(a) Interpretation: The explanation for the fact that the m / z = 57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in the spectrum of 2-hexanone is to be stated. Concept introduction: Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m / z of the molecular ion occurs at the molecular mass.

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Answer 1

Question

Chapter 19, Problem 19.10P

Interpretation Introduction

(a)

Interpretation:

The explanation for the fact that the m/z=57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in the spectrum of 2-hexanone is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Interpretation Introduction

(b)

Interpretation:

The explanation for the fact that the spectrum of 3, 3-dimethyl-2-butanone (B) does not shows a fragment at m/z=58, but that of 2-hexanone shows is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

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Transmitance 3. Which one of the following compounds corresponds to this IR spectrum? Point out the absorption band(s) that helped you decide. OH H3C OH H₂C CH3 H3C CH3 H3C INFRARED SPECTRUM 0.8- 0.6 0.4- 0.2 3000 2000 1000 Wavenumber (cm-1) 4. Consider this compound: H3C On the structure above, label the different types of H's as A, B, C, etc. In table form, list the labeled signals, and for each one state the number of hydrogens, their shifts, and the splitting you would observe for these hydrogens in the ¹H NMR spectrum. Label # of hydrogens splitting Shift (2)

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Answer 2

Question

Chapter 19, Problem 19.10P

Interpretation Introduction

(a)

Interpretation:

The explanation for the fact that the m/z=57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in the spectrum of 2-hexanone is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Interpretation Introduction

(b)

Interpretation:

The explanation for the fact that the spectrum of 3, 3-dimethyl-2-butanone (B) does not shows a fragment at m/z=58, but that of 2-hexanone shows is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

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Answer 3

Question

Chapter 19, Problem 19.10P

Interpretation Introduction

(a)

Interpretation:

The explanation for the fact that the m/z=57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in the spectrum of 2-hexanone is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Interpretation Introduction

(b)

Interpretation:

The explanation for the fact that the spectrum of 3, 3-dimethyl-2-butanone (B) does not shows a fragment at m/z=58, but that of 2-hexanone shows is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

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Answer 4

Question

Chapter 19, Problem 19.10P

Interpretation Introduction

(a)

Interpretation:

The explanation for the fact that the m/z=57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in the spectrum of 2-hexanone is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Interpretation Introduction

(b)

Interpretation:

The explanation for the fact that the spectrum of 3, 3-dimethyl-2-butanone (B) does not shows a fragment at m/z=58, but that of 2-hexanone shows is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

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Answer 5

Chapter 19, Problem 19.10P

Interpretation Introduction

(a)

Interpretation:

The explanation for the fact that the m/z=57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in the spectrum of 2-hexanone is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Interpretation Introduction

(b)

Interpretation:

The explanation for the fact that the spectrum of 3, 3-dimethyl-2-butanone (B) does not shows a fragment at m/z=58, but that of 2-hexanone shows is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Answer 6

Chapter 19, Problem 19.10P

Interpretation Introduction

(a)

Interpretation:

The explanation for the fact that the m/z=57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in the spectrum of 2-hexanone is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Answer 7

Chapter 19, Problem 19.10P

Interpretation Introduction

(a)

Interpretation:

The explanation for the fact that the m/z=57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in the spectrum of 2-hexanone is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The explanation for the fact that the spectrum of 3, 3-dimethyl-2-butanone (B) does not shows a fragment at m/z=58, but that of 2-hexanone shows is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The explanation for the fact that the spectrum of 3, 3-dimethyl-2-butanone (B) does not shows a fragment at m/z=58, but that of 2-hexanone shows is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 19 - Prob. 19.1P Ch. 19 - Prob. 19.2P Ch. 19 - Prob. 19.3P Ch. 19 - Prob. 19.4P Ch. 19 - Prob. 19.5P Ch. 19 - Prob. 19.6P Ch. 19 - Prob. 19.7P Ch. 19 - Prob. 19.8P Ch. 19 - Prob. 19.9P Ch. 19 - Prob. 19.10P

Solution Summary: The author explains that the m/z=57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in

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