Chemical Principles
Chemical Principles
8th Edition
ISBN: 9781305581982
Author: Steven S. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Chapter 18, Problem 117AE

(a)

Interpretation Introduction

Interpretation: The hybridization of nitrogen atom in NO+ ion needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that existing on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

The shape or geometry of molecule can be predicted with the help of hybridization and VSEPR theory. It can be checked with the below formula:

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.

(a)

Expert Solution
Check Mark

Answer to Problem 117AE

  sp = linear; 180°

Explanation of Solution

To draw the Lewis structure of NO+

ion:

Number of valence electrons in N = 5

Number of valence electrons in O = 6

Total number of valence electrons in NO+ ion = 5 +6 -1 = 10 electrons

Hence the Lewis structure of NO+ ion must be:

  Chemical Principles, Chapter 18, Problem 117AE , additional homework tip  1

The hybridization can be checked with the help of Lewis structure and VSEPR theory which provide the geometry of molecules with lone pairs.

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.Hybridization = 1 +1Hybridization = sp = linear; 180°

(b)

Interpretation Introduction

Interpretation: The hybridization of nitrogen atom in N2O3(O2NN_O) molecule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that existing on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

The shape or geometry of molecule can be predicted with the help of hybridization and VSEPR theory. It can be checked with the below formula:

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.

(b)

Expert Solution
Check Mark

Answer to Problem 117AE

   sp2 = triangular planar; 120°

Explanation of Solution

To draw the Lewis structure of N2O3(O2NN_O)

molecule :

Number of valence electrons in N = 5

Number of valence electrons in O = 6

Total number of valence electrons in N2O3(O2NN_O) = (2x5)+(3x6) = 28 electrons

Hence the Lewis structure of N2O3(O2NN_O) must be:

  Chemical Principles, Chapter 18, Problem 117AE , additional homework tip  2

The hybridization can be checked with the help of Lewis structure and VSEPR theory which provide the geometry of molecules with lone pairs.

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.Hybridization = 2 +1Hybridization = sp2 = triangular planer; 120°

(c)

Interpretation Introduction

Interpretation: The hybridization of nitrogen atom in NO2 ion needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that existing on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

The shape or geometry of molecule can be predicted with the help of hybridization and VSEPR theory. It can be checked with the below formula:

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.

(c)

Expert Solution
Check Mark

Answer to Problem 117AE

   sp2 = triangular planer; 120°

Explanation of Solution

To draw the Lewis structure of NO2 ion:

Number of valence electrons in N = 5

Number of valence electrons in O = 6

Total number of valence electrons in NO2 ion =(1x5)+(2x6)+1 = 18 electrons

Hence the Lewis structure of NO2 ion must be:

  Chemical Principles, Chapter 18, Problem 117AE , additional homework tip  3

The hybridization can be checked with the help of Lewis structure and VSEPR theory which provide the geometry of molecules with lone pairs.

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.Hybridization = 2 +1Hybridization = sp2 = triangular planer; 120°

(d)

Interpretation Introduction

Interpretation: The hybridization of nitrogen atom in N2 molecule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that existing on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

The shape or geometry of molecule can be predicted with the help of hybridization and VSEPR theory. It can be checked with the below formula:

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.

(d)

Expert Solution
Check Mark

Answer to Problem 117AE

   sp = linear; 180°

Explanation of Solution

To draw the Lewis structure of N2 molecule :

Number of valence electrons in N = 5

Total number of valence electrons in N2 = (2x5) =10 electrons

Hence the Lewis structure of N2 must be:

  Chemical Principles, Chapter 18, Problem 117AE , additional homework tip  4

The hybridization can be checked with the help of Lewis structure and VSEPR theory which provide the geometry of molecules with lone pairs.

