
(a)
Interpretation:
The structure for the eight constitutional isomers of molecular formula C4H11N should be drawn.
Concept Introduction:
There are three types of

Answer to Problem 42P
The structures for the eight constitutional isomers of molecular formula C4H11N are represented as follows:
Explanation of Solution
Four structures of primary amines can be drawn with the formula C4H11N.
Three structures of secondary amines can also be drawn.
A tertiary structure can also be drawn as follows:
(b)
Interpretation:
The systematic name for each amine should be given.
Concept Introduction:
In nomenclature of primary amine, the longest carbon chain bonded to nitrogen is determined and the −e ending of the parent

Answer to Problem 42P
The name of amines are as follows:
1-butanamine 2-methylpropan-1-amine butan-2-amine
2-methylpropan-2-amine N-ethylethanamine N-methylpropan-1-amine
N-methylpropan-2-amine N,N-dimethylethanamine
Explanation of Solution
The longest carbon chain has four carbons. So the alkane name is butane. N is attached to C-1. Therefore, the systematic name of the amine is butanamine.
The longest carbon chain has three carbons. There is a methyl group at C-2. So the parent name is 2-methylpropanamine. The N atom is bonded to C-1. Therefore, the name become 2-methylpropan-1-amine.
The longest carbon chain bonded to amine group has four carbons. The parent name is butanamine. The N atom is bonded to C-2. Therefore, the systematic name of the amine is butan-2-amine.
The longest carbon chain bonded to amine group has three carbons. There is a methyl group at C-2. The parent name is 2-methylpropanamine. The N atom is bonded to C-2. Therefore, the systematic name of the amine is 2-methylpropan-2-amine.
The secondary amine has the longest carbon chain with 2 carbons. So, the parent name is ethanamine. The N atom has bonded to C-1 and has 1 ethyl group as a substituent. Therefore, the systematic name become N-ethylethanamine.
The secondary amine has the longest carbon chain with 3 carbons. So, the parent name is propanamine. The N atom has bonded to C-1 and has 1 methyl group as a substituent. Therefore, the systematic name become N-methylpropan-1-amine.
The secondary amine has the longest carbon chain with 3 carbons. So, the parent name is propanamine. The N atom has bonded to C-2 and has 1 methyl group as a substituent. Therefore, the systematic name become N-methylpropan-2-amine.
The tertiary amine has the longest carbon chain with 2 carbons. So the parent name is ethanamine. N atom has bonded to C-1 and has two methyl groups and 1 ethyl group as substituents. So, the systematic name of the amine is N,N-dimethylethanamine.
(c)
Interpretation:
The chirality center present in one of the amines should be identified.
Concept Introduction:
An atom that has four different groups bonded to it is referred to as chirality center. A chiral molecule has a non-superimposable mirror image.

Answer to Problem 42P
Explanation of Solution
Butan-2-amine has long carbon chain with 4 carbons and amine group is bonded to C-2. This C-2 carbon has four different groups bonded to it as 1 ethyl group, 1 methyl group, 1 amine group and a hydrogen. So, C-2 carbon is a chirality center.
Want to see more full solutions like this?
Chapter 18 Solutions
Loose Leaf for General, Organic and Biological Chemistry with Connect 2 Year Access Card
- Draw the major product of this reaction. Ignore inorganic byproducts. Assume that the water side product is continuously removed to drive the reaction toward products. (CH3)2NH, TSOH Drawingarrow_forwardSo, the first image is what I'm trying to understand regarding my approach. The second image illustrates my teacher's method, and the third image includes my notes on the concepts behind these types of problems.arrow_forwardHAND DRAWarrow_forward
- Draw a mental model for calcium chloride mixed with sodium phosphatearrow_forwardhere is my question (problem number 20) please explain to me thanks!arrow_forwardThe bromination of anisole is an extremely fast reaction. Complete the resonance structures of the intermediate arenium cation for the reaction (Part 1), and then answer the question that follows (Part 2).arrow_forward
- Drawing of 3-fluro-2methylphenolarrow_forwardWhich compound(s) will be fully deprotonated (>99%) by reaction with one molar equivalent of sodium hydroxide? I, II, III I, || I, III I only II, III SH | H3C-C=C-H || III NH2arrow_forwardWill NBS (and heat or light) work for this reaction, or do we have to use Br2?arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning

