Starting Out with C++ from Control Structures to Objects Plus MyLab Programming with Pearson eText -- Access Card Package (9th Edition)
9th Edition
ISBN: 9780134544847
Author: Tony Gaddis
Publisher: PEARSON
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Chapter 18, Problem 12PC
Program Plan Intro
Double Merge
Program Plan:
“NumberList.h”:
- Include the required specifications into the program.
- Define a class named “NumberList”.
- Declare the member variables “value” and “*next” in structure named “ListNode”.
- Declare the constructor, copy constructor, destructor, and member functions in the class.
“NumberList.cpp”:
- Include the required header files into the program.
- Define a function named “appendNode()” to insert the node at end of the list.
- Declare the structure pointer variables “newNode” and “nodePtr” for the structure named “ListNode”.
- Assign the value of received variable “num” into “newNode” and assign the “newNode” address into null.
- Using “if…else” condition check whether the list is empty or not, if the “head” is empty and make a new node into “head” pointer. Otherwise, make a loop find last node in the loop.
- Assign “newNode” into the variable “nodePtr” value.
- Define a function named “displayList()” to print the values in the list.
- Declare the structure pointer “nodePtr” for the structure named “ListNode”.
- Initialize the variable “dataPtr” with the “head” pointer.
- Make a loop “while” to display the values of the list.
- Define a function named “insertNode()” used to insert a value into the list.
- Declare the structure pointer variables “newNode”, “dataPtr”, and “prev” for the structure named “ListNode”.
- Make a “newNode” value into the received variable value “num”.
- Using “if…else” condition to check whether the list is empty or not.
- If the list is empty, initialize a value into “head” pointer with the value of “newNode” variable.
- Otherwise, make a “while” loop to test the “num” value is less than the list values.
- Using “if…else” condition to initialize the value into list.
- Define a function named “deleteNode()” to delete a value from the list.
- Declare the structure pointer variables “nodePtr”, and “previousNode” for the structure named “ListNode”.
- Using “if…else” condition to check the “head” value equal to “num”.
- Initialize the address of “nodePtr” to the “head”.
- Remove the value using “delete” operator and reassign the “head” value into the “nodePtr”.
- If the “num” value not equal to the “head” value, define the “while” loop to assign the “nodePtr” into “previousNode”.
- Using “if” condition to delete the “previousNode” pointer.
- Define a destructor named “~NumberList()” to destroy the list values from the memory.
- Declare the structure pointer variables “nodePtr”, and “nextNode” for the structure named “ListNode”.
- Initialize the “head” value into the “nodePtr”.
- Define a “while” loop to make the links of node into “nextNode” and remove the node using “delete” operator.
- Define a member function named “mergeArray()” to merge the array into list.
- Using “for” loop to insert a value of the array into list.
- Make a call to “insertNode()” function to insert an index value of received array “dArray” into list.
“main.cpp”:
- Include the required header files into the program.
- Declare a constant variable “n” and initialize a value as “5”.
- Declare and define a variable “arr” in type of array.
- Make an object named “obj” for the class “NumberList” and call the member functions “append()” and “display()” using the object.
- Make a call to “mergeArray()” with arguments of “arr” and “n” and then print the list using “displayList()” function.
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Chapter 18 Solutions
Starting Out with C++ from Control Structures to Objects Plus MyLab Programming with Pearson eText -- Access Card Package (9th Edition)
Ch. 18.1 - Prob. 18.1CPCh. 18.1 - Prob. 18.2CPCh. 18.1 - Prob. 18.3CPCh. 18.1 - Prob. 18.4CPCh. 18.2 - Prob. 18.5CPCh. 18.2 - Prob. 18.6CPCh. 18.2 - Prob. 18.7CPCh. 18.2 - Prob. 18.8CPCh. 18.2 - Prob. 18.9CPCh. 18.2 - Prob. 18.10CP
Ch. 18 - Prob. 1RQECh. 18 - Prob. 2RQECh. 18 - Prob. 3RQECh. 18 - Prob. 4RQECh. 18 - Prob. 5RQECh. 18 - Prob. 6RQECh. 18 - Prob. 7RQECh. 18 - Prob. 8RQECh. 18 - Prob. 9RQECh. 18 - Prob. 10RQECh. 18 - Prob. 11RQECh. 18 - Prob. 12RQECh. 18 - Prob. 13RQECh. 18 - Prob. 14RQECh. 18 - Prob. 15RQECh. 18 - Prob. 16RQECh. 18 - Prob. 17RQECh. 18 - Prob. 18RQECh. 18 - Prob. 19RQECh. 18 - Prob. 20RQECh. 18 - Prob. 21RQECh. 18 - Prob. 22RQECh. 18 - Prob. 23RQECh. 18 - Prob. 24RQECh. 18 - Prob. 25RQECh. 18 - T F The programmer must know in advance how many...Ch. 18 - T F It is not necessary for each node in a linked...Ch. 18 - Prob. 28RQECh. 18 - Prob. 29RQECh. 18 - Prob. 30RQECh. 18 - Prob. 31RQECh. 18 - Prob. 32RQECh. 18 - Prob. 33RQECh. 18 - Prob. 34RQECh. 18 - Prob. 35RQECh. 18 - Prob. 1PCCh. 18 - Prob. 2PCCh. 18 - Prob. 3PCCh. 18 - Prob. 4PCCh. 18 - Prob. 5PCCh. 18 - Prob. 6PCCh. 18 - Prob. 7PCCh. 18 - List Template Create a list class template based...Ch. 18 - Prob. 9PCCh. 18 - Prob. 10PCCh. 18 - Prob. 11PCCh. 18 - Prob. 12PCCh. 18 - Prob. 13PCCh. 18 - Prob. 14PCCh. 18 - Prob. 15PC
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