Concept explainers
(a)
Interpretation: The term monosaccharide, disaccharide, reducing sugar, anomers, enantiomer and aldohexoses whether applies to both the members of the given pair or not has to be stated.
Concept introduction: Monosaccharides are those type of sugars which cannot be hydrolysed further.
Disaccharides are those type of sugars which have two units of monosaccharides.
The enantiomers are the molecules that form non-superimposable mirror images of each other.
Carbon atom which behaves as a stereocenter in the cyclic form of the hemiacetal compound is known as anomeric carbon. The molecule containing the anomeric carbon is called anomer.
The monosaccharides that have
The sugars that have a free carbonyl group are called reducing sugars.
(b)
Interpretation: The term monosaccharide, disaccharide, reducing sugar, anomers, enantiomer and aldohexoses whether applies to both the members of the given pair or not has to be stated.
Concept introduction: Monosaccharides are those type of sugars which cannot be hydrolysed further.
Disaccharides are those type of sugars which have two units of monosaccharides.
The enantiomers are the molecules that form non-superimposable mirror images of each other.
Carbon atom which behaves as a stereocenter in the cyclic form of the hemiacetal compound is known as anomeric carbon. The molecule containing the anomeric carbon is called anomer.
The monosaccharides that have aldehyde as a functional group and a long chain of six carbon atoms are called aldohexoses.
The sugars that have a free carbonyl group are called reducing sugars.
(c)
Interpretation: The term monosaccharide, disaccharide, reducing sugar, anomers, enantiomer and aldohexoses whether applies to both the members of the given pair or not has to be stated.
Concept introduction: Monosaccharides are those type of sugars which cannot be hydrolysed further.
Disaccharides are those type of sugars which have two units of monosaccharides.
The enantiomers are the molecules that form non-superimposable mirror images of each other.
Carbon atom which behaves as a stereocenter in the cyclic form of the hemiacetal compound is known as anomeric carbon. The molecule containing the anomeric carbon is called anomer.
The monosaccharides that have aldehyde as a functional group and a long chain of six carbon atoms are called aldohexoses.
The sugars that have a free carbonyl group are called reducing sugars.
(d)
Interpretation: The term monosaccharide, disaccharide, reducing sugar, anomers, enantiomer and aldohexoses whether applies to both the members of the given pair or not has to be stated.
Concept introduction: Monosaccharides are those type of sugars which cannot be hydrolysed further.
Disaccharides are those type of sugars which have two units of monosaccharides.
The enantiomers are the molecules that form non-superimposable mirror images of each other.
Carbon atom which behaves as a stereocenter in the cyclic form of the hemiacetal compound is known as anomeric carbon. The molecule containing the anomeric carbon is called anomer.
The monosaccharides that have aldehyde as a functional group and a long chain of six carbon atoms are called aldohexoses.
The sugars that have a free carbonyl group are called reducing sugars.
Want to see the full answer?
Check out a sample textbook solutionChapter 18 Solutions
EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
- The decomposition of dinitrogen pentoxide according to the equation: 50°C 2 N2O5(g) 4 NO2(g) + O2(g) follows first-order kinetics with a rate constant of 0.0065 s-1. If the initial concentration of N2O5 is 0.275 M, determine: the final concentration of N2O5 after 180 seconds. ...arrow_forwardDon't used hand raitingarrow_forwardCS2(g) →CS(g) + S(g) The rate law is Rate = k[CS2] where k = 1.6 × 10−6 s−¹. S What is the concentration of CS2 after 5 hours if the initial concentration is 0.25 M?arrow_forward
- CS2(g) → CS(g) + S(g) The rate law is Rate = k [CS2] where k = 1.6 × 10-6 s−1. S Calculate the half-life.arrow_forwardThe following is a first order reaction where the rate constant, k, is 6.29 x 10-3 min-*** What is the half-life? C2H4 C2H2 + H2arrow_forwardControl Chart Drawing Assignment The table below provides the number of alignment errors observed during the final inspection of a certain model of airplane. Calculate the central, upper, and lower control limits for the c-chart and draw the chart precisely on the graph sheet provided (based on 3-sigma limits). Your chart should include a line for each of the control limits (UCL, CL, and LCL) and the points for each observation. Number the x-axis 1 through 25 and evenly space the numbering for the y-axis. Connect the points by drawing a line as well. Label each line drawn. Airplane Number Number of alignment errors 201 7 202 6 203 6 204 7 205 4 206 7 207 8 208 12 209 9 210 9 211 8 212 5 213 5 214 9 215 8 216 15 217 6 218 4 219 13 220 7 221 8 222 15 223 6 224 6 225 10arrow_forward
- Collagen is used to date artifacts. It has a rate constant = 1.20 x 10-4 /years. What is the half life of collagen?arrow_forwardיווי 10 20 30 40 50 60 70 3.5 3 2.5 2 1.5 1 [ppm] 3.5 3 2.5 2 1.5 1 6 [ppm] 1 1.5 -2.5 3.5arrow_forward2H2S(g)+3O2(g)→2SO2(g)+2H2O(g) A 1.2mol sample of H2S(g) is combined with excess O2(g), and the reaction goes to completion. Question Which of the following predicts the theoretical yield of SO2(g) from the reaction? Responses 1.2 g Answer A: 1.2 grams A 41 g Answer B: 41 grams B 77 g Answer C: 77 grams C 154 g Answer D: 154 grams Darrow_forward
- Part VII. Below are the 'HNMR, 13 C-NMR, COSY 2D- NMR, and HSQC 2D-NMR (similar with HETCOR but axes are reversed) spectra of an organic compound with molecular formula C6H1003 - Assign chemical shift values to the H and c atoms of the compound. Find the structure. Show complete solutions. Predicted 1H NMR Spectrum 4.7 4.6 4.5 4.4 4.3 4.2 4.1 4.0 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 f1 (ppm) Predicted 13C NMR Spectrum 100 f1 (ppm) 30 220 210 200 190 180 170 160 150 140 130 120 110 90 80 70 -26 60 50 40 46 30 20 115 10 1.0 0.9 0.8 0 -10arrow_forwardQ: Arrange BCC and Fec metals, in sequence from the Fable (Dr. R's slides) and Calculate Volume and Density. Aa BCC V 52 5 SFCCarrow_forwardNonearrow_forward
- Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning