General Chemistry: Atoms First
General Chemistry: Atoms First
2nd Edition
ISBN: 9780321809261
Author: John E. McMurry, Robert C. Fay
Publisher: Prentice Hall
bartleby

Concept explainers

Question
Book Icon
Chapter 18, Problem 18.102CHP

(a)

Interpretation Introduction

Interpretation: The balanced equation should be written for the reaction in which the O2 acts as an oxidizing agent.

Concept introduction:

Balanced reaction is a chemical reaction in which number of atoms for each element in the reaction and the total charge are same on both reactant side and the product side.

Steps in balancing the information

  • Step 1: Write the unbalanced equation
  • Step 2: Find the coefficient to balance the equation.
  • The coefficient should be reduced to the smallest whole number

A balanced equation should be obeying the law of conservation of mass. Law of conservation of mass states that, the number of atoms remains constant throughout the reaction, simply it can be stated as follows, “during a chemical reaction atoms are neither be created nor be destroyed”.

Oxidation: Losing electrons, increasing oxidation number.

Reduction: Gaining electron, decreasing oxidation number.

Oxidizing agent is a substance that removes electrons from another reactant in a chemical reaction and so it is reduced by taking electron onto itself and the reactant is oxidized by having its electron taken away.

Reducing agent is the element or compound in a redox reaction that donate an electron to another species and so it is oxidized.

(b)

Interpretation Introduction

Interpretation: The balanced equation should be written for the reaction in which the O3 acts as an oxidizing agent.

Concept introduction:

Balanced reaction is a chemical reaction in which number of atoms for each element in the reaction and the total charge are same on both reactant side and the product side.

Steps in balancing the information

  • Step 1: Write the unbalanced equation
  • Step 2: Find the coefficient to balance the equation.
  • The coefficient should be reduced to the smallest whole number

A balanced equation should be obeying the law of conservation of mass. Law of conservation of mass states that, the number of atoms remains constant throughout the reaction, simply it can be stated as follows, “during a chemical reaction atoms are neither be created nor be destroyed”.

Oxidation: Losing electrons, increasing oxidation number.

Reduction: Gaining electron, decreasing oxidation number.

Oxidizing agent is a substance that removes electrons from another reactant in a chemical reaction and so it is reduced by taking electron onto itself and the reactant is oxidized by having its electron taken away.

Reducing agent is the element or compound in a redox reaction that donate an electron to another species and so it is oxidized.

(c)

Interpretation Introduction

Interpretation: The balanced equation should be written for the reaction in which the H2O2 acts as an oxidizing agent.

Concept introduction:

Balanced reaction is a chemical reaction in which number of atoms for each element in the reaction and the total charge are same on both reactant side and the product side.

Steps in balancing the information

  • Step 1: Write the unbalanced equation
  • Step 2: Find the coefficient to balance the equation.
  • The coefficient should be reduced to the smallest whole number

A balanced equation should be obeying the law of conservation of mass. Law of conservation of mass states that, the number of atoms remains constant throughout the reaction, simply it can be stated as follows, “during a chemical reaction atoms are neither be created nor be destroyed”.

Oxidation: Losing electrons, increasing oxidation number.

Reduction: Gaining electron, decreasing oxidation number.

Oxidizing agent is a substance that removes electrons from another reactant in a chemical reaction and so it is reduced by taking electron onto itself and the reactant is oxidized by having its electron taken away.

Reducing agent is the element or compound in a redox reaction that donate an electron to another species and so it is oxidized.

(d)

Interpretation Introduction

Interpretation: The balanced equation should be written for the reaction in which the H2 acts as an oxidizing agent.

Concept introduction:

Balanced reaction is a chemical reaction in which number of atoms for each element in the reaction and the total charge are same on both reactant side and the product side.

Steps in balancing the information

  • Step 1: Write the unbalanced equation
  • Step 2: Find the coefficient to balance the equation.
  • The coefficient should be reduced to the smallest whole number

A balanced equation should be obeying the law of conservation of mass. Law of conservation of mass states that, the number of atoms remains constant throughout the reaction, simply it can be stated as follows, “during a chemical reaction atoms are neither be created nor be destroyed”.

