob. 19.10P
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