Explanation Given info: The length of the string is 0.400 m , the mass per unit length is 9.00 × 10 − 3 kg / m . The length of the pipe opened at one end in the condition of second resonance is, L p = 3 λ 4 λ = 4 L p 3 . (1) Here, λ is the wavelength. L p is the length of pipe. Substitute 1.75 m for L p in equation (1). λ = 4 × 1.75 m 3 = 2.33 m The formula for the frequency of the string is, f = v λ Here, v is the speed of sound. Substitute 343 m / s for v and 2.33 m for λ in above equation. f = 343 m / s 2.33 m = 147.21 Hz The length of string is equal to the wavelength. λ = L s Substitute 0

9th Edition

ISBN: 9780100460300

Author: SERWAY

Publisher: YUZU

See similar textbooks

Concept explainers

Properties of sound

A sound wave is a mechanical wave (or mechanical vibration) that transit through media such as gas (air), liquid (water), and solid (wood).

Quality Of Sound

A sound or a sound wave is defined as the energy produced due to the vibrations of particles in a medium. When any medium produces a disturbance or vibrations, it causes a movement in the air particles which produces sound waves. Molecules in the air vib…

Categories of Sound Wave

People perceive sound in different ways, like a medico student takes sound as vibration produced by objects reaching the human eardrum. A physicist perceives sound as vibration produced by an object, which produces disturbances in nearby air molecules th…

Videos

Question

Chapter 18, Problem 18.63AP

To determine

The tension in string if its second harmonic has the same frequency as the second resonance mode of a 1.75 m long pipe open at one end.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 18, Problem 18.62AP

Chapter 18, Problem 18.64AP

Students have asked these similar questions

For each of the actions depicted below, a magnet and/or metal loop moves with velocity v→ (v→ is constant and has the same magnitude in all parts). Determine whether a current is induced in the metal loop. If so, indicate the direction of the current in the loop, either clockwise or counterclockwise when seen from the right of the loop. The axis of the magnet is lined up with the center of the loop. For the action depicted in (Figure 5), indicate the direction of the induced current in the loop (clockwise, counterclockwise or zero, when seen from the right of the loop). I know that the current is clockwise, I just dont understand why. Please fully explain why it's clockwise, Thank you

A planar double pendulum consists of two point masses \[m_1 = 1.00~\mathrm{kg}, \qquad m_2 = 1.00~\mathrm{kg}\]connected by massless, rigid rods of lengths \[L_1 = 1.00~\mathrm{m}, \qquad L_2 = 1.20~\mathrm{m}.\]The upper rod is hinged to a fixed pivot; gravity acts vertically downward with\[g = 9.81~\mathrm{m\,s^{-2}}.\]Define the generalized coordinates \(\theta_1,\theta_2\) as the angles each rod makes with thedownward vertical (positive anticlockwise, measured in radians unless stated otherwise).At \(t=0\) the system is released from rest with \[\theta_1(0)=120^{\circ}, \qquad\theta_2(0)=-10^{\circ}, \qquad\dot{\theta}_1(0)=\dot{\theta}_2(0)=0 .\]Using the exact nonlinear equations of motion (no small-angle or planar-pendulumapproximations) and assuming the rods never stretch or slip, determine the angle\(\theta_2\) at the instant\[t = 10.0~\mathrm{s}.\]Give the result in degrees, in the interval \((-180^{\circ},180^{\circ}]\).

What are the expected readings of the ammeter and voltmeter for the circuit in the figure below? (R = 5.60 Ω, ΔV = 6.30 V) ammeter I =

Chapter 18 Solutions

EBK PHYSICS FOR SCIENTISTS AND ENGINEER

Ch. 18 - Prob. 18.1QQ Ch. 18 - Consider the waves in Figure 17.8 to be waves on a...Ch. 18 - When a standing wave is set up on a string fixed...Ch. 18 - Prob. 18.4QQ Ch. 18 - Balboa Park in San Diego has an outdoor organ....Ch. 18 - In figure OQ18.1 (page 566), a sound wave of...Ch. 18 - A string of length L, mass pet unit length , and...Ch. 18 - In Example 18.1, we investigated an oscillator at...Ch. 18 - Prob. 18.4OQ Ch. 18 - A flute has a length of 58.0 cm. If the speed of...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

The tension in string if its second harmonic has the same frequency as the second resonance mode of a 1.75 m long pipe open at one end.

Solution Summary: The author determines the tension in string if its second harmonic has the same frequency as the second resonance mode of a 1.75m long pipe.

Concept explainers

Videos

The tension in string if its second harmonic has the same frequency as the second resonance mode of a 1.75 m long pipe open at one end.

Want to see the full answer?

Chapter 18 Solutions