(a) Interpretation: The products of the reaction between HCN and HO − are to be drawn. Concept introduction: The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H 2 O .

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Answer 1

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Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

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1/2 - 51% + » GAY Organic Reactions Assignment /26 Write the type of reaction that is occurring on the line provided then complete the reaction. Only include the major products and any byproducts (e.g. H₂O) but no minor products. Please use either full structural diagrams or the combination method shown in the lesson. Skeletal/line diagrams will not be accepted. H3C 1. 2. CH3 A Acid OH Type of Reaction: NH Type of Reaction: + H₂O Catalyst + HBr 3. Type of Reaction: H3C 4. Type Reaction: 5. H3C CH2 + H2O OH + [0] CH3 Type of Reaction: 6. OH CH3 HO CH3 + Type of Reaction: 7. Type of Reaction: + [H]

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If a reaction occurs, what would be the major products? Please include a detailed explanation as well as a drawing showing how the reaction occurs and what the final product is.

Answer 2

Question

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

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Answer 3

Question

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

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Answer 4

Question

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

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Answer 5

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

Answer 6

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Answer 7

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

Answer 9

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 18 - Prob. 18.1P Ch. 18 - Prob. 18.2P Ch. 18 - Prob. 18.3P Ch. 18 - Prob. 18.4P Ch. 18 - Prob. 18.5P Ch. 18 - Prob. 18.6P Ch. 18 - Prob. 18.7P Ch. 18 - Prob. 18.8P Ch. 18 - Prob. 18.9P Ch. 18 - Prob. 18.10P

(a) Interpretation: The products of the reaction between HCN and HO − are to be drawn. Concept introduction: The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H 2 O .

Solution Summary: The author explains that the products of the reaction between HCN and HO- are to be drawn.

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

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Chapter 18 Solutions

(a) Interpretation: The products of the reaction between HCN and HO − are to be drawn. Concept introduction: The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H 2 O .

Solution Summary: The author explains that the products of the reaction between HCN and HO- are to be drawn.

(a) Interpretation: The products of the reaction between HCN and HO− are to be drawn. Concept introduction: The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Want to see the full answer?

Chapter 18 Solutions

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.