Oxidation: Losing electrons, increasing oxidation number.

Reduction: Gaining electron, decreasing oxidation number.

Oxidizing agent is a substance that removes electrons from another reactant in a chemical reaction and so it is reduced by taking electron onto itself and the reactant is oxidized by having its electron taken away.

Reducing agent is the element or compound in a redox reaction that donate an electron to another species and so it is oxidized.

(e)

Interpretation Introduction

Interpretation: The balanced equation should be written for the reaction in which the H2O acts as an oxidizing agent.

Concept introduction:

Balanced reaction is a chemical reaction in which number of atoms for each element in the reaction and the total charge are same on both reactant side and the product side.

Steps in balancing the information

  • Step 1: Write the unbalanced equation
  • Step 2: Find the coefficient to balance the equation.
  • The coefficient should be reduced to the smallest whole number

A balanced equation should be obeying the law of conservation of mass. Law of conservation of mass states that, the number of atoms remains constant throughout the reaction, simply it can be stated as follows, “during a chemical reaction atoms are neither be created nor be destroyed”.

Oxidation: Losing electrons, increasing oxidation number.

Reduction: Gaining electron, decreasing oxidation number.

Oxidizing agent is a substance that removes electrons from another reactant in a chemical reaction and so it is reduced by taking electron onto itself and the reactant is oxidized by having its electron taken away.

Reducing agent is the element or compound in a redox reaction that donate an electron to another species and so it is oxidized.

Blurred answer
Students have asked these similar questions
please help
Experiment 1 Data Table 1: Conservation of Mass - Initial Mass Data Table 1 Data Table 2 Data Table 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Reaction Mass of test tube and 5.0% HC₂H₂O2 (g) # (A) (B) Mass of NaHCO, (g) Mass of balloon and NaHCO, (g) (C) 0.10 1 0829 14.38g 0.20 2 0.929 14.29g 0.35 1.00g 3 14.25g 0.50 1.14g 14.29 Experiment 1 Data Table 2: Moles of HC2H3O2 Reaction Volume of Mass of Moles of HC₂H₂O₂ 5.0% Vinegar (g) (ML) 5.0 0.25 0042 mol 2 5.0 0.25 0042 mol 3 5.0 0.25 0042 mol 5.0 0.25 0042 mol Experiment 1 Data Table 3: Moles of NaHCO3 Reaction Mass of NaHCO (g) 10g 20g 35g 50g Experiment 1 Data Table 4: Theoretical Yield of CO₂ Reaction # 1 2 3 Experiment 1 Total mass before reaction (g) (D=A+C) 15.29 15.21g 15.25g 15.349 Exercise 1 Data Table 1 Data Table 2 Data Table 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Exercise 1- Data Table 1 Data Table 2 DataTable 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Exercise 1- Moles of NaHCO 0012 mol 0025 mol 0044 mol 0062 mol…
The chemical reaction you investigated is a two-step reaction. What type of reaction occurs in each step? How did you determine your answer?

