Concept explainers
(a)
Interpretation:
The value of
Concept introduction:
The point at which the bond between the two atoms become nonexistent thus the molecule exists as two separated atoms are known as dissociation limit. The relation between
Where,
•
•
•
•
(b)
Interpretation:
Whether it is expected that
Concept introduction:
The point at which the bond between the two atoms become nonexistent thus the molecule exists as two separated atoms are known as dissociation limit. The relation between
Where,
•
•
•
•
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PHYSICAL CHEMISTRY-STUDENT SOLN.MAN.
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- (e) The mean bond enthalpy for chlorine is +242 kJ mol·l and that for fluorine is +158 kJ mol-". The enthalpy of formation of CIF (g) is 56 kJ mol·l (ii) Calculate the enthalpy of formation of, gaseous Chlorine Trifluoride, CIF3 (g), using the bond enthalpy value you obtained in part (i). (iii) The bond enthalpy of CIF3 calculated in part (ii) is likely to be different than that determined from experiment. Explain.arrow_forwardCombustion reactions involve reacting a substance with oxygen. When compounds containing carbon and hydrogen are combusted, carbon dioxide and water are the products. Using the enthalpies of combustion for C₂H₂ (-1300. kJ/mol), C₂H6 (-1560. kJ/mol), and H₂ (-286 kJ/mol), calculate AH for the reaction C₂H₂(g) + 2H₂(g) → C₂H6 (9) ΔΗ - Submit Answer Try Another Version Titem attempt remaining Cengage Learning Cengage Technical Support Previous Next> Email Instructor Save and Exitarrow_forwardAcetylene (C2H2) and nitrogen (N2) both contain a triplebond, but they differ greatly in their chemical properties.(a) Write the Lewis structures for the two substances. (b) By referring to Appendix C, look up the enthalpies of formationof acetylene and nitrogen. Which compound is more stable?(c) Write balanced chemical equations for the completeoxidation of N2 to form N2O5(g) and of acetylene to formCO2(g) and H2O(g). (d) Calculate the enthalpy of oxidationper mole for N2 and for C2H2 (the enthalpy of formationof N2O5(g) is 11.30 kJ/mol). (e) Both N2 and C2H2 possesstriple bonds with quite high bond enthalpies (Table 8.3).Calculate the enthalpy of hydrogenation per mole for bothcompounds: acetylene plus H2 to make methane, CH4;nitrogen plus H2 to make ammonia, NH3.arrow_forward
- Fructose, C6H1206(S), consists of 5 C-C single bonds, 7 C-O bonds, 7 C-H bonds, and 5 O-H bonds with average bond energies of 348 kJ/mol, 360 kJ/mol, 412 kJ/mol, and 463 kJ/mol respectively. The bond energy for C=O is 799 kJ/mol and O=O is 498 kJ/mol. The molar mass of fructose is 180.12 g/mol. Estimate the change in enthalpy if 2.56 g of fructose undergoes complete combustion at standard temperature and pressure.arrow_forward1. Draw Lewis structures for ozone and for dioxygen. Using the data given below, qualitatively compare the bond enthalpies, bond orders, and bond lengths of these two compounds. O₂ (g) 20 (g) AH" = +498 kJ O(g) + O₂(g) →O, (g) AH-105 kJarrow_forwardGiven the bond enthalpies C=O (707), O=O (498), H—O (464), and C—H (414) in kJ/mol, compute Δ H° in kJ/mol for: CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(g) +259 -618 -259 -519 +618arrow_forward
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