Concept explainers
Draw structures of the following derivatives.
- a. the 2,4-dinitrophenylhydrazone of benzaldehyde
- b. the semicarbazone of cyclobutanone
- c. cyclopropanone oxime
- d. the ethylene acetal of hexan-3-one
- e. acetaldehyde dimethyl acetal
- f. the methyl hemiacetal of formaldehyde
- g. the (E) isomer of the ethyl imine of propiophenone
- h. the hemiacetal form of 5-hydroxypentanal
(a)
Interpretation:
The structure of the given derivative is to be drawn.
Concept introduction:
Ketones and aldehydes show different types of reactions which results to form many different products. The nucleophilic addition reactions are the common reactions, which form products like imines, diols, alcohols, cyanohydrins, and alkenes.
Answer to Problem 18.37SP
The structure of the given derivative is shown in Figure 1.
Explanation of Solution
The given derivative is 2,4-dinitrophenylhydrazone of benzaldehyde.
The 2,4-dinitrophenylhydrazine is treated with benzaldehyde to form a 2,4-dinitrophenylhydrazone derivative.
The structure of 2,4-dinitrophenylhydrazone of benzaldehyde is given as,
Figure 1
(b)
Interpretation:
The structure of the given derivative is to be drawn.
Concept introduction:
Ketones and aldehydes show different types of reactions which results to form many different products. The nucleophilic addition reactions are the common reactions, which form products like imines, diols, alcohols, cyanohydrins, and alkenes.
Answer to Problem 18.37SP
The structure of the given derivative is shown in Figure 2.
Explanation of Solution
The given derivative is semicarbazone of cyclobutanone.
The cyclobutanone is treated with semicarbazide to form a semicarbazone derivative.
The structure of semicarbazone of cyclobutanone is given as,
Figure 2
(c)
Interpretation:
The structure of the given derivative is to be drawn.
Concept introduction:
Ketones and aldehydes show different types of reactions which results to form many different products. The nucleophilic addition reactions are the common reactions, which form products like imines, diols, alcohols, cyanohydrins, and alkenes.
Answer to Problem 18.37SP
The structure of the given derivative is shown in Figure 3.
Explanation of Solution
The given derivative is cyclopropanone oxime.
The cyclopropanone is treated with hydroxylamine to form an oxime.
The structure of cyclopropanone oxime is given as,
Figure 3
(d)
Interpretation:
The structure of the given derivative is to be drawn.
Concept introduction:
Ketones and aldehydes show different types of reactions which results to form many different products. The nucleophilic addition reactions are the common reactions, which form products like imines, diols, alcohols, cyanohydrins, and alkenes.
Answer to Problem 18.37SP
The structure of the given derivative is shown in Figure 4.
Explanation of Solution
The given derivative is ethylene acetal of hexan-3-one.
The ethylene glycol is treated with hexan-3-one to form ethylene acetal of hexan-3-one.
The structure of ethylene acetal of hexan-3-one is given as,
Figure 4
(e)
Interpretation:
The structure of the given derivative is to be drawn.
Concept introduction:
Ketones and aldehydes show different types of reactions which results to form many different products. The nucleophilic addition reactions are the common reactions, which form products like imines, diols, alcohols, cyanohydrins, and alkenes.
Answer to Problem 18.37SP
The structure of the given derivative is shown in Figure 5.
Explanation of Solution
The given derivative is acetaldehyde dimethyl acetal.
The acetaldehyde is treated with two moles of ethyl alcohol to form acetaldehyde dimethyl acetal.
The structure of acetaldehyde dimethyl acetal is given as,
Figure 5
(f)
Interpretation:
The structure of the given derivative is to be drawn.
Concept introduction:
Ketones and aldehydes show different types of reactions which results to form many different products. The nucleophilic addition reactions are the common reactions, which form products like imines, diols, alcohols, cyanohydrins, and alkenes.
Answer to Problem 18.37SP
The structure of the given derivative is shown in Figure 6.
Explanation of Solution
The given derivative is methyl hemiacetal of formaldehyde.
The structure of hemiacetal of formaldehyde is given as,
Figure 6
(g)
Interpretation:
The structure of the given derivative is to be drawn.
Concept introduction:
Ketones and aldehydes show different types of reactions which results to form many different products. The nucleophilic addition reactions are the common reactions, which form products like imines, diols, alcohols, cyanohydrins, and alkenes.
Answer to Problem 18.37SP
The structure of the given derivative is shown in Figure 7.
