PHYSICAL CHEMISTRY-STUDENT SOLN.MAN.
PHYSICAL CHEMISTRY-STUDENT SOLN.MAN.
2nd Edition
ISBN: 9781285074788
Author: Ball
Publisher: CENGAGE L
Question
Book Icon
Chapter 18, Problem 18.4E
Interpretation Introduction

(a)

Interpretation:

The numbers of terms for the summation of the electronic partition function for N2 gas at standard temperature is to be stated.

Concept introduction:

Different linearly independent wavefunctions that have same energy are called degenerate. This is expressed in terms of degeneracy. If two functions are having same energy then they are called doubly degenerate and so on. The electronic partition function is represented as,

qelect=igiei/kT

Expert Solution
Check Mark

Answer to Problem 18.4E

The numbers of terms for the summation of the electronic partition function for N2 gas at standard temperature are 46.

Explanation of Solution

The term symbol of a diatomic compound is represented as,

2S+1ΛΩ

Where,

S represents the total spin of the molecule.

Λ represents the axial component of L.

Ω represents the axial component of total angular quantum number J.

The term (Λ) of diatomic molecule is represented by Greek symbols such as Σ, Π, Δ and Φ. The term Ω is represented by either alphabet u or g.

From the referred Table, the state of 14N2 are represented as,

[ x" (1Σu+),x' (1Πu),1Πg,u5,u4,s,r,q,p,o5 1Πu,O5 (3Πu),c'n 1Σu+,cn 1Πu,cn 1Πu,o4 1Πu,O4 (3Πu),c'5 1Σu+,c4 1Πu,c4 1Πu,1Δg,1Πg,k 1Πg,1Σg-,d' 1Σu- or 1Δu,o3 1Πu,3Φu,c'4 1Σu+,c3 1Πu,b' 1Σu+,3Σu+,b 1Πu,a" 1Σg+,C' 3Πu,3Σg+,C" 5Πu,3Πu,3Δg,A' 5Σg+,1Δu,1Πg,a' 1Σu-,B' 3Σu-,3Δu,3Πg,3Σu+,1Σg+]

The total number of states of 14N2 is 46.

The electronic partition function is represented as,

qelect=igiei/kT

Where,

gi represents the degeneracy.

i represents the energy of ith microstate.

k represents the Boltzmann constant with value 1.381×1023J/K.

T represents the temperature (K).

The number of terms in the electronic partition function will be equal to the number of states. Therefore, the numbers of terms for the summation of the electronic partition function for N2 gas at standard temperature are 46.

Conclusion

The numbers of terms for the summation of the electronic partition function for N2 gas at standard temperature are 46.

Interpretation Introduction

(b)

Interpretation:

The numbers of terms for the summation of the electronic partition function for O2 gas at standard temperature is to be stated.

Concept introduction:

Different linearly independent wavefunctions that have same energy are called degenerate. This is expressed in terms of degeneracy. If two functions are having same energy then they are called doubly degenerate and so on. The electronic partition function is represented as,

qelect=igiei/kT

Expert Solution
Check Mark

Answer to Problem 18.4E

The numbers of terms for the summation of the electronic partition function for O2 gas at standard temperature are 37.

Explanation of Solution

The term symbol of a diatomic compound is represented as,

2S+1ΛΩ

Where,

S represents the total spin of the molecule.

Λ represents the axial component of L.

Ω represents the axial component of total angular quantum number J.

The term (Λ) of diatomic molecule is represented by Greek symbols such as Σ, Π, Δ and Φ. The term Ω is represented by either alphabet u or g.

From the referred Table, the state of 16O2 are represented as,

[Z  (2Πu), Y,W(3Σu+) ,V, U,R,Q,P, 1Φu,I", I', I,H (3Πu),4f,L( 3Πu),K( 1Δu),J(1Σu+),G(3Σu+),i( 1Δ2u),i( 3Δ2u),h(1Πu),g(1Πu),F*,F3Πu,E3Σu-,F 1Σu+,D( 3Σu+), e( 1Δ2u),e*( 3Δ2u),d( 1Πg),c( 3Πg),B3Σu-,A3Σu+,A3Δu,c1Σu-,b1Σg+,a1Δg,x3Σg]

The total number of states of O2 is 37.

The electronic partition function is represented as,

qelect=igiei/kT

Where,

gi represents the degeneracy.

i represents the energy of ith microstate.

k represents the Boltzmann constant with value 1.381×1023J/K.

T represents the temperature (K).

The number of terms in the electronic partition function will be equal to the number of states. Therefore, the numbers of terms for the summation of the electronic partition function for O2 gas at standard temperature are 37.

Conclusion

The numbers of terms for the summation of the electronic partition function for O2 gas at standard temperature are 37.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3
Show work. don't give Ai generated solution.  How many carbons and hydrogens are in the structure?
13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…

Chapter 18 Solutions

PHYSICAL CHEMISTRY-STUDENT SOLN.MAN.

Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
  • Text book image
    Physical Chemistry
    Chemistry
    ISBN:9781133958437
    Author:Ball, David W. (david Warren), BAER, Tomas
    Publisher:Wadsworth Cengage Learning,
Text book image
Physical Chemistry
Chemistry
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Wadsworth Cengage Learning,