Chapter 18, Problem 18.51P

(a)

Interpretation Introduction

Interpretation:

The balanced net ionic equation has to be written and the conjugate acid-base pair for the given ${\text{NaOH (aq) + NaH}}_{\text{2}}{\text{PO}}_{\text{4}}\text{(aq)}\to {\text{H}}_{\text{2}}{\text{O(l) + Na}}_{\text{2}}{\text{HPO}}_{\text{4}}\text{(aq)}$ has to be identified

Concept introduction:

The law of conservation of mass states that no atoms can be created or destroyed in a chemical reaction, therefore, the number of atoms present in the reactants is equal to the number of atoms present in the products.

Most of the ionic compounds are soluble in water, very few of the ionic compounds are sparingly soluble, and some of the ionic compounds are insoluble in water. When it is soluble in water ions gets separated in the solution.

Conjugate acid-Base pairs:

The acid donates the proton to form its conjugate base and the base accepts a proton to form its conjugate acid.

When an acid is dissolved in water, the acid $\text{(HA)}$ donates a proton to water to form a new acid (conjugate acid) and a new base (conjugate base).

The pair of an Acid –Base differs by a proton called conjugated Acid-Base pair.

(b)

Interpretation Introduction

Interpretation:

The balanced net ionic equation has to be written and the conjugate acid-base pair for the given ${\text{KHSO}}_{\text{4}}{\text{(aq) + K}}_{\text{2}}{\text{CO}}_{\text{3}}\text{(aq)}\to {\text{K}}_{\text{2}}{\text{SO}}_{\text{4}}{\text{(aq) + KHCO}}_{\text{3}}\text{(aq)}$ has to be identified.

Concept introduction:

The law of conservation of mass states that no atoms can be created or destroyed in a chemical reaction, therefore, the number of atoms present in the reactants is equal to the number of atoms present in the products.

Most of the ionic compounds are soluble in water, very few of the ionic compounds are sparingly soluble, and some of the ionic compounds are insoluble in water. When it is soluble in water ions gets separated in the solution.

Conjugate acid-Base pairs:

The acid donates the proton to form its conjugate base and the base accepts a proton to form its conjugate acid.

When an acid is dissolved in water, the acid $\text{(HA)}$ donates a proton to water to form a new acid (conjugate acid) and a new base (conjugate base).

The pair of an Acid –Base differs by a proton called conjugated Acid-Base pair.