ORGANIC CHEM +SG +SAPLING >IP<
ORGANIC CHEM +SG +SAPLING >IP<
6th Edition
ISBN: 9781319171179
Author: LOUDON
Publisher: MAC HIGHER
Question
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Chapter 19, Problem 19.14P
Interpretation Introduction

(a)

Interpretation:

The reason as to why pmethoxybezaldehyde is more basic as compared to pnitrobenzaldehyde by using resonance arguments is to be stated.

Concept introduction:

The delocalization of electrons results in the formation of resonance structure. The curved-arrow notation traces the flow of the electrons in a compound. This notation is used to derive the resonance structure.

Interpretation Introduction

(b)

Interpretation:

The reason as to why 3buten2one is more basic as compared to 2butanone by using resonance arguments is to be stated.

Concept introduction:

The delocalization of electrons results in the formation of resonance structure. The curved-arrow notation traces the flow of the electrons in a compound. This notation is used to derive the resonance structure.

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Transmitance 3. Which one of the following compounds corresponds to this IR spectrum? Point out the absorption band(s) that helped you decide. OH H3C OH H₂C CH3 H3C CH3 H3C INFRARED SPECTRUM 0.8- 0.6 0.4- 0.2 3000 2000 1000 Wavenumber (cm-1) 4. Consider this compound: H3C On the structure above, label the different types of H's as A, B, C, etc. In table form, list the labeled signals, and for each one state the number of hydrogens, their shifts, and the splitting you would observe for these hydrogens in the ¹H NMR spectrum. Label # of hydrogens splitting Shift (2)
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Chapter 19 Solutions

ORGANIC CHEM +SG +SAPLING >IP<

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