Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 19, Problem 19.5P
To determine
Find the net allowable point bearing capacity of the drilled shaft and the percentage of load carried by the shaft.
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A free-headed drilled shaft, shown in Figure 4, has an elastic modulus, Ep = 20,000 MPa.
M, = 880 kN m
Q = 245 kN,
Sand
at = 19 kN/m3
O' = 34°
1.2 m
Figure 4
(a) Determine the ground line deflection, x.
Figure P10.7 shows a drilled shaft without a bell. Assume the following values:L1 = 6 m cu(1) = 50 kN/m2L2 = 7 m cu(2) = 75 kN/m2Ds = 1.5 mDetermine:a. The net ultimate point bearing capacity [use Eqs. (10.33) and (10.34)]b. The ultimate skin friction [use Eqs. (10.37) and (10.39)]c. The working load Qw (factor of safety = 3)
Refer to Figure 11.26b. For the drilled shaft with bell, given:Thickness of active zone, Z = 9 mDead load = 1500 kN Live load = 300 kNDiameter of the shaft, Ds = 1 mZero swell pressure for the clay in the active zone = 600 kN/m2Average angle of plinth-soil friction, Φ'ps = 20°Average undrained cohesion of the clay around the bell = 150 kN/m2. Determine the diameter of the bell, Db. A factor of safety of 3 against uplift is required with the assumption that dead load plus live load is equal to zero.
Chapter 19 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 19 - Prob. 19.1PCh. 19 - Prob. 19.2PCh. 19 - Redo Problem 19.2. Use Eq. (19.4) and Es = 600 pa....Ch. 19 - For the drilled shaft described in Problem 19.2,...Ch. 19 - Prob. 19.5PCh. 19 - Prob. 19.6PCh. 19 - Prob. 19.7PCh. 19 - For the drilled shaft described in Problem 19.7,...Ch. 19 - For the drilled shaft described in Problem 19.7,...Ch. 19 - Prob. 19.10P
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- A free-headed drilled shaft is shown in Figure P13.10. Let Qg = 260 kN, Mg = 0, = 17.5 kN/m3, = 35, c' = 0, and Ep = 22 106 kN/m2. Determine a. The ground line deflection, xo b. The maximum bending moment in the drilled shaft c. The maximum tensile stress in the shaft d. The minimum penetration of the shaft needed for this analysisarrow_forwardFigure P13.9 shows a drilled shaft extending into clay shale. Given: qu (clay shale) = 1.81 MN/m2. Considering the socket to be rough, estimate the allowable load-carrying capacity of the drilled shaft. Use FS = 4. Use the Zhang and Einstein procedure.arrow_forwardFor the drilled shaft described in Problem 19.7, estimate the total elastic settlement at working load. Use Eqs. (18.45), (18.47), and (18.48). Assume that Ep = 20 106 kN/m2, s = 0.3, Es = 12 103 kN/m2, = 0.65 and Cp = 0.03. Assume 80% mobilization of skin resistance at working load. (See Part c of Problem 19.7) 19.7 Figure 19.16 shows a drilled shaft without a bell. Here, L1 = 6 m, L2 = 7 m, Ds = 1.5 m, cu(1) = 50 kN/m2, and cu(2) = 75 kN/m2. Find these values: a. The net ultimate point bearing capacity. Use Eqs. (19.23) and (19.24) b. The ultimate skin resistance. Use Eqs. (19.26) and (19.28) c. The working load, Qw (FS = 3) FIG. 19.16arrow_forward
- A 3 ft diameter straight drilled shaft is shown in Figure P13.7. Determine the load-carrying capacity of the drilled shaft with FS = 3. Take / as 0.8 for the sand.arrow_forwardTake o, = 580 kPa (Figure 1) Express your answer to three significant figures and include the appropriate units. HÀ ? o, = Value Units Submit Request Answer Figure Part B Determine the shear stress acting on the inclined plane AB. Express your answer to three significant figures and include the appropriate units. В HA ? 30° Value Units Aarrow_forward1. Triaxial compression tests are done on quartzite rocks, the results are shown below. (0₁+03)/2 -964.25 14500 19575 23200 29000 43210 63075 psi (01-03)/2 964.25 14500 18850 21750 26100 35960 48575 psi Comment on the applicability of each of the Mohr-Coulomb, Griffith, and Hoek-Brown criteria for the testing results.arrow_forward
- For the drilled shaft described in Problem 10.1, what skin resistance would develop in the top 6 m, which are in clay ?arrow_forwardFor the drilled shaft described in Problem 19.7, determine these values: a. The ultimate load-carrying capacity b. The load-carrying capacity for a settlement of 25 mm Use the procedure outlined in Section 19.8. 19.7 Figure 19.16 shows a drilled shaft without a bell. Here, L1 = 6 m, L2 = 7 m, Ds = 1.5 m, cu(1) = 50 kN/m2, and cu(2) = 75 kN/m2. Find these values: a. The net ultimate point bearing capacity. Use Eqs. (19.23) and (19.24) b. The ultimate skin resistance. Use Eqs. (19.26) and (19.28) c. The working load, Qw (FS = 3) FIG. 19.16arrow_forwardEarth Sciences Downward force is 4000 kg and rotational force is 3000 kg. Contact surface area (cross sectional area) is 100 cm2. Also, the rock sample (diameter: 20 cm) is tested by a uniaxial compressive strength machine and the sample was cracked at 30000 kg. Answer the following questions:a. Find the resultant force acting on the rock formation.b. Find the bearing strength of the rock drilled.c. Can we drill under these circumstances?arrow_forward
- (1) A well is drilling to the depth of 6000 m. Formation pore pressure can be expressed in equivalent mud weight is 1.50 g/cm' at the depth and changes in proportion to well depth. Also, overburden pressure gradient is 0.0245 MPa/m. Calculate: a. Pore pressure gradient at 6000 m, MPa/m. b.Pore pressure, psi, at 6000 m. c. Matrix stress gradient, MPa/m d.Matrix stress at 6000 m, MPaarrow_forwardPlease help me solve. This is not a graded question.arrow_forwardShow me all clear calculationsarrow_forward
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