(a) Interpretation: The geometry of [ Zn ( CN ) 4 ] 2 − ion with the help of hybridization is to be predicted. Concept introduction: Hybridization is the mixing of orbitals. After mixing of orbitals, the hybrid orbital is formed which has lower energy than s and p orbitals. The hybrid orbitals give definite geometry to a molecule.

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Answer 1

Question

Chapter 18, Problem 18.13P

Interpretation Introduction

(a)

Interpretation:

The geometry of [Zn(CN)4]2− ion with the help of hybridization is to be predicted.

Concept introduction:

Hybridization is the mixing of orbitals. After mixing of orbitals, the hybrid orbital is formed which has lower energy than s and p orbitals. The hybrid orbitals give definite geometry to a molecule.

Interpretation Introduction

(b)

Interpretation:

The geometry of [Pd(PPh3)4] with the help of hybridization is to be predicted.

Concept introduction:

Hybridisation is the mixing of orbitals. After mixing of orbitals, the hybrid orbital is formed which has lower energy than s and p orbitals. The hybrid orbital gives definite geometry to a molecule.

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2. Use Hess's law to calculate the AH (in kJ) for: rxn CIF(g) + F2(g) → CIF 3 (1) using the following information: 2CIF(g) + O2(g) → Cl₂O(g) + OF 2(g) AH = 167.5 kJ ΔΗ 2F2 (g) + O2(g) → 2 OF 2(g) 2C1F3 (1) + 202(g) → Cl₂O(g) + 3 OF 2(g) о = = -43.5 kJ AH = 394.1kJ

Answer 2

Question

Chapter 18, Problem 18.13P

Interpretation Introduction

(a)

Interpretation:

The geometry of [Zn(CN)4]2− ion with the help of hybridization is to be predicted.

Concept introduction:

Hybridization is the mixing of orbitals. After mixing of orbitals, the hybrid orbital is formed which has lower energy than s and p orbitals. The hybrid orbitals give definite geometry to a molecule.

Interpretation Introduction

(b)

Interpretation:

The geometry of [Pd(PPh3)4] with the help of hybridization is to be predicted.

Concept introduction:

Hybridisation is the mixing of orbitals. After mixing of orbitals, the hybrid orbital is formed which has lower energy than s and p orbitals. The hybrid orbital gives definite geometry to a molecule.

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Answer 3

Question

Chapter 18, Problem 18.13P

Interpretation Introduction

(a)

Interpretation:

The geometry of [Zn(CN)4]2− ion with the help of hybridization is to be predicted.

Concept introduction:

Hybridization is the mixing of orbitals. After mixing of orbitals, the hybrid orbital is formed which has lower energy than s and p orbitals. The hybrid orbitals give definite geometry to a molecule.

Interpretation Introduction

(b)

Interpretation:

The geometry of [Pd(PPh3)4] with the help of hybridization is to be predicted.

Concept introduction:

Hybridisation is the mixing of orbitals. After mixing of orbitals, the hybrid orbital is formed which has lower energy than s and p orbitals. The hybrid orbital gives definite geometry to a molecule.

Expert Solution & Answer

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Answer 4

Question

Chapter 18, Problem 18.13P

Interpretation Introduction

(a)

Interpretation:

The geometry of [Zn(CN)4]2− ion with the help of hybridization is to be predicted.

Concept introduction:

Hybridization is the mixing of orbitals. After mixing of orbitals, the hybrid orbital is formed which has lower energy than s and p orbitals. The hybrid orbitals give definite geometry to a molecule.

Interpretation Introduction

(b)

Interpretation:

The geometry of [Pd(PPh3)4] with the help of hybridization is to be predicted.

Concept introduction:

Hybridisation is the mixing of orbitals. After mixing of orbitals, the hybrid orbital is formed which has lower energy than s and p orbitals. The hybrid orbital gives definite geometry to a molecule.

Expert Solution & Answer

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Answer 5

Chapter 18, Problem 18.13P

Interpretation Introduction

(a)

Interpretation:

The geometry of [Zn(CN)4]2− ion with the help of hybridization is to be predicted.

Concept introduction:

Hybridization is the mixing of orbitals. After mixing of orbitals, the hybrid orbital is formed which has lower energy than s and p orbitals. The hybrid orbitals give definite geometry to a molecule.

Interpretation Introduction

(b)

Interpretation:

The geometry of [Pd(PPh3)4] with the help of hybridization is to be predicted.

Concept introduction:

Hybridisation is the mixing of orbitals. After mixing of orbitals, the hybrid orbital is formed which has lower energy than s and p orbitals. The hybrid orbital gives definite geometry to a molecule.

Answer 6

Chapter 18, Problem 18.13P

Interpretation Introduction

(a)

Interpretation:

The geometry of [Zn(CN)4]2− ion with the help of hybridization is to be predicted.

Concept introduction:

Hybridization is the mixing of orbitals. After mixing of orbitals, the hybrid orbital is formed which has lower energy than s and p orbitals. The hybrid orbitals give definite geometry to a molecule.

Answer 7

Chapter 18, Problem 18.13P

Interpretation Introduction

(a)

Interpretation:

The geometry of [Zn(CN)4]2− ion with the help of hybridization is to be predicted.

Concept introduction:

Hybridization is the mixing of orbitals. After mixing of orbitals, the hybrid orbital is formed which has lower energy than s and p orbitals. The hybrid orbitals give definite geometry to a molecule.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The geometry of [Pd(PPh3)4] with the help of hybridization is to be predicted.

Concept introduction:

Hybridisation is the mixing of orbitals. After mixing of orbitals, the hybrid orbital is formed which has lower energy than s and p orbitals. The hybrid orbital gives definite geometry to a molecule.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The geometry of [Pd(PPh3)4] with the help of hybridization is to be predicted.

Concept introduction:

Hybridisation is the mixing of orbitals. After mixing of orbitals, the hybrid orbital is formed which has lower energy than s and p orbitals. The hybrid orbital gives definite geometry to a molecule.

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

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Answer 13

Ch. 18 - Prob. 18.1P Ch. 18 - Prob. 18.2P Ch. 18 - Prob. 18.3P Ch. 18 - Prob. 18.4P Ch. 18 - Prob. 18.5P Ch. 18 - Prob. 18.6P Ch. 18 - Prob. 18.7P Ch. 18 - Prob. 18.8P Ch. 18 - Prob. 18.9P Ch. 18 - Prob. 18.10P

Solution Summary: The author explains how the geometry of left[Zn] is tetrahedral with the help of hybridization.

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Chapter 18 Solutions