Chapter 18 Solutions

General Chemistry: Atoms First

Ch. 18.9 - Prob. 18.11PCh. 18.9 - Prob. 18.12CPCh. 18.10 - Prob. 18.13PCh. 18.10 - Prob. 18.14PCh. 18.13 - Prob. 18.15PCh. 18.13 - Prob. 18.16PCh. 18.13 - Prob. 18.17PCh. 18 - Prob. 18.18CPCh. 18 - Look at the location of elements A, B, C, and D in...Ch. 18 - Prob. 18.20CPCh. 18 - Prob. 18.21CPCh. 18 - Prob. 18.22CPCh. 18 - Prob. 18.23CPCh. 18 - Prob. 18.24CPCh. 18 - Prob. 18.25CPCh. 18 - Prob. 18.26CPCh. 18 - Prob. 18.27CPCh. 18 - Prob. 18.28SPCh. 18 - Prob. 18.29SPCh. 18 - Prob. 18.30SPCh. 18 - Prob. 18.31SPCh. 18 - Prob. 18.32SPCh. 18 - Prob. 18.33SPCh. 18 - Prob. 18.34SPCh. 18 - Prob. 18.35SPCh. 18 - Prob. 18.36SPCh. 18 - Prob. 18.37SPCh. 18 - Prob. 18.38SPCh. 18 - Prob. 18.39SPCh. 18 - Prob. 18.40SPCh. 18 - Prob. 18.41SPCh. 18 - Prob. 18.42SPCh. 18 - Prob. 18.43SPCh. 18 - Prob. 18.44SPCh. 18 - Prob. 18.45SPCh. 18 - Prob. 18.46SPCh. 18 - Prob. 18.47SPCh. 18 - Prob. 18.48SPCh. 18 - Prob. 18.49SPCh. 18 - Prob. 18.50SPCh. 18 - Prob. 18.51SPCh. 18 - Prob. 18.52SPCh. 18 - Prob. 18.53SPCh. 18 - Prob. 18.54SPCh. 18 - Prob. 18.55SPCh. 18 - Prob. 18.56SPCh. 18 - Prob. 18.57SPCh. 18 - Prob. 18.58SPCh. 18 - Prob. 18.59SPCh. 18 - Prob. 18.60SPCh. 18 - Prob. 18.61SPCh. 18 - Prob. 18.62SPCh. 18 - Prob. 18.63SPCh. 18 - Prob. 18.64SPCh. 18 - Prob. 18.65SPCh. 18 - Which is more acidic? (a) Cr2O3 or CrO3 (b) N2O5...Ch. 18 - Prob. 18.67SPCh. 18 - Prob. 18.68SPCh. 18 - Write a balanced net ionic equation for the...Ch. 18 - Prob. 18.70SPCh. 18 - Prob. 18.71SPCh. 18 - Prob. 18.72SPCh. 18 - Prob. 18.73SPCh. 18 - What products are formed when the following metals...Ch. 18 - Prob. 18.75SPCh. 18 - Draw MO energy-level diagrams for O2, O2, and O22,...Ch. 18 - Prob. 18.77SPCh. 18 - Prob. 18.78SPCh. 18 - Prob. 18.79SPCh. 18 - Prob. 18.80SPCh. 18 - Prob. 18.81SPCh. 18 - Prob. 18.82SPCh. 18 - Prob. 18.83SPCh. 18 - Prob. 18.84SPCh. 18 - Prob. 18.85SPCh. 18 - Why does boiler scale form when hard water is...Ch. 18 - Prob. 18.87SPCh. 18 - Prob. 18.88SPCh. 18 - Prob. 18.89SPCh. 18 - Prob. 18.90SPCh. 18 - Prob. 18.91SPCh. 18 - Prob. 18.92SPCh. 18 - Prob. 18.93SPCh. 18 - Prob. 18.94CHPCh. 18 - Prob. 18.95CHPCh. 18 - Prob. 18.96CHPCh. 18 - Prob. 18.97CHPCh. 18 - Prob. 18.98CHPCh. 18 - Prob. 18.99CHPCh. 18 - Prob. 18.100CHPCh. 18 - Prob. 18.101CHPCh. 18 - Prob. 18.102CHPCh. 18 - Prob. 18.103CHPCh. 18 - Use the standard heats of formation in Appendix B...Ch. 18 - Prob. 18.105CHPCh. 18 - Prob. 18.106CHPCh. 18 - Prob. 18.107CHPCh. 18 - Prob. 18.108CHPCh. 18 - Prob. 18.109CHPCh. 18 - A boiler with water that contained high...Ch. 18 - Prob. 18.111CHPCh. 18 - Prob. 18.112CHPCh. 18 - Prob. 18.113CHPCh. 18 - Prob. 18.114CHPCh. 18 - Prob. 18.116MPCh. 18 - Prob. 18.117MPCh. 18 - Prob. 18.118MPCh. 18 - Prob. 18.120MPCh. 18 - Prob. 18.121MPCh. 18 - Prob. 18.122MPCh. 18 - Prob. 18.123MP
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry by OpenStax (2015-05-04)
Chemistry
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:OpenStax