To determine whether the given concentration has an equal concentration of [H 3 O + ] and [ CH 3 COO - ] Concept introduction: CH 3 COOH is a weak acid and will not completely dissociate into ions. The concentration of CH 3 COOH is already given in the question and the K a value of CH 3 COOH is 1.8 × 10 − 5 . Now, draw a reaction table and find the concentration of [ H 3 O + ] and the [ CH 3 COO - ] ions.
To determine whether the given concentration has an equal concentration of [H 3 O + ] and [ CH 3 COO - ] Concept introduction: CH 3 COOH is a weak acid and will not completely dissociate into ions. The concentration of CH 3 COOH is already given in the question and the K a value of CH 3 COOH is 1.8 × 10 − 5 . Now, draw a reaction table and find the concentration of [ H 3 O + ] and the [ CH 3 COO - ] ions.
Interpretation: To determine whether the given concentration has an equal concentration of [H3O+] and [CH3COO-]
Concept introduction: CH3COOH is a weak acid and will not completely dissociate into ions. The concentration of CH3COOH is already given in the question and the Ka value of CH3COOH is 1.8×10−5 . Now, draw a reaction table and find the concentration of [H3O+] and the [CH3COO-] ions.
b)
Interpretation Introduction
Interpretation: To determine whether the given concentration has an equal concentration of [H3O+] and [CH3COO-]
Concept introduction: CH3COOH is a weak acid and will not completely dissociate into ions. The concentration of CH3COOH is already given in the question and the Ka value of CH3COOH is 1.8×10−5 . The self-ionization of water will come into play because water can act both as a base and as an acid.
c)
Interpretation Introduction
Interpretation: To determine whether the given concentration has an equal concentration of [H3O+] and [CH3COO-]
Concept introduction: CH3COOH is a weak acid and will not completely dissociate into ions. The concentration of CH3COOH is already given in the question and the Ka value of CH3COOH is 1.8×10−5 . Find the pKa value and then substitute this in the equation of pH.