Explanation of Solution
The given derivative is (E)-isomer of the ethyl imine of propiophenone.
The propiophenone is treated with ethyl amine to form an ethyl imine derivative.
The structure of (E)-isomer of the ethyl imine of propiophenone is given as,
Figure 7
(h)
Interpretation:
The structure of the given derivative is to be drawn.
Concept introduction:
Ketones and aldehydes show different types of reactions which results to form many different products. The nucleophilic addition reactions are the common reactions, which form products like imines, diols, alcohols, cyanohydrins, and alkenes.
Answer to Problem 18.37SP
The structure of the given derivative is shown in Figure 8.
Explanation of Solution
The given derivative is hemiacetal of 5-hydroxypentanal.
The structure of hemiacetal of 5-hydroxypentanal is given as,
Figure 8
Want to see more full solutions like this?
Chapter 18 Solutions
EP ORGANIC CHEMISTRY -MOD.MASTERING 18W
- we were assigned to dilute 900ppm in to 18ppm by using only 250ml vol flask. firstly we did calc and convert 900ppm to 0.9 ppm to dilute in 1 liter. to begin the experiment we took 0,225g of kmno4 and dissolved in to 250 vol flask. then further we took 10 ml sample sol and dissolved in to 100 ml vol flask and put it in to a spectrometer and got value of 0.145A . upon further calc we got v2 as 50ml . need to find DF, % error (expval and accptVal), molarity, molality. please write the whole report. thank you The format, tables, introduction, procedure and observation, result, calculations, discussion and conclusionarrow_forwardQ5. Predict the organic product(s) for the following transformations. If no reaction will take place (or the reaction is not synthetically useful), write "N.R.". Determine what type of transition state is present for each reaction (think Hammond Postulate). I Br₂ CH3 F2, light CH3 Heat CH3 F₂ Heat Br2, light 12, light CH3 Cl2, light Noarrow_forwardNonearrow_forward
- In the phase diagram of steel (two components Fe and C), region A is the gamma austenite solid and region B contains the gamma solid and liquid. Indicate the degrees of freedom that the fields A and B have,arrow_forwardFor a condensed binary system in equilibrium at constant pressure, indicate the maximum number of phases that can exist.arrow_forwardPart V. Label ad match the carbons in compounds Jane and Diane w/ the corresponding peak no. in the Spectra (Note: use the given peak no. To label the carbons, other peak no are intentionally omitted) 7 4 2 -0.13 -0.12 -0.11 -0.10 -0.08 8 CI Jane 1 -0.09 5 210 200 190 180 170 160 150 140 130 120 110 100 -8 90 f1 (ppm) 11 8 172.4 172.0 f1 (ppr HO CI NH Diane 7 3 11 80 80 -80 -R 70 60 60 2 5 -8 50 40 8. 170 160 150 140 130 120 110 100 90 -0 80 70 20 f1 (ppm) 15 30 -20 20 -60 60 -0.07 -0.06 -0.05 -0.04 -0.03 -0.02 -0.01 -0.00 -0.01 10 -0.17 16 15 56 16 -0.16 -0.15 -0.14 -0.13 -0.12 -0.11 -0.10 -0.09 -0.08 -0.07 -0.06 -0.05 -0.04 17.8 17.6 17.4 17.2 17.0 f1 (ppm) -0.03 -0.02 550 106 40 30 20 20 -0.01 -0.00 F-0.01 10 0arrow_forward
- n Feb 3 A T + 4. (2 pts) Draw the structure of the major component of the Limonene isolated. Explain how you confirmed the structure. 5. (2 pts) Draw the fragment corresponding to the base peak in the Mass spectrum of Limonene. 6. (1 pts) Predict the 1H NMR spectral data of R-Limonene. Proton NMR: 5.3 pon multiplet (H Ringarrow_forwardPart VI. Ca H 10 O is the molecular formula of compound Tom and gives the in the table below. Give a possible structure for compound Tom. 13C Signals summarized C1 C2 C3 C4 C5 C6 C7 13C shift (ppm) 23.5 27.0 33.0 35.8 127 162 205 DEPT-90 + DEPT-135 + +arrow_forward2. Using the following data to calculate the value of AvapH o of water at 298K. AvapH o of water at 373K is 40.7 kJ/mol; molar heat capacity of liquid water at constant pressure is 75.2J mol-1 K-1 and molar heat capacity of water vapor at constant pressure is 33.6 J mol-1 K-1.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY