Compound that can remove H B r more rapidly in a basic solution has to be identified. Concept introduction: Catalyst: Substance which helps in increasing the rate of a particular reaction without getting consumed in the reaction. Base Catalyst: A catalyst which helps in increasing the rate of a particular reaction by the removal of a proton. There are two types of catalysis: 1. Specific-base catalysis: Proton is completely removed before the slow step in a reaction 2. General- base catalysis: Proton is completely removed during the slow step in a reaction Intramolecular general-base catalysis: A catalysis where catalyst is a part of the molecule that undergoes the reaction promotes the reaction in a species by completely removing a proton during the slow step in a reaction

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 18, Problem 32P

Interpretation Introduction

Interpretation:

Compound that can remove HBr more rapidly in a basic solution has to be identified.

Concept introduction:

Catalyst: Substance which helps in increasing the rate of a particular reaction without getting consumed in the reaction.

Base Catalyst: A catalyst which helps in increasing the rate of a particular reaction by the removal of a proton. There are two types of catalysis:

1. Specific-base catalysis: Proton is completely removed before the slow step in a reaction

2. General- base catalysis: Proton is completely removed during the slow step in a reaction

Intramolecular general-base catalysis: A catalysis where catalyst is a part of the molecule that undergoes the reaction promotes the reaction in a species by completely removing a proton during the slow step in a reaction

Expert Solution & Answer

Explanation of Solution

In the below compound, negatively charged oxygen atom is in axial position where it can easily undergo intramolecular general-base reaction comparing to O− group in equatorial position. Here, the O− act as the intramolecular catalyst where it attacks the proton atom from the carbon atom that is attached to CH2Br group. Thus, HBr is easily removed in the below compound due to the position of negatively charge oxygen.

Essential Organic Chemistry (3rd Edition), Chapter 18, Problem 32P , additional homework tip 1

Therefore, the compound where HBr is easily removed in a basic solution is,

Essential Organic Chemistry (3rd Edition), Chapter 18, Problem 32P , additional homework tip 2

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Identify the starting material in the following reaction. Click the "draw structure" button to launch the drawing utility. draw structure ... [1] 0 3 C10H18 [2] CH3SCH3 H

In an equilibrium mixture of the formation of ammonia from nitrogen and hydrogen, it is found that PNH3 = 0.147 atm, PN2 = 1.41 atm and Pн2 = 6.00 atm. Evaluate Kp and Kc at 500 °C. 2 NH3 (g) N2 (g) + 3 H₂ (g) K₂ = (PN2)(PH2)³ = (1.41) (6.00)³ = 1.41 x 104

What alkene or alkyne yields the following products after oxidative cleavage with ozone? Click the "draw structure" button to launch the drawing utility. and two equivalents of CH2=O draw structure ...

Answer 2

Question

Chapter 18, Problem 32P

Interpretation Introduction

Interpretation:

Compound that can remove HBr more rapidly in a basic solution has to be identified.

Concept introduction:

Catalyst: Substance which helps in increasing the rate of a particular reaction without getting consumed in the reaction.

Base Catalyst: A catalyst which helps in increasing the rate of a particular reaction by the removal of a proton. There are two types of catalysis:

1. Specific-base catalysis: Proton is completely removed before the slow step in a reaction

2. General- base catalysis: Proton is completely removed during the slow step in a reaction

Intramolecular general-base catalysis: A catalysis where catalyst is a part of the molecule that undergoes the reaction promotes the reaction in a species by completely removing a proton during the slow step in a reaction

Expert Solution & Answer

Explanation of Solution

In the below compound, negatively charged oxygen atom is in axial position where it can easily undergo intramolecular general-base reaction comparing to O− group in equatorial position. Here, the O− act as the intramolecular catalyst where it attacks the proton atom from the carbon atom that is attached to CH2Br group. Thus, HBr is easily removed in the below compound due to the position of negatively charge oxygen.

Essential Organic Chemistry (3rd Edition), Chapter 18, Problem 32P , additional homework tip 1

Therefore, the compound where HBr is easily removed in a basic solution is,

Essential Organic Chemistry (3rd Edition), Chapter 18, Problem 32P , additional homework tip 2

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 18, Problem 32P

Interpretation Introduction

Interpretation:

Compound that can remove HBr more rapidly in a basic solution has to be identified.

Concept introduction:

Catalyst: Substance which helps in increasing the rate of a particular reaction without getting consumed in the reaction.

Base Catalyst: A catalyst which helps in increasing the rate of a particular reaction by the removal of a proton. There are two types of catalysis:

1. Specific-base catalysis: Proton is completely removed before the slow step in a reaction

2. General- base catalysis: Proton is completely removed during the slow step in a reaction

Intramolecular general-base catalysis: A catalysis where catalyst is a part of the molecule that undergoes the reaction promotes the reaction in a species by completely removing a proton during the slow step in a reaction

Expert Solution & Answer

Explanation of Solution

In the below compound, negatively charged oxygen atom is in axial position where it can easily undergo intramolecular general-base reaction comparing to O− group in equatorial position. Here, the O− act as the intramolecular catalyst where it attacks the proton atom from the carbon atom that is attached to CH2Br group. Thus, HBr is easily removed in the below compound due to the position of negatively charge oxygen.

