Explanation 1) Concept: We can write an expression for the rate of energy loss through a glass window using the formula for conduction rate. Inserting values for both cases, we can get the rate of energy loss through a glass window for both cases. 2) Formula: P c o n d = k A ∆ T L 3) Given: i) Thickness of wire is L = 3.0 m m = 0.003 m . ii) Air gap between two windows is d = 7.5 c m = 0.075 m . iii) The temperature outside of the glass window is T o = - 20 ° F . iv) The temperature outside of the glass window is T i = 72 ° F . 4) Calculations: Thermal conductivity of glass is 1.0 W m . K . Temperature difference between inside and outside air of glass window is ∆ T = 72 - - 20 = 92 ° F = 5 9 92 = 51.1 ° c a) Conduction rate is P c o n d = k A ∆ T L ∴ P c o n d A = k ∆ T L P c o n d A = ( 1 ) 51.1 0.003 P c o n d A = 17033 ~ 1.7 × 10 4 W / m 2 Therefore, the rate of energy loss through a glass window is 1

Fundamentals of Physics, Volume 1, Chapter 1-20

10th Edition

ISBN: 9781118233764

Author: David Halliday

Publisher: WILEY

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Question

Chapter 18, Problem 57P

To determine

To find:

a) The rate of energy loss in W/m² through a glass window.

b) The rate of energy loss in W/m² through a glass window if conduction is the only important energy-loss mechanism.

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Chapter 18, Problem 56P

Chapter 18, Problem 58P

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Example Two charges, one with +10 μC of charge, and another with - 7.0 μC of charge are placed in line with each other and held at a fixed distance of 0.45 m. Where can you put a 3rd charge of +5 μC, so that the net force on the 3rd charge is zero?

* Coulomb's Law Example Three charges are positioned as seen below. Charge 1 is +2.0 μC and charge 2 is +8.0μC, and charge 3 is - 6.0MC. What is the magnitude and the direction of the force on charge 2 due to charges 1 and 3? 93 kq92 F == 2 r13 = 0.090m 91 r12 = 0.12m 92 Coulomb's Constant: k = 8.99x10+9 Nm²/C² ✓

Make sure to draw a Free Body Diagram as well

Chapter 18 Solutions

Fundamentals of Physics, Volume 1, Chapter 1-20

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a) The rate of energy loss in W/m 2 through a glass window. b) The rate of energy loss in W/m 2 through a glass window if conduction is the only important energy-loss mechanism.

Solution Summary: The author explains how to write an expression for the rate of energy loss through a glass window using the formula for conduction rate.

Concept explainers

To find:

a) The rate of energy loss in W/m² through a glass window.

b) The rate of energy loss in W/m² through a glass window if conduction is the only important energy-loss mechanism.

Want to see the full answer?

Chapter 18 Solutions

a) The rate of energy loss in W/m 2 through a glass window. b) The rate of energy loss in W/m 2 through a glass window if conduction is the only important energy-loss mechanism.

Solution Summary: The author explains how to write an expression for the rate of energy loss through a glass window using the formula for conduction rate.

Concept explainers

To find: a) The rate of energy loss in W/m2 through a glass window. b) The rate of energy loss in W/m2 through a glass window if conduction is the only important energy-loss mechanism.

Want to see the full answer?

Chapter 18 Solutions

To find:

a) The rate of energy loss in W/m² through a glass window.

b) The rate of energy loss in W/m² through a glass window if conduction is the only important energy-loss mechanism.