Concept explainers
(a)
Interpretation:
The amine needs to be labeled as 10, 20 or 30.
Concept introduction:
Answer to Problem 73P
A tertiary (3o) amine.
Explanation of Solution
Amines are derivatives which are derived from ammonia, wherein one or more hydrogen atoms have been replaced by a substituent such as an alkyl or aryl group. They can be called as alkylamines and arylamines.
Whether an amine is primary (1o), secondary (2o) or tertiary (3o) depends on the number of hydrogen atoms replaced by an alkyl or aryl group in ammonia. The amine is a primary amine if one hydrogen atom is replaced, it is a secondary amine if 2 hydrogen atoms are replaced and if three hydrogen atoms are replaced, it is known as a tertiary amine.
Here, all three hydrogen atoms are replaced and therefore this amine called a tertiary (3o) amine.
(b)
Interpretation:
The chiral center of the benzphetamine molecule needs to be labeled.
Concept Introduction:
The molecules with a chiral center can form a superimposable mirror image and is known as enantiomers. There should not be any plane of symmetry in a molecule to be chiral. A plane that bisects a molecule into two equal halves is known as a plane of symmetry. If there is a plane of symmetry in a molecule and it is identical to any of its mirror image, it is considered as achiral. The chiral center is carbon attached to 4 different groups attached to it.
Answer to Problem 73P
Explanation of Solution
The chiral center in the given molecule is shown as follows:
The labeled carbon atom is attached to 4 different groups.
The chiral center has four different groups attached to carbon and no plane of symmetry. The molecule with a chiral center shows optical isomerism. The chiral center is a stereocenter holding the atoms in space, the mirror image so formed are not superimposable.
(c)
Interpretation:
The enantiomers of benzphetamine molecule needs to be determined.
Concept introduction:
The chiral molecules which are mirror images of each other are known as enantiomers. They are non-superimposable mirror images, or they cannot be placed on top of each other.
Answer to Problem 73P
Explanation of Solution
Benzphetamine has two enantiomers due to its one chiral center. It rotates the plane-polarized light. Here, S-benzphetamine rotates the light anticlockwise and R- benzphetamine rotates it clockwise.
Benzphetaminecan can be called as a racemic mixture of two enantiomers, which are R(+) and S(-).
(d)
Interpretation:
The constitutional isomer that contains a primary amine needs to be drawn.
Concept introduction:
Constitutional isomers have the same molecular formula but different structural connectivity. The number of each atom in both the molecules needs to be counted and the arrangement is observed to check whether two molecules are a constitutional isomer of each other or not.
Answer to Problem 73P
Explanation of Solution
Whether an amine is primary (1o), secondary (2o) or tertiary (3o) depends on the number of hydrogen atoms replaced by an alkyl or aryl group in ammonia. The amine is a primary amine if one hydrogen atom is replaced, it is a secondary amine if 2 hydrogen atoms are replaced and if three hydrogen atoms are replaced it is known as a tertiary amine.
The given compound is as follows:
The constitutional isomer with a primary amine is as follows:
Here, only one hydrogen atom is replaced therefore this amine called a primary amine (1o).
(e)
Interpretation:
The constitutional isomer that contains a tertiary amine needs to be determined.
Concept introduction:
Constitutional isomers have the same molecular formula but different structural connectivity. The number of each atom in both the molecules needs to be counted and the arrangement is observed to check whether two molecules are a constitutional isomer of each other or not.
Answer to Problem 73P
Explanation of Solution
Whether an amine is primary (1o), secondary (2o) or tertiary (3o) depends on the number of hydrogen atoms replaced by an alkyl or aryl group in ammonia. The amine is a primary amine if one hydrogen atom is replaced, it is a secondary amine if 2 hydrogen atoms are replaced and if three hydrogen atoms are replaced it is known as a tertiary amine.
The given compound is as follows:
The constitutional isomer with a tertiary amine is represented as follows:
Here all 3 hydrogen atomsare replaced and therefore this amine called as a tertiary amine (3o).
(f)
Interpretation:
The structure of benzphetaminehychloride molecule needs to be drawn.
Concept introduction:
Benzphetamine hydrochloride can be defined as the hydrochloride salt version of benzphetamine.
Answer to Problem 73P
Explanation of Solution
Benzphetamine hydrochloride can be defined as the hydrochloride salt version of benzphetamine. Its molecular formula is C17H22ClN. It has the following structure.
(g)
Interpretation:
The products formed if benzphetamine is treated with acetic acid needs to be determined.
Concept introduction:
Amines are derived from ammonia and formed by replacement of one or more hydrogen atoms by alkyl or aryl groups. They can be called as alkylamines and arylamines. Benzphetamine is a tertiary amine.
