General Chemistry: Atoms First
General Chemistry: Atoms First
2nd Edition
ISBN: 9780321809261
Author: John E. McMurry, Robert C. Fay
Publisher: Prentice Hall
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Chapter 18, Problem 18.20CP

(a)

Interpretation Introduction

Interpretation:

Given compound is whether the compound is peroxide or superoxide has to be identified and chemical formula of this compound should be written.

Concept Introduction:

Molecular orbital theory:

Molecular orbital theory states that atomic orbitals lose their individuality and electrons of the molecule present in the new orbital called molecular orbital. A brief outline of this theory is given below.

  • Atomic orbital of equal energy combine together to form molecular orbital.
  • Shape of molecular orbital depending on the shapes of combining atomic orbital.
  • Bonding orbitals denoted by σ, π and δ and antibonding orbital are denoted by σ, π and δ.
  • Molecular orbital are filled in increasing order of their energies, starting with orbital of least energy.  This is called Aufbau principle.
  • A molecular orbital is filled with only two electrons with opposite spins.  This is called Paul’s exclusion principle.

Paramagnetic and diamagnetic nature:

If all electrons in the molecule are paired, the substance is diamagnetic nature and substance has unpaired electron(s) are called paramagnetic nature.

(b)

Interpretation Introduction

Interpretation:

Whether the given compound is attracted or repelled by magnetic field has to be identified.

Concept Introduction:

Paramagnetic substance: If the substance has unpaired electron(s) which is paramagnetic in nature.  Paramagnetic substance are attracted by magnetic fields due to having unpaired electron(s).

Diamagnetic substance: If all electrons in substance are paired which is diamagnetic in nature.  Diamagnetic substance are repelled by magnetic fields due to having no unpaired electron.

(c)

Interpretation Introduction

Interpretation:

The molecular orbital derived from the atomic 2p orbital of Oxygen containing binary compound of Potassium is given.  Oxygen-Oxygen bond energy and bond length in this compound with the corresponding properties of Oxygen molecule has to be compared.

(d)

Interpretation Introduction

Interpretation:

The given compound is treated with water, resulting aqueous solution is acidic or basic has to be explained.

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Chapter 18 Solutions

General Chemistry: Atoms First

Ch. 18.9 - Prob. 18.11PCh. 18.9 - Prob. 18.12CPCh. 18.10 - Prob. 18.13PCh. 18.10 - Prob. 18.14PCh. 18.13 - Prob. 18.15PCh. 18.13 - Prob. 18.16PCh. 18.13 - Prob. 18.17PCh. 18 - Prob. 18.18CPCh. 18 - Look at the location of elements A, B, C, and D in...Ch. 18 - Prob. 18.20CPCh. 18 - Prob. 18.21CPCh. 18 - Prob. 18.22CPCh. 18 - Prob. 18.23CPCh. 18 - Prob. 18.24CPCh. 18 - Prob. 18.25CPCh. 18 - Prob. 18.26CPCh. 18 - Prob. 18.27CPCh. 18 - Prob. 18.28SPCh. 18 - Prob. 18.29SPCh. 18 - Prob. 18.30SPCh. 18 - Prob. 18.31SPCh. 18 - Prob. 18.32SPCh. 18 - Prob. 18.33SPCh. 18 - Prob. 18.34SPCh. 18 - Prob. 18.35SPCh. 18 - Prob. 18.36SPCh. 18 - Prob. 18.37SPCh. 18 - Prob. 18.38SPCh. 18 - Prob. 18.39SPCh. 18 - Prob. 18.40SPCh. 18 - Prob. 18.41SPCh. 18 - Prob. 18.42SPCh. 18 - Prob. 18.43SPCh. 18 - Prob. 18.44SPCh. 18 - Prob. 18.45SPCh. 18 - Prob. 18.46SPCh. 18 - Prob. 18.47SPCh. 18 - Prob. 18.48SPCh. 18 - Prob. 18.49SPCh. 18 - Prob. 18.50SPCh. 18 - Prob. 18.51SPCh. 18 - Prob. 18.52SPCh. 18 - Prob. 18.53SPCh. 18 - Prob. 18.54SPCh. 18 - Prob. 18.55SPCh. 18 - Prob. 18.56SPCh. 18 - Prob. 18.57SPCh. 18 - Prob. 18.58SPCh. 18 - Prob. 18.59SPCh. 18 - Prob. 18.60SPCh. 18 - Prob. 18.61SPCh. 18 - Prob. 18.62SPCh. 18 - Prob. 18.63SPCh. 18 - Prob. 18.64SPCh. 18 - Prob. 18.65SPCh. 18 - Which is more acidic? (a) Cr2O3 or CrO3 (b) N2O5...Ch. 18 - Prob. 18.67SPCh. 18 - Prob. 18.68SPCh. 18 - Write a balanced net ionic equation for the...Ch. 18 - Prob. 18.70SPCh. 18 - Prob. 18.71SPCh. 18 - Prob. 18.72SPCh. 18 - Prob. 18.73SPCh. 18 - What products are formed when the following metals...Ch. 18 - Prob. 18.75SPCh. 18 - Draw MO energy-level diagrams for O2, O2, and O22,...Ch. 18 - Prob. 18.77SPCh. 18 - Prob. 18.78SPCh. 18 - Prob. 18.79SPCh. 18 - Prob. 18.80SPCh. 18 - Prob. 18.81SPCh. 18 - Prob. 18.82SPCh. 18 - Prob. 18.83SPCh. 18 - Prob. 18.84SPCh. 18 - Prob. 18.85SPCh. 18 - Why does boiler scale form when hard water is...Ch. 18 - Prob. 18.87SPCh. 18 - Prob. 18.88SPCh. 18 - Prob. 18.89SPCh. 18 - Prob. 18.90SPCh. 18 - Prob. 18.91SPCh. 18 - Prob. 18.92SPCh. 18 - Prob. 18.93SPCh. 18 - Prob. 18.94CHPCh. 18 - Prob. 18.95CHPCh. 18 - Prob. 18.96CHPCh. 18 - Prob. 18.97CHPCh. 18 - Prob. 18.98CHPCh. 18 - Prob. 18.99CHPCh. 18 - Prob. 18.100CHPCh. 18 - Prob. 18.101CHPCh. 18 - Prob. 18.102CHPCh. 18 - Prob. 18.103CHPCh. 18 - Use the standard heats of formation in Appendix B...Ch. 18 - Prob. 18.105CHPCh. 18 - Prob. 18.106CHPCh. 18 - Prob. 18.107CHPCh. 18 - Prob. 18.108CHPCh. 18 - Prob. 18.109CHPCh. 18 - A boiler with water that contained high...Ch. 18 - Prob. 18.111CHPCh. 18 - Prob. 18.112CHPCh. 18 - Prob. 18.113CHPCh. 18 - Prob. 18.114CHPCh. 18 - Prob. 18.116MPCh. 18 - Prob. 18.117MPCh. 18 - Prob. 18.118MPCh. 18 - Prob. 18.120MPCh. 18 - Prob. 18.121MPCh. 18 - Prob. 18.122MPCh. 18 - Prob. 18.123MP
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