Chapter 18, Problem 63E

Interpretation Introduction

Interpretation:

The standard enthalpy change, ΔH° for the following reactions needs to be deduced:

  ${\text{4N}}_{\text{2}}{\text{H}}_{\text{3}}{\text{CH}}_{\text{3}}{\text{(l) + 5N}}_{\text{2}}{\text{O}}_4\text{(l) }\to {\text{ 12H}}_2\text{O}(g)+{\text{9N}}_2{\text{(g) + 4CO}}_2\text{(g)}$

Concept Introduction:

The standard enthalpy change for a reaction ${\text{ΔH}}_{\text{R}}^{\text{0}}$ measured at 298 K and 1 atm is given in terms of the difference in the standard enthalpy of formation of the products and that of reactants.

That is ${\text{ΔH}}_{\text{R}}^{\text{0}}\text{ = }{\displaystyle \sum {\text{n}}_{\text{p}}{\text{ΔH}}_{\text{f}}^{\text{0}}}\text{(products) - }{\displaystyle \sum {\text{n}}_{\text{r}}{\text{ΔH}}_{\text{f}}^{\text{0}}}\text{(reactants) ------(1)}$

Here, n_p and n_r are the number of moles of the products and reactants.