Whether one or more galactose monosaccharide unit is/are present in sucrose has to be predicted. Concept introduction: Sucrose is a disaccharide and it contains two monosaccharide units, Fructose and Glucose. These monosaccharide units are joined together by α , β ( 1 → 2 ) glycosidic linkage.

Question

Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following: (a) match structures of isomers given their mass spectra below (spectra A and spectra B) (b) Draw the fragments given the following prominent peaks from each spectrum: Spectra A m/2 =43 and 1/2-57 spectra B m/2 = 43 (c) why is 1/2=57 peak in spectrum A more intense compared to the same peak in spectrum B. Relative abundance Relative abundance 100 A 50 29 29 0 10 -0 -0 100 B 50 720 30 41 43 57 71 4-0 40 50 60 70 m/z 43 57 8-0 m/z = 86 M 90 100 71 m/z = 86 M -O 0 10 20 30 40 50 60 70 80 -88 m/z 90 100

Answer 1

Question

Chapter 18, Problem 18.139EP

(a)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in sucrose has to be predicted.

Concept introduction: Sucrose is a disaccharide and it contains two monosaccharide units, Fructose and Glucose. These monosaccharide units are joined together by α,β(1→2) glycosidic linkage.

(b)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in ribose has to be predicted.

Concept introduction: Monosaccharides are those types of sugars which cannot be further hydrolyzed. Ribose is a pentose.

(c)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in stachyose has to be predicted.

Concept introduction: Monosaccharides are those types of sugars which cannot be further hydrolyzed. If two monosaccharides combine, then the sugar is called disaccharide. If three monosaccharides combine, then the sugar is called trisaccharide. Stachyose is a tetrasaccharide.

(d)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in lactose has to be predicted.

Concept introduction: Lactose is a disaccharide and it contains two monosaccharide units, D-galactose and D-glucose which are joined together by β(1→4) glycosidic linkage.

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Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following: (a) match structures of isomers given their mass spectra below (spectra A and spectra B) (b) Draw the fragments given the following prominent peaks from each spectrum: Spectra A m/2 =43 and 1/2-57 spectra B m/2 = 43 (c) why is 1/2=57 peak in spectrum A more intense compared to the same peak in spectrum B. Relative abundance Relative abundance 100 A 50 29 29 0 10 -0 -0 100 B 50 720 30 41 43 57 71 4-0 40 50 60 70 m/z 43 57 8-0 m/z = 86 M 90 100 71 m/z = 86 M -O 0 10 20 30 40 50 60 70 80 -88 m/z 90 100

Part IV. C6H5 CH2CH2OH is an aromatic compound which was subjected to Electron Ionization - mass spectrometry (El-MS) analysis. Prominent m/2 values: m/2 = 104 and m/2 = 9) was obtained. Draw the structures of these fragments.

For each reaction shown below follow the curved arrows to complete each equationby showing the structure of the products. Identify the acid, the base, the conjugated acid andconjugated base. Consutl the pKa table and choose the direciton theequilibrium goes. However show the curved arrows. Please explain if possible.

Answer 2

Question

Chapter 18, Problem 18.139EP

(a)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in sucrose has to be predicted.

Concept introduction: Sucrose is a disaccharide and it contains two monosaccharide units, Fructose and Glucose. These monosaccharide units are joined together by α,β(1→2) glycosidic linkage.

(b)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in ribose has to be predicted.

Concept introduction: Monosaccharides are those types of sugars which cannot be further hydrolyzed. Ribose is a pentose.

(c)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in stachyose has to be predicted.

Concept introduction: Monosaccharides are those types of sugars which cannot be further hydrolyzed. If two monosaccharides combine, then the sugar is called disaccharide. If three monosaccharides combine, then the sugar is called trisaccharide. Stachyose is a tetrasaccharide.

(d)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in lactose has to be predicted.

