(a)
Interpretation:
The given amine needs to be labeled as 10, 20 or 30.
Concept introduction:

Answer to Problem 74P
A tertiary (3o) amine.
Explanation of Solution
Amines are derivatives which are derived from ammonia, wherein one or more hydrogen atoms have been replaced by a substituent such as an alkyl or aryl group. They can be called as alkylamines and arylamines.
Whether an amine is primary (1o), secondary (2o) or tertiary (3o) depends on the number of hydrogen atoms replaced by an alkyl or aryl group in ammonia. The amine is a primary amine if one hydrogen atom is replaced, it is a secondary amine if 2 hydrogen atoms are replaced and if three hydrogen atoms are replaced it is known as a tertiary amine.
The given compound is as follows:
Here, only one hydrogen atom is replaced and therefore this amine called as a primary (1o) amine.
(b)
Interpretation:
The molecular shape around each atom of phentermine needs to be determined.
Concept introduction:
Molecular geometry is named as molecular shape and it is the three-dimensional arrangement of atoms within a molecule of the environment. Atoms arrange in space with an exact shape to minimize the repulsion. This can be determined using VSEPR theory.

Answer to Problem 74P
Carbons of benzene molecule;trigonal planar.
Carbon of −CH2 / -C(CH3)2NH2 CH2-/-CH3;tetrahedral.
Nitrogen of NH2;trigonal pyramidal.
Explanation of Solution
VSEPR or Valence Shell Electron Pair Repulsion theory is a model used to determine the geometry of molecules considering minimum electrostatic repulsion between the valence electrons of central atom in the molecule.
Carbons of benzene molecule;
Number of bonds= 3
Number of lone pairs = 0
Therefore, the shape is trigonal planar.
Carbon of −CH2/ -C(CH3)2NH2CH2-/-CH3;
Number of bonds= 4
Number of lone pairs = 0
Therefore, the shape is tetrahedral.
Nitrogen of NH2;
Number of bonds= 3
Number of lone pairs = 1
Therefore, the shape is trigonal pyramidal.
(c)
Interpretation:
The constitutional isomer containing a primary amine needs to be determined.
Concept introduction:
Constitutional isomers are called as compounds that have the unique molecular formula and different structural connectivity. To determine whether two molecules are constitutional isomer, the number of each atom needs to be counted in both molecules and see how the atoms are arranged.

Answer to Problem 74P
Explanation of Solution
Whether an amine is primary (1o), secondary (2o) or tertiary (3o) depends on the number of hydrogen atoms replaced by an alkyl or aryl group in ammonia. The amine is a primary amine if one hydrogen atom is replaced, it is a secondary amine if 2 hydrogen atoms are replaced and if three hydrogen atoms are replaced it is known as a tertiary amine.
Here all one hydrogen atom is replaced and therefore this amine called a primary amine (1o).
(d)
Interpretation:
The constitutional isomer that contains a secondary amine needs to be determined.
Concept introduction:
Constitutional isomers are called as compounds that have the unique molecular formula and different structural connectivity. To determine whether two molecules are constitutional isomer, the number of each atom needs to be counted in both molecules and see how the atoms are arranged.

Answer to Problem 74P
Explanation of Solution
Whether an amine is primary (1o), secondary (2o) or tertiary (3o) depends on the number of hydrogen atoms replaced by an alkyl or aryl group in ammonia. The amine is a primary amine if one hydrogen atom is replaced, it is a secondary amine if 2 hydrogen atoms are replaced and if three hydrogen atoms are replaced it is known as a tertiary amine.
Here all 3 hydrogen atoms are replaced and therefore this amine called as a secondary amine (2o).
(e)
Interpretation:
The structure of phentermine hydrobromide molecule needs to be drawn.
Concept introduction:
Phentermine hydrobromide can stimulate the central nervous system and increases the blood pressure and heart rate which decreases the appetite. It is taken along with diet and exercise in order to reduce obesity.

