Concept explainers
(a)
To find:
The direction of the electric field at the center of the given square.

Answer to Problem 19PE
Electric field at the center of the square is in upward direction.
Explanation of Solution
Given:
Four charges qa, qb, qc, qd placed at each corner of the square with side 5 cmhaving magnitude qa= qb = -1.00 μC, qc= qd = +1.00 μC.
Electric field is something that is produced by the charge around it and another charge placed in it experiences a force. Charges of same sign repel each other and the charges of opposite sign attract each other.
In the given fig., place a test charge q at the center of the square. Charges qa, qbattract the test charge with same because both the charges are negative in nature and having same magnitude. And the charges qc, qdrepel the test charge with same force as the charges are of positive in nature and have the same magnitude.
Conclusion:
The direction of the resultant electric field at the center of the square is in upward direction due to entire system.
(b)
To calculate:
The magnitude of the electric field at the location of q.

Answer to Problem 19PE
Explanation of Solution
Given:
Side of the square = 5 cm
Formula used:
εο = permittivity of free space,
E = intensity of the electric field,
q = given charge,
r = distance between the charge q and the point where electric field needs to be calculated.
Calculation:
The electric field at q due to the charge qa and qb
On putting the values,
Conclusion:
The magnitude of the electric field at the location of q is
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Chapter 18 Solutions
COLLEGE PHYSICS
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