Concept introduction: Lactose is a disaccharide and it contains two monosaccharide units, D-galactose and D-glucose which are joined together by β(1→4) glycosidic linkage.

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Answer 3

Question

Chapter 18, Problem 18.139EP

(a)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in sucrose has to be predicted.

Concept introduction: Sucrose is a disaccharide and it contains two monosaccharide units, Fructose and Glucose. These monosaccharide units are joined together by α,β(1→2) glycosidic linkage.

(b)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in ribose has to be predicted.

Concept introduction: Monosaccharides are those types of sugars which cannot be further hydrolyzed. Ribose is a pentose.

(c)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in stachyose has to be predicted.

Concept introduction: Monosaccharides are those types of sugars which cannot be further hydrolyzed. If two monosaccharides combine, then the sugar is called disaccharide. If three monosaccharides combine, then the sugar is called trisaccharide. Stachyose is a tetrasaccharide.

(d)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in lactose has to be predicted.

Concept introduction: Lactose is a disaccharide and it contains two monosaccharide units, D-galactose and D-glucose which are joined together by β(1→4) glycosidic linkage.

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Answer 4

Question

Chapter 18, Problem 18.139EP

(a)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in sucrose has to be predicted.

Concept introduction: Sucrose is a disaccharide and it contains two monosaccharide units, Fructose and Glucose. These monosaccharide units are joined together by α,β(1→2) glycosidic linkage.

(b)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in ribose has to be predicted.

Concept introduction: Monosaccharides are those types of sugars which cannot be further hydrolyzed. Ribose is a pentose.

(c)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in stachyose has to be predicted.

Concept introduction: Monosaccharides are those types of sugars which cannot be further hydrolyzed. If two monosaccharides combine, then the sugar is called disaccharide. If three monosaccharides combine, then the sugar is called trisaccharide. Stachyose is a tetrasaccharide.

(d)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in lactose has to be predicted.

Concept introduction: Lactose is a disaccharide and it contains two monosaccharide units, D-galactose and D-glucose which are joined together by β(1→4) glycosidic linkage.

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Answer 5

Chapter 18, Problem 18.139EP

(a)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in sucrose has to be predicted.

Concept introduction: Sucrose is a disaccharide and it contains two monosaccharide units, Fructose and Glucose. These monosaccharide units are joined together by α,β(1→2) glycosidic linkage.

(b)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in ribose has to be predicted.

Concept introduction: Monosaccharides are those types of sugars which cannot be further hydrolyzed. Ribose is a pentose.

(c)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in stachyose has to be predicted.

Concept introduction: Monosaccharides are those types of sugars which cannot be further hydrolyzed. If two monosaccharides combine, then the sugar is called disaccharide. If three monosaccharides combine, then the sugar is called trisaccharide. Stachyose is a tetrasaccharide.

(d)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in lactose has to be predicted.

Concept introduction: Lactose is a disaccharide and it contains two monosaccharide units, D-galactose and D-glucose which are joined together by β(1→4) glycosidic linkage.

Answer 6

Chapter 18, Problem 18.139EP

(a)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in sucrose has to be predicted.

Concept introduction: Sucrose is a disaccharide and it contains two monosaccharide units, Fructose and Glucose. These monosaccharide units are joined together by α,β(1→2) glycosidic linkage.

Answer 7

Chapter 18, Problem 18.139EP

(a)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in sucrose has to be predicted.

Concept introduction: Sucrose is a disaccharide and it contains two monosaccharide units, Fructose and Glucose. These monosaccharide units are joined together by α,β(1→2) glycosidic linkage.

Answer 8

(b)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in ribose has to be predicted.

Concept introduction: Monosaccharides are those types of sugars which cannot be further hydrolyzed. Ribose is a pentose.

Answer 9

(b)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in ribose has to be predicted.

Concept introduction: Monosaccharides are those types of sugars which cannot be further hydrolyzed. Ribose is a pentose.

Answer 10

(c)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in stachyose has to be predicted.

