To classify the given monosaccharide as aldohexose, aldopentose, ketopentose or ketohexose. Concept Introduction : Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components. They contain about three to seven carbon atoms in total and one of them is a carbonyl group and rest of the carbon atoms are attached to the hydroxyl groups. If a given monosaccharide will contain five carbon atoms in total, then it is called as a pentose, if the number of carbon atoms is six, then it will be known as a hexose. An aldohexose refers to a monosaccharide which contains six carbon atoms and the carbonyl group is an aldehydic group (CH=O). On the other hand a ketohexose refers to the monosaccharide which contains a ketonic group (C=O), and six carbon atoms in its carbon skeleton.

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Answer 1

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 18.1, Problem 9PP

(a)

Interpretation Introduction

Interpretation:

To classify the given monosaccharide as aldohexose, aldopentose, ketopentose or ketohexose.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components. They contain about three to seven carbon atoms in total and one of them is a carbonyl group and rest of the carbon atoms are attached to the hydroxyl groups. If a given monosaccharide will contain five carbon atoms in total, then it is called as a pentose, if the number of carbon atoms is six, then it will be known as a hexose. An aldohexose refers to a monosaccharide which contains six carbon atoms and the carbonyl group is an aldehydic group (CH=O). On the other hand a ketohexose refers to the monosaccharide which contains a ketonic group (C=O), and six carbon atoms in its carbon skeleton.

(b)

Interpretation Introduction

Interpretation:

To classify the given monosaccharide as aldohexose, aldopentose, ketopentose or ketohexose.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components. They contain about three to seven carbon atoms in total and one of them is a carbonyl group and rest of the carbon atoms are attached to the hydroxyl groups. If a given monosaccharide will contain five carbon atoms in total, then it is called as a pentose, if the number of carbon atoms is six, then it will be known as a hexose. An aldohexose refers to a monosaccharide which contains six carbon atoms and the carbonyl group is an aldehydic group (CH=O). On the other hand a ketohexose refers to the monosaccharide which contains a ketonic group (C=O), and six carbon atoms in its carbon skeleton.

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Answer 2

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 18.1, Problem 9PP

(a)

Interpretation Introduction

Interpretation:

To classify the given monosaccharide as aldohexose, aldopentose, ketopentose or ketohexose.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components. They contain about three to seven carbon atoms in total and one of them is a carbonyl group and rest of the carbon atoms are attached to the hydroxyl groups. If a given monosaccharide will contain five carbon atoms in total, then it is called as a pentose, if the number of carbon atoms is six, then it will be known as a hexose. An aldohexose refers to a monosaccharide which contains six carbon atoms and the carbonyl group is an aldehydic group (CH=O). On the other hand a ketohexose refers to the monosaccharide which contains a ketonic group (C=O), and six carbon atoms in its carbon skeleton.

(b)

Interpretation Introduction

Interpretation:

To classify the given monosaccharide as aldohexose, aldopentose, ketopentose or ketohexose.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components. They contain about three to seven carbon atoms in total and one of them is a carbonyl group and rest of the carbon atoms are attached to the hydroxyl groups. If a given monosaccharide will contain five carbon atoms in total, then it is called as a pentose, if the number of carbon atoms is six, then it will be known as a hexose. An aldohexose refers to a monosaccharide which contains six carbon atoms and the carbonyl group is an aldehydic group (CH=O). On the other hand a ketohexose refers to the monosaccharide which contains a ketonic group (C=O), and six carbon atoms in its carbon skeleton.

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Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 18.1, Problem 9PP

(a)

Interpretation Introduction

Interpretation:

To classify the given monosaccharide as aldohexose, aldopentose, ketopentose or ketohexose.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components. They contain about three to seven carbon atoms in total and one of them is a carbonyl group and rest of the carbon atoms are attached to the hydroxyl groups. If a given monosaccharide will contain five carbon atoms in total, then it is called as a pentose, if the number of carbon atoms is six, then it will be known as a hexose. An aldohexose refers to a monosaccharide which contains six carbon atoms and the carbonyl group is an aldehydic group (CH=O). On the other hand a ketohexose refers to the monosaccharide which contains a ketonic group (C=O), and six carbon atoms in its carbon skeleton.

(b)

Interpretation Introduction

Interpretation:

To classify the given monosaccharide as aldohexose, aldopentose, ketopentose or ketohexose.

Concept Introduction :

Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components. They contain about three to seven carbon atoms in total and one of them is a carbonyl group and rest of the carbon atoms are attached to the hydroxyl groups. If a given monosaccharide will contain five carbon atoms in total, then it is called as a pentose, if the number of carbon atoms is six, then it will be known as a hexose. An aldohexose refers to a monosaccharide which contains six carbon atoms and the carbonyl group is an aldehydic group (CH=O). On the other hand a ketohexose refers to the monosaccharide which contains a ketonic group (C=O), and six carbon atoms in its carbon skeleton.

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 18.1, Problem 9PP

(a)

Interpretation Introduction