pH of the solution for 7 .52×10 -4 M CsOH has to be calculated and the solution is acidic, basic or neutral also has be identified. Concept introduction: The concentration of H 3 O + is calculating by using following formula, K w = K a × K b K w = [H 3 O + ][OH - ] = 1 .0 × 10 − 14 The Relationships Among pH, pOH, and pKw pH = - log (H 3 O + ) pOH = - log (OH − ) pK w = pH + pOH = 14 .00 The pH is a unit of measure which describe the degree of alkanity or acidity of a solution. pH = − log [ H + ] A solution may be acidic and basic depends on relative strength of anions as an acid or base. Anions and cations can be acidic, basic and netural. Acidic have pH < 7 , basic have pH > 7 and netural have pH=7 .
pH of the solution for 7 .52×10 -4 M CsOH has to be calculated and the solution is acidic, basic or neutral also has be identified. Concept introduction: The concentration of H 3 O + is calculating by using following formula, K w = K a × K b K w = [H 3 O + ][OH - ] = 1 .0 × 10 − 14 The Relationships Among pH, pOH, and pKw pH = - log (H 3 O + ) pOH = - log (OH − ) pK w = pH + pOH = 14 .00 The pH is a unit of measure which describe the degree of alkanity or acidity of a solution. pH = − log [ H + ] A solution may be acidic and basic depends on relative strength of anions as an acid or base. Anions and cations can be acidic, basic and netural. Acidic have pH < 7 , basic have pH > 7 and netural have pH=7 .
pH of the solution for 7.52×10-4MCsOH has to be calculated and the solution is acidic, basic or neutral also has be identified.
Concept introduction:
The concentration of H3O+ is calculating by using following formula,
Kw = Ka × Kb
Kw = [H3O+][OH-] = 1.0×10−14
The Relationships Among pH, pOH, and pKw
pH = -log(H3O+)pOH = -log(OH−)
pKw = pH + pOH = 14.00
The pH is a unit of measure which describe the degree of alkanity or acidity of a solution.
pH = −log[H+]
A solution may be acidic and basic depends on relative strength of anions as an acid or base. Anions and cations can be acidic, basic and netural. Acidic have pH < 7, basic have pH > 7 and netural have pH=7.
(b)
Interpretation Introduction
Interpretation:
pOH of the solution for 1.59×10-3MHClO4 has to be calculated and the solution is acidic, basic or neutral also has be identified.
Concept introduction:
The concentration of H3O+ is calculating by using following formula,
Kw = Ka × Kb
Kw = [H3O+][OH-] = 1.0×10−14
The Relationships Among pH, pOH, and pKw
pH = -log(H3O+)pOH = -log(OH−)
pKw = pH + pOH = 14.00
The pH is a unit of measure which describe the degree of alkanity or acidity of a solution.
pH = −log[H+]
A solution may be acidic and basic depends on relative strength of anions as an acid or base. Anions and cations can be acidic, basic and netural. Acidic have pH < 7, basic have pH > 7 and netural have pH=7.
What are the major products of both of the organic reactions. Please be sure to use wedge and dash bonds to show the stereochemistry of the products if it is needed. Please include the final product as well as a digram/drawing to show the mechanism of the reaction.
K
Problem 16 of 24
Submit
Draw the starting structure that
would yield this product under these
conditions.
Select to Draw
1. NH4Cl, NaCN
2. HCI, H2O, A
NH3
+
0
Give detailed me detailed mechanism Solution with explanation needed. Don't give Ai generated solution. avoid handwritten Solution
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