Essential Organic Chemistry (3rd Edition), Chapter 18, Problem 32P , additional homework tip 1

Therefore, the compound where HBr is easily removed in a basic solution is,

Essential Organic Chemistry (3rd Edition), Chapter 18, Problem 32P , additional homework tip 2

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 18, Problem 32P

Interpretation Introduction

Interpretation:

Compound that can remove HBr more rapidly in a basic solution has to be identified.

Concept introduction:

Catalyst: Substance which helps in increasing the rate of a particular reaction without getting consumed in the reaction.

Base Catalyst: A catalyst which helps in increasing the rate of a particular reaction by the removal of a proton. There are two types of catalysis:

1. Specific-base catalysis: Proton is completely removed before the slow step in a reaction

2. General- base catalysis: Proton is completely removed during the slow step in a reaction

Intramolecular general-base catalysis: A catalysis where catalyst is a part of the molecule that undergoes the reaction promotes the reaction in a species by completely removing a proton during the slow step in a reaction

Expert Solution & Answer

Explanation of Solution

In the below compound, negatively charged oxygen atom is in axial position where it can easily undergo intramolecular general-base reaction comparing to O− group in equatorial position. Here, the O− act as the intramolecular catalyst where it attacks the proton atom from the carbon atom that is attached to CH2Br group. Thus, HBr is easily removed in the below compound due to the position of negatively charge oxygen.

Essential Organic Chemistry (3rd Edition), Chapter 18, Problem 32P , additional homework tip 1

Therefore, the compound where HBr is easily removed in a basic solution is,

Essential Organic Chemistry (3rd Edition), Chapter 18, Problem 32P , additional homework tip 2

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 18, Problem 32P

Interpretation Introduction

Interpretation:

Compound that can remove HBr more rapidly in a basic solution has to be identified.

Concept introduction:

Catalyst: Substance which helps in increasing the rate of a particular reaction without getting consumed in the reaction.

Base Catalyst: A catalyst which helps in increasing the rate of a particular reaction by the removal of a proton. There are two types of catalysis:

1. Specific-base catalysis: Proton is completely removed before the slow step in a reaction

2. General- base catalysis: Proton is completely removed during the slow step in a reaction

Intramolecular general-base catalysis: A catalysis where catalyst is a part of the molecule that undergoes the reaction promotes the reaction in a species by completely removing a proton during the slow step in a reaction

Expert Solution & Answer

Explanation of Solution

In the below compound, negatively charged oxygen atom is in axial position where it can easily undergo intramolecular general-base reaction comparing to O− group in equatorial position. Here, the O− act as the intramolecular catalyst where it attacks the proton atom from the carbon atom that is attached to CH2Br group. Thus, HBr is easily removed in the below compound due to the position of negatively charge oxygen.

Essential Organic Chemistry (3rd Edition), Chapter 18, Problem 32P , additional homework tip 1

Therefore, the compound where HBr is easily removed in a basic solution is,

Essential Organic Chemistry (3rd Edition), Chapter 18, Problem 32P , additional homework tip 2

Answer 6

Chapter 18, Problem 32P

Interpretation Introduction

Interpretation:

Compound that can remove HBr more rapidly in a basic solution has to be identified.

Concept introduction:

Catalyst: Substance which helps in increasing the rate of a particular reaction without getting consumed in the reaction.

Base Catalyst: A catalyst which helps in increasing the rate of a particular reaction by the removal of a proton. There are two types of catalysis:

1. Specific-base catalysis: Proton is completely removed before the slow step in a reaction

2. General- base catalysis: Proton is completely removed during the slow step in a reaction

Intramolecular general-base catalysis: A catalysis where catalyst is a part of the molecule that undergoes the reaction promotes the reaction in a species by completely removing a proton during the slow step in a reaction

Expert Solution & Answer

Explanation of Solution

In the below compound, negatively charged oxygen atom is in axial position where it can easily undergo intramolecular general-base reaction comparing to O− group in equatorial position. Here, the O− act as the intramolecular catalyst where it attacks the proton atom from the carbon atom that is attached to CH2Br group. Thus, HBr is easily removed in the below compound due to the position of negatively charge oxygen.

Essential Organic Chemistry (3rd Edition), Chapter 18, Problem 32P , additional homework tip 1

Therefore, the compound where HBr is easily removed in a basic solution is,

Essential Organic Chemistry (3rd Edition), Chapter 18, Problem 32P , additional homework tip 2

Answer 7

Chapter 18, Problem 32P

Interpretation Introduction

Interpretation:

Compound that can remove HBr more rapidly in a basic solution has to be identified.

Concept introduction:

Catalyst: Substance which helps in increasing the rate of a particular reaction without getting consumed in the reaction.

Base Catalyst: A catalyst which helps in increasing the rate of a particular reaction by the removal of a proton. There are two types of catalysis:

1. Specific-base catalysis: Proton is completely removed before the slow step in a reaction

2. General- base catalysis: Proton is completely removed during the slow step in a reaction

Intramolecular general-base catalysis: A catalysis where catalyst is a part of the molecule that undergoes the reaction promotes the reaction in a species by completely removing a proton during the slow step in a reaction

Answer 8

Expert Solution & Answer

Explanation of Solution

In the below compound, negatively charged oxygen atom is in axial position where it can easily undergo intramolecular general-base reaction comparing to O− group in equatorial position. Here, the O− act as the intramolecular catalyst where it attacks the proton atom from the carbon atom that is attached to CH2Br group. Thus, HBr is easily removed in the below compound due to the position of negatively charge oxygen.