Answer to Problem 73P
Explanation of Solution
Whether an amine is primary (1o), secondary (2o) or tertiary (3o) depends on the number of hydrogen atoms replaced by an alkyl or aryl group in ammonia. The amine is a primary amine if one hydrogen atom is replaced, it is a secondary amine if 2 hydrogen atoms are replaced and if three hydrogen atoms are replaced it is known as a tertiary amine.
Benzphetamine is a tertiary ammine. It has basic properties and it accepts protons from acids. Acetic acid donates a proton to this amine and formed below the salt.
Want to see more full solutions like this?
Chapter 18 Solutions
CONNECT IA GENERAL ORGANIC&BIO CHEMISTRY
- 4. Propose a synthesis of the target molecules from the respective starting materials. a) b) LUCH C Br OHarrow_forwardThe following mechanism for the gas phase reaction of H2 and ICI that is consistent with the observed rate law is: step 1 step 2 slow: H2(g) +ICI(g) → HCl(g) + HI(g) fast: ICI(g) + HI(g) → HCl(g) + |2(g) (1) What is the equation for the overall reaction? Use the smallest integer coefficients possible. If a box is not needed, leave it blank. + → + (2) Which species acts as a catalyst? Enter formula. If none, leave box blank: (3) Which species acts as a reaction intermediate? Enter formula. If none, leave box blank: (4) Complete the rate law for the overall reaction that is consistent with this mechanism. (Use the form k[A][B]"..., where '1' is understood (so don't write it) for m, n etc.) Rate =arrow_forwardPlease correct answer and don't use hand rating and don't use Ai solutionarrow_forward
- 1. For each of the following statements, indicate whether they are true of false. ⚫ the terms primary, secondary and tertiary have different meanings when applied to amines than they do when applied to alcohols. • a tertiary amine is one that is bonded to a tertiary carbon atom (one with three C atoms bonded to it). • simple five-membered heteroaromatic compounds (e.g. pyrrole) are typically more electron rich than benzene. ⚫ simple six-membered heteroaromatic compounds (e.g. pyridine) are typically more electron rich than benzene. • pyrrole is very weakly basic because protonation anywhere on the ring disrupts the aromaticity. • thiophene is more reactive than benzene toward electrophilic aromatic substitution. • pyridine is more reactive than nitrobenzene toward electrophilic aromatic substitution. • the lone pair on the nitrogen atom of pyridine is part of the pi system.arrow_forwardThe following reactions are NOT ordered in the way in which they occur. Reaction 1 PhO-OPh Reaction 2 Ph-O -CH₂ heat 2 *OPh Pho -CH2 Reaction 3 Ph-O ⚫OPh + -CH₂ Reaction 4 Pho Pho + H₂C OPh + CHOPh H₂C -CH₂ Reactions 1 and 3 Reaction 2 O Reaction 3 ○ Reactions 3 and 4 ○ Reactions 1 and 2 Reaction 4 ○ Reaction 1arrow_forwardSelect all possible products from the following reaction: NaOH H₂O a) b) ОН HO O HO HO e) ОН f) O HO g) h) + OHarrow_forward
- 3. Draw diagrams to represent the conjugation in these molecules. Draw two types of diagram: a. Show curly arrows linking at least two different ways of representing the molecule b. Indicate with dotted lines and partial charges (where necessary) the partial double bond (and charge) distribution H₂N* H₂N -NH2arrow_forwardQuestion 2 of 25 point Question Attempt 3 of Ulimited Draw the structure for 3-chloro-4-ethylheptane. Part 2 of 3 Click and drag to start drawing a structure. Draw the structure for 1-chloro-4-ethyl-3-lodooctane. Click and drag to start drawing a structure. X G X B c Part 3 of 30 Draw the structure for (R)-2-chlorobutane. Include the stereochemistry at all stereogenic centers. Check Click and drag to start drawing a structure. G X A 。 MacBook Pro G P Save For Later Submit Assignment Privacyarrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- In a silicon and aluminum alloy, with 12.6% silicon, what are the approximate percentages of the phases present in the constituent that is formed at the end of solidification? Temperature (°C) 1500 1000 L B+L 1415- α+L 577' 500 1.65 12.6 99.83 α+B B 0 Al 20 40 60 Weight percent silicon 80 Siarrow_forwardPlease correct answer and don't used hand raitingarrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage LearningOrganic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningOrganic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
- Macroscale and Microscale Organic ExperimentsChemistryISBN:9781305577190Author:Kenneth L. Williamson, Katherine M. MastersPublisher:Brooks Cole