Concept explainers
Interpretation:
Imagining that the
Concept introduction:
The acid protonates the epoxide and then water attacks the protonated epoxide to yield the
To draw:
The structure of the epoxide with stereochemistry.
To give:
The name and structure of the product with stereochemistry.
To explain:
Whether the product is chiral or not and whether the product is optically active or not.
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Chapter 18 Solutions
Organic Chemistry
- (a) Draw two different enol tautomers of 2-methylcyclohexanone. (b) Draw two constitutional isomers that are not tautomers, but contain a C=C and an OH group. 2-methylcyclohexanonearrow_forwardThe alkyl halide cis-1-bromo-4-methycyclohexane (A) undergoes a (c) substitution reaction when treated with H,0 to give a racemic mixture which is made up of product B and C. (i) What is a racemic mixture? (ii) Draw all the possible diastereoisomers of the compound below. Br Brarrow_forwardThe alkene shown undergoes bromination. H (a) Draw the product(s) of bromination of this compound, including all expected stereoisomers (if any). Use wedge-and-dash bonds to designate the stereochemistry at any chirality centers, and make sure to draw an explicit hydrogen if a chirality center has one. (b) Characterize the starting alkene as having the E or Z configuration. (c) characterize the product(s). (a) H Br₂ Draw the product(s) of bromination. Br H Brarrow_forward
- The alkene shown undergoes bromination. (a) Draw the product(s) of bromination of this compound, including all expected stereoisomers (if any). Use wedge‑and‑dash bonds to designate the stereochemistry at any chirality centers, and make sure to draw an explicit hydrogen if a chirality center has one. (b) Characterize the starting alkene as having the E or Z configuration. (c) characterize the product(s).arrow_forward(a) Show how you would synthesize the pure (R) enantiomer of 2-butyl methyl sulfide, starting with pure (R)-butan-2-oland any reagents you need.(b) Show how you would synthesize the pure (S) enantiomer of the product, still starting with (R)-butan-2-ol and anyreagents you need.arrow_forwardPredict the favored product of each of the following reduction reactions. If the product is chiral, draw both stereoisomers expected. (b) NaBD4 CH3CH₂OH NaBH4 CH3CH₂OHarrow_forward
- H 9. (a) Optically active 2-bromobutane undergoes racemization on treatment with a solution of KBr. Give a mechanism for this racemization. (b) In contrast, optically active butan-2-ol does not racemize on treatment with a solution of KOH. Explain why a reaction like that in part (a) does not occur. (c) Optically active butan-2-ol racemizes in dilute acid. Propose a mechanism for this racemization.arrow_forwardDraww all possible organic products and kinds of reactions (SN1, SN2, E1, E2)arrow_forwardThe bicyclic heterocycles quinoline and indole undergo electrophilic aromatic substitution to give the products shown. (a) Explain why electrophilic substitution occurs on the ring without the N atom for quinoline, but occurs on the ring with the N atom in indole. (b) Explain why electrophilic substitution occurs more readily at C8 than C7 in quinoline. (c) Explain whyelectrophilic substitution occurs more readily at C3 rather than C2 of indole.arrow_forward
- In some nucleophilic substitutions under SN1 conditions, complete racemization does not occur and a small excess of one enantiomer is present. For example, treatment of optically pure 1-bromo-1-phenylpropane with water forms 1-phenyl-1-propanol. (a) Calculate how much of each enantiomer is present using the given optical rotation data. (b) Which product predominates-the product of inversion or the product of retention of configuration? (c) Suggest an explanation for this phenomenon. H Br он H20 1-bromo-1-phenylpropane 1-phenyl-1-propanol observed [a) = +5.0 optically pure S isomer, [a] =-48 %3Darrow_forwardIn some nucleophilic substitutions under SN1 conditions, complete racemization does not occur and a small excess of one enantiomer is present. For example, treatment of optically pure 1-bromo-1-phenylpropane with water forms 1-phenylpropan-1-ol. (a) Calculate how much of each enantiomer is present using the given optical rotation data. (b) Which product predominates—the product of inversion or the product of retention of configuration? (c) Suggest an explanation for this phenomenon.arrow_forwardQ4 Which statement below about Snl reactions is incorrect? (A) SNl reactions are stepwise and have intermediates. (B) The slow step in a Snl reaction is formation of the carbocation intermediate. (C) SNl reactions have first order kinetics which means only the alkyl halide is involved in the rate limiting step. (D) The products of a Syl reaction will be a pair of enantiomers. (E) An aprotic solvent is best for Snl reactions as they tend to help stabilize carbocation intermediates.arrow_forward
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