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.Hybridization = 1+1Hybridization = sp = linear; 180°

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Chapter 18 Solutions

Chemical Principles

Ch. 18 - Prob. 11ECh. 18 - Prob. 12ECh. 18 - Prob. 13ECh. 18 - Prob. 14ECh. 18 - Prob. 15ECh. 18 - Prob. 16ECh. 18 - Prob. 17ECh. 18 - Prob. 18ECh. 18 - Prob. 19ECh. 18 - Prob. 20ECh. 18 - Prob. 21ECh. 18 - Prob. 22ECh. 18 - Prob. 23ECh. 18 - Prob. 24ECh. 18 - Prob. 25ECh. 18 - Prob. 26ECh. 18 - Prob. 27ECh. 18 - Prob. 28ECh. 18 - Prob. 29ECh. 18 - Prob. 30ECh. 18 - Prob. 31ECh. 18 - Prob. 32ECh. 18 - Prob. 33ECh. 18 - Prob. 34ECh. 18 - Prob. 35ECh. 18 - Prob. 36ECh. 18 - Prob. 37ECh. 18 - Prob. 38ECh. 18 - Prob. 39ECh. 18 - Prob. 40ECh. 18 - Prob. 41ECh. 18 - Prob. 42ECh. 18 - Prob. 43ECh. 18 - Prob. 44ECh. 18 - Prob. 45ECh. 18 - Prob. 46ECh. 18 - Prob. 47ECh. 18 - Prob. 48ECh. 18 - Prob. 49ECh. 18 - The synthesis of ammonia gas from nitrogen gas...Ch. 18 - Prob. 51ECh. 18 - Prob. 52ECh. 18 - Prob. 53ECh. 18 - Prob. 54ECh. 18 - Prob. 55ECh. 18 - Prob. 56ECh. 18 - Prob. 57ECh. 18 - Prob. 58ECh. 18 - Prob. 59ECh. 18 - Prob. 60ECh. 18 - Prob. 61ECh. 18 - Prob. 62ECh. 18 - Prob. 63ECh. 18 - Prob. 64ECh. 18 - Prob. 65ECh. 18 - Prob. 66ECh. 18 - Prob. 67ECh. 18 - Prob. 68ECh. 18 - Prob. 69ECh. 18 - Prob. 70ECh. 18 - Prob. 71ECh. 18 - Prob. 72ECh. 18 - Prob. 73ECh. 18 - Prob. 74ECh. 18 - Prob. 75ECh. 18 - Prob. 76ECh. 18 - Prob. 77ECh. 18 - Prob. 78ECh. 18 - Prob. 79ECh. 18 - Prob. 80ECh. 18 - Prob. 81ECh. 18 - Prob. 82ECh. 18 - Prob. 83ECh. 18 - Prob. 84ECh. 18 - Prob. 85ECh. 18 - Prob. 86ECh. 18 - Prob. 87ECh. 18 - Prob. 88ECh. 18 - Prob. 89ECh. 18 - Prob. 90AECh. 18 - Prob. 91AECh. 18 - Prob. 92AECh. 18 - Prob. 93AECh. 18 - Prob. 94AECh. 18 - Prob. 95AECh. 18 - Prob. 96AECh. 18 - Prob. 97AECh. 18 - Prob. 98AECh. 18 - Prob. 99AECh. 18 - Prob. 100AECh. 18 - Prob. 101AECh. 18 - Prob. 102AECh. 18 - Prob. 103AECh. 18 - Prob. 104AECh. 18 - Prob. 105AECh. 18 - Prob. 106AECh. 18 - Prob. 107AECh. 18 - Prob. 108AECh. 18 - Prob. 109AECh. 18 - Prob. 110AECh. 18 - Prob. 111AECh. 18 - Prob. 112AECh. 18 - Hydrogen gas is being considered as a fuel for...Ch. 18 - Prob. 114AECh. 18 - Prob. 115AECh. 18 - Prob. 116AECh. 18 - Prob. 117AECh. 18 - Prob. 118AECh. 18 - Prob. 119AECh. 18 - What is the molecular structure for each of the...Ch. 18 - Prob. 121AECh. 18 - Prob. 122AECh. 18 - Prob. 123CPCh. 18 - Prob. 124CPCh. 18 - Prob. 125CPCh. 18 - Prob. 126CPCh. 18 - Prob. 127CPCh. 18 - Prob. 128CPCh. 18 - Prob. 129CPCh. 18 - Prob. 130CPCh. 18 - Prob. 131CPCh. 18 - Prob. 132CPCh. 18 - Prob. 133CP
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