Starting Out With C++: Early Objects (10th Edition)
10th Edition
ISBN: 9780135235003
Author: Tony Gaddis, Judy Walters, Godfrey Muganda
Publisher: PEARSON
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Chapter 18, Problem 9RQE
Program Plan Intro
Queue:
- A queue contains sequence of items.
- The item which is inserted first, will be retrieved first.
- Queue performs “First In First Out”.
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Chapter 18 Solutions
Starting Out With C++: Early Objects (10th Edition)
Ch. 18.3 - Describe what LIFO means.Ch. 18.3 - What is the difference between static and dynamic...Ch. 18.3 - What are the two primary stack operations?...Ch. 18.3 - What STL types does the STL stack container adapt?Ch. 18 - Prob. 1RQECh. 18 - Prob. 2RQECh. 18 - What is the difference between a static stack and...Ch. 18 - Prob. 4RQECh. 18 - The STL stack is considered a container adapter....Ch. 18 - What types may the STL stack be based on? By...
Ch. 18 - Prob. 7RQECh. 18 - Prob. 8RQECh. 18 - Prob. 9RQECh. 18 - Prob. 10RQECh. 18 - Prob. 11RQECh. 18 - Prob. 12RQECh. 18 - Prob. 13RQECh. 18 - Prob. 14RQECh. 18 - Prob. 15RQECh. 18 - Prob. 16RQECh. 18 - Prob. 17RQECh. 18 - Prob. 18RQECh. 18 - Prob. 1PCCh. 18 - Prob. 2PCCh. 18 - Prob. 3PCCh. 18 - Prob. 4PCCh. 18 - Prob. 5PCCh. 18 - Prob. 6PCCh. 18 - Prob. 7PCCh. 18 - Prob. 8PCCh. 18 - Prob. 14PCCh. 18 - Prob. 9PCCh. 18 - Prob. 10PCCh. 18 - Prob. 11PCCh. 18 - Prob. 12PCCh. 18 - Prob. 13PCCh. 18 - Prob. 15PC
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- You need to implement a class named "Queue" that simulates a basic queue data structure. The class should have the following methods: Enqueue(int value) - adds a new element to the end of the queue Dequeue() - removes the element from the front of the queue and returns it Peek() - returns the element from the front of the queue without removing it Count() - returns the number of elements in the queue The class should also have a property named "IsEmpty" that returns a boolean indicating whether the queue is empty or not. Constraints: The queue should be implemented using an array and the array should automatically resize when needed. All methods and properties should have a time complexity of O(1) You can write the program in C# and use the test cases to check if your implementation is correct. An example of how the class should be used: Queue myQueue = new Queue(); myQueue.Enqueue(1); myQueue.Enqueue(2); myQueue.Enqueue(3); Console.WriteLine(myQueue.Peek()); // 1…arrow_forwardListQueue Node Node Node front= next next= next = nul1 rear = data "Thome" data "Abreu" data - "Jones" size - 3 The above is a queue of a waiting list. The ListQueue has a node (front) to record the address of the front element of a queue. It also has another node (rear) to record the address of the tail element of a queue. 4. How do you push a node with data, "Chu" to the above queue? front.next = new Node("Chu", front); a. b. front = new Node ("Chu", front) rear = new Node("Chu", rear) с. d. = new Node ("Chu", rear.next) rear Describe the reason of your choice. Your answer is (a, b, c, or d) Will the push action take time in 0(1) or 0(n)? Next Page Type here to searcharrow_forwardThe data structure that allows for elements to be added and removed at both ends but not in the middle is called: 1.Double-ended Queue. 2.Priority Queue. 3.Duck. 4.Torque.arrow_forward
- C++ ProgrammingActivity: Queue Linked List Explain the flow of the code not necessarily every line, as long as you explain what the important parts of the code do. The code is already correct, just explain the flow. SEE ATTACHED PHOTO FOR THE PROBLEM #include "queue.h" #include "linkedlist.h" class SLLQueue : public Queue { LinkedList* list; public: SLLQueue() { list = new LinkedList(); } void enqueue(int e) { list->addTail(e); return; } int dequeue() { int elem; elem = list->removeHead(); return elem; } int first() { int elem; elem = list->get(1); return elem;; } int size() { return list->size(); } bool isEmpty() { return list->isEmpty(); } int collect(int max) { int sum = 0; while(first() != 0) { if(sum + first() <= max) { sum += first();…arrow_forwardAfter removing the next element from queue, what is the index of the first element?arrow_forwardA queue and a deque data structure are related concepts. Deque is an acronym meaning "double-ended queue." With a deque, you may insert, remove, or view from either end of the queue, which distinguishes it from the other two. Use arrays to implement a dequearrow_forward
- When removing a node from a linked list, what are the two steps?arrow_forwardA data structure called a deque is closely related to a queue. The name deque stands for “double-ended queue.” The difference between the two is that with a deque, you can insert, remove, or view from either end of the queue. Implement a deque using arraysarrow_forwardC++ ProgrammingActivity: Queue Linked List Explain the flow of the code not necessarily every line, as long as you explain what the important parts of the code do. The code is already correct, just explain the flow. #include "queue.h" #include "linkedlist.h" class SLLQueue : public Queue { LinkedList* list; public: SLLQueue() { list = new LinkedList(); } void enqueue(int e) { list->addTail(e); return; } int dequeue() { int elem; elem = list->removeHead(); return elem; } int first() { int elem; elem = list->get(1); return elem;; } int size() { return list->size(); } bool isEmpty() { return list->isEmpty(); } int collect(int max) { int sum = 0; while(first() != 0) { if(sum + first() <= max) { sum += first(); dequeue(); } else {…arrow_forward
- The definition of linked list is given as follows: struct Node { ElementType Element ; struct Node *Next ; } ; typedef struct Node *PtrToNode, *List, *Position; If L is head pointer of a linked list, then the data type of L should be ??arrow_forwarddata structures-java language quickly plsarrow_forwardListQueue Node Node Node front- next = next next - nul1 data - "Jones" rear data "Thome" data - "Abreu" size = 3 The above is a queue of a waiting list. The ListQueue has a node (front) to record the address of the front element of a queue. It also has another node (rear) to record the address of the tail element of a queue. 3. How do you pop a node from the above queue? a. front.next = front; b. front = front.next с. rear = rear.next d. rear.next = rear Describe the reason of your choice. Your answer is (a, b, c or d) will the pop action take time in 0(1) or 0(n)? Next Page P Type here to searcharrow_forward
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