Answer to Problem 74P
Explanation of Solution
Phentermine hydrobromide can stimulate the central nervous system and increases the blood pressure and heart rate which decreases the appetite. It is taken along with the diet and exercise in order to reduce the obesity.
Its molecular formula is C17H22BrN. It has the following structure.
(f)
Interpretation:
The products formed if phentermine is treated with benzoic acid needs to be determined.
Concept introduction:
Amines are derivatives which are derived from ammonia, wherein one or more hydrogen atoms have been replaced by a substituent such as an alkyl or aryl group. They can be called as alkylamines and arylamines.

Answer to Problem 74P
Explanation of Solution
Amines are derivatives which are derived from ammonia, wherein one or more hydrogen atoms have been replaced by a substituent such as an alkyl or aryl group. They can be called as alkylamines and arylamines.
Whether an amine is primary (1o), secondary (2o) or tertiary (3o) depends on the number of hydrogen atoms replaced by an alkyl or aryl group in ammonia. The amine is a primary amine if one hydrogen atom is replaced, it is a secondary amine if 2 hydrogen atoms are replaced and if three hydrogen atoms are replaced it is known as a tertiary amine.
Benzphetamine is a tertiary ammine. It has basic properties and it accepts protons from acids. Acetic acid is donated a proton to this amine and formed below the salt.
Want to see more full solutions like this?
Chapter 18 Solutions
GENERAL,ORGANIC, & BIOLOGICAL CHEM-ACCES
- Rank the compounds below from lowest to highest melting point.arrow_forward18 Question (1 point) Draw the line structure form of the given partially condensed structure in the box provided. :ÖH HC HC H2 ΙΩ Н2 CH2 CH3 CH3 partially condensed formarrow_forwardsomeone else has already submitted the same question on here and it was the incorrect answer.arrow_forward
- The reaction: 2NO2(g) ⇌ N2O4(g) is an exothermic reaction, ΔH=-58.0 kJ/molrxn at 0°C the KP is 58.If the initial partial pressures of both NO2(g) and N2O4(g) are 2.00 atm:A) Is the reaction at equilibrium? If not, what is the value of Q? B) Which direction will the reaction go to reach equilibrium? C) Use an ICE table to find the equilibrium pressures.arrow_forwardThe dissociation of the weak acid, nitrous acid, HNO2, takes place according to the reaction: HNO2 (aq) ⇌ H+(aq) + NO2–(aq) K=7.2 X 10-4 When 1.00 mole of HNO2 is added to 1.00 L of water, the H+ concentration at equilibrium is 0.0265 M.A) Calculate the value of Q if 1.00 L of water is added? B) How will reaction shift if 1.00 L of water is added?arrow_forwardSuppose a certain copolymer elastomeric material “styrene-butadiene rubber”) contains styrene ("S") monomers –(C8H8)– and butadiene ("B") monomers –(C4H6)– and that their numerical ratio S:B = 1:8. What is the mass ratio mS:mB of the two monomers in the material? What is the molecular mass M of a macromolecule of this copolymer with degree of polymerization n = 60,000? Data: AC = 12.01 u, AH = 1.008 u.arrow_forward
- Lab Questions from Lab: Gravimetric Determination of Calcium as CaC2O4•H2O What is the purpose of the methyl red indicator? Why does a color change to yellow tell you that the reaction is complete? Why is the precipitate rinsed with ice-cold water in step 4? Why not room temperature or hot water? Why is it important that the funnels be placed in a desiccator before weighing (steps 1 and 5)?arrow_forwardWhat mass of ethylene glycol, HOCH2CH2OH, Mustbe added to 5.50 kg of water to antifreeze that would work for the car radiator to -10.0 degrees celcius? MM (g/mol): 62.07arrow_forwardWhat is the molarity of a 0.393 m glucose solution if its density is 1.16 g/mL? MM glucose 180.2 g/molarrow_forward
- The rate constant for the decay of a radioactive element is 2.28 × 10⁻³ day⁻¹. What is the half-life of this element in days?arrow_forwardHandwritten pleasearrow_forwardChoose the best reagents to complete the following reaction. i H A B 1. CH3CH2Na 2. H3O+ 1. CH3CH2MgBr 2. H3O+ 1. CH3MgBr Q C 2. H3O+ 1. H3O+ D 2. CH3MgBr 00 OH Q E CH³MgBrarrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning

