Concept explainers
(a)
Interpretation:
The structure of 1-decanamine needs to be determined.
Concept Introduction:
The name of the
In the case of secondary and tertiary amines, if there are more than 1 same alkyl groups present, they are named using prefix di- or tri- along with the primary amine name. If there is more than one type of alkyl groups, they are named as N-substituted primary amines.
(b)
Interpretation:
The structure of tricyclohexylamine needs to be determined.
Concept Introduction:
The name of the amines is written based on their structure that whether they are primary, secondary or tertiary. The name of the primary amine is written using the longest carbon chain having the amine group. At the end of the name of the parent alkane chain, the suffix amine is added.
In the case of secondary and tertiary amines, if there are more than 1 same alkyl groups present, they are named using prefix di- or tri- along with the primary amine name. If there is more than one type of alkyl groups, they are named as N-substituted primary amines.
(c)
Interpretation:
The structure of p-bromoaniline needs to be determined.
Concept Introduction:
The name of the amines is written based on their structure that whether they are primary, secondary or tertiary. The name of the primary amine is written using the longest carbon chain having the amine group. At the end of the name of the parent alkane chain, the suffix amine is added.
In the case of secondary and tertiary amines, if there are more than 1 same alkyl groups present, they are named using prefix di- or tri- along with the primary amine name. If there is more than one type of alkyl groups, they are named as N-substituted primary amines.
(d)
Interpretation:
The structure of 3-aminobutanoic needs to be determined.
Concept Introduction:
The name of the amines is written based on their structure that whether they are primary, secondary or tertiary. The name of the primary amine is written using the longest carbon chain having the amine group. At the end of the name of the parent alkane chain, the suffix amine is added.
In the case of secondary and tertiary amines, if there are more than 1 same alkyl groups present, they are named using prefix di- or tri- along with the primary amine name. If there is more than one type of alkyl groups, they are named as N-substituted primary amines.
(e)
Interpretation:
The structure of N, N-dipropyl-2-octanmine needs to be determined.
Concept Introduction:
The name of the amines is written based on their structure that whether they are primary, secondary or tertiary. The name of the primary amine is written using the longest carbon chain having the amine group. At the end of the name of the parent alkane chain, the suffix amine is added.
In the case of secondary and tertiary amines, if there are more than 1 same alkyl groups present, they are named using prefix di- or tri- along with the primary amine name. If there is more than one type of alkyl groups, they are named as N-substituted primary amines.
(f)
Interpretation:
The structure of N-ethylhexylamine needs to be drawn.
Concept Introduction:
The name of the amines is written based on their structure that whether they are primary, secondary or tertiary. The name of the primary amine is written using the longest carbon chain having the amine group. At the end of the name of the parent alkane chain, the suffix amine is added.
In the case of secondary and tertiary amines, if there are more than 1 same alkyl groups present, they are named using prefix di- or tri- along with the primary amine name. If there is more than one type of alkyl groups, they are named as N-substituted primary amines.

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Chapter 18 Solutions
CONNECT IA GENERAL ORGANIC&BIO CHEMISTRY
- > You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: 1. ☑ CI 2. H3O+ O Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. Explanation Check ? DO 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibilityarrow_forwardDon't use ai to answer I will report you answerarrow_forwardConsider a solution of 0.00304 moles of 4-nitrobenzoic acid (pKa = 3.442) dissolved in 25 mL water and titrated with 0.0991 M NaOH. Calculate the pH at the equivalence pointarrow_forward
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