Concept introduction: Monosaccharides are those types of sugars which cannot be further hydrolyzed. If two monosaccharides combine, then the sugar is called disaccharide. If three monosaccharides combine, then the sugar is called trisaccharide. Stachyose is a tetrasaccharide.

Answer 11

(c)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in stachyose has to be predicted.

Concept introduction: Monosaccharides are those types of sugars which cannot be further hydrolyzed. If two monosaccharides combine, then the sugar is called disaccharide. If three monosaccharides combine, then the sugar is called trisaccharide. Stachyose is a tetrasaccharide.

Answer 12

(d)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in lactose has to be predicted.

Concept introduction: Lactose is a disaccharide and it contains two monosaccharide units, D-galactose and D-glucose which are joined together by β(1→4) glycosidic linkage.

Answer 13

(d)

Interpretation Introduction

Interpretation: Whether one or more galactose monosaccharide unit is/are present in lactose has to be predicted.

Concept introduction: Lactose is a disaccharide and it contains two monosaccharide units, D-galactose and D-glucose which are joined together by β(1→4) glycosidic linkage.

Answer 14

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Ch. 18.1 - In terms of mass percent, which of the following...Ch. 18.1 - Which of the following is the most abundant type...Ch. 18.2 - Which of the following statements concerning the...Ch. 18.2 - Prob. 2QQ Ch. 18.3 - Prob. 1QQ Ch. 18.3 - Prob. 2QQ Ch. 18.3 - Which of the following is not a possible value for...Ch. 18.3 - The complete hydrolysis of a polysaccharide...Ch. 18.4 - Prob. 1QQ Ch. 18.4 - Prob. 2QQ

Whether one or more galactose monosaccharide unit is/are present in sucrose has to be predicted. Concept introduction: Sucrose is a disaccharide and it contains two monosaccharide units, Fructose and Glucose. These monosaccharide units are joined together by α , β ( 1 → 2 ) glycosidic linkage.

Solution Summary: The author explains the structure of sucrose, ribose, and tetrasaccharides.

Concept explainers

Interpretation: Whether one or more galactose monosaccharide unit is/are present in ribose has to be predicted.

Concept introduction: Monosaccharides are those types of sugars which cannot be further hydrolyzed. Ribose is a pentose.

Interpretation: Whether one or more galactose monosaccharide unit is/are present in lactose has to be predicted.

Concept introduction: Lactose is a disaccharide and it contains two monosaccharide units, D-galactose and D-glucose which are joined together by β(1→4) glycosidic linkage.

Chapter 18 Solutions

Whether one or more galactose monosaccharide unit is/are present in sucrose has to be predicted. Concept introduction: Sucrose is a disaccharide and it contains two monosaccharide units, Fructose and Glucose. These monosaccharide units are joined together by α , β ( 1 → 2 ) glycosidic linkage.

Solution Summary: The author explains the structure of sucrose, ribose, and tetrasaccharides.

Concept explainers

Interpretation: Whether one or more galactose monosaccharide unit is/are present in ribose has to be predicted. Concept introduction: Monosaccharides are those types of sugars which cannot be further hydrolyzed. Ribose is a pentose.

Interpretation: Whether one or more galactose monosaccharide unit is/are present in lactose has to be predicted. Concept introduction: Lactose is a disaccharide and it contains two monosaccharide units, D-galactose and D-glucose which are joined together by β(1→4) glycosidic linkage.

Chapter 18 Solutions

Interpretation: Whether one or more galactose monosaccharide unit is/are present in ribose has to be predicted.

Concept introduction: Monosaccharides are those types of sugars which cannot be further hydrolyzed. Ribose is a pentose.

Interpretation: Whether one or more galactose monosaccharide unit is/are present in lactose has to be predicted.

Concept introduction: Lactose is a disaccharide and it contains two monosaccharide units, D-galactose and D-glucose which are joined together by β(1→4) glycosidic linkage.