Chapter 18, Problem 18.30QP

Interpretation Introduction

Interpretation:

The free energy ($\Delta G_f^{°}$) values has to be calculated the $COC{l}_2$ formation reaction at ${25}^{°}C$.

Concept Information:

Free energy$({\text{ΔG}}^0)$: In thermodynamics free energy or Gibbs free energy is the energy that is used to express the total energy content of a system.  According to second law of thermodynamics, in all spontaneous process is associated with the decrease in free energy of the system.  That is the change in free energy will be negative.

$\begin{array}{l}ForareactionA+B\underset{}{\overset{}{\rightleftharpoons }}C+D\\ \Delta G=\Delta G°+RT\ln \left(\frac{[C][D]}{[A][B]}\right)\\ Here\Delta G°=\text{standared}\text{free}\text{energy}\text{change}\end{array}$

Unit of free energy: Since the term free energy represents the total energy of a system.  It has the same unit of energy, ${\text{kJmol}}^{\text{-1}}$

Kp:  The equilibrium constant calculated from the partial pressures of a reaction equation. It is used to express the relationship between product pressures and reactant pressures. It is unites number, although it relates the pressures.

$\begin{array}{l}\text{Kp}\text{=}\text{Kc}{\text{(RT)}}^{\text{Δn}}\text{(or})\\ Kc=\frac{\text{Kp}}{{\text{(RT)}}^{\text{Δn}}}(or)Kp={\text{(RT)}}^{\text{Δn}}\\ \text{Δn}\text{=Product - Reactant}\end{array}$