All the functional groups present in phenacetin have to be identified Concept Introduction: Carboxylic acid : One − O H group is attached to the carbonyl carbon atom of the compound. It is represented as R C O O H Ether: Ether is a group of organic compound where two aryl or alkyl groups are connected by an oxygen atom. It is represented as R O R ' . Amide: One − N H 2 , − N H R ' or − N R ' 2 group is attached to the carbonyl carbon atom of the compound. It is represented as R C O N R ' 2 . Aromatic Compounds: Compounds that are planar, cyclic and having ( 4 n + 2 ) π electrons are known as aromatic compounds.

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Answer 1

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Chapter 17.3, Problem 17.21P

(a)

Interpretation Introduction

Interpretation:

All the functional groups present in phenacetin have to be identified

Concept Introduction:

Carboxylic acid: One $−OH$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCOOH$

Ether: Ether is a group of organic compound where two aryl or alkyl groups are connected by an oxygen atom. It is represented as $ROR'$ .

Amide: One $−NH2$ , $−NHR'$ or $−NR'2$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCONR'2$ .

Aromatic Compounds: Compounds that are planar, cyclic and having $(4n+2)π$ electrons are known as aromatic compounds.

(b)

Interpretation Introduction

Interpretation:

The carboxylic acid and amine that are needed to form phenacetin has to be drawn.

Concept introduction:

Carboxylic acid: One $−OH$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCOOH$

Amide: One $−NH2$ , $−NHR'$ or $−NR'2$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCONR'2$ .

Amide Formation: Amide is formed when a carboxylic acid reacts with an amine or ammonia.

Primary amide is produce when a carboxylic acid reacts with ammonia.

Secondary and tertiary amide is produce when a carboxylic acid reacts with primary and secondary amine respectively.

Ammonium salt is formed when tertiary amine and a carboxylic acid reacts forming an ionic compound with a carboxylate acid anion and a trialkyl ammonium cation since there is no hydrogen atom in trialkyl amine

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Answer 2

Question

Chapter 17.3, Problem 17.21P

(a)

Interpretation Introduction

Interpretation:

All the functional groups present in phenacetin have to be identified

Concept Introduction:

Carboxylic acid: One $−OH$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCOOH$

Ether: Ether is a group of organic compound where two aryl or alkyl groups are connected by an oxygen atom. It is represented as $ROR'$ .

Amide: One $−NH2$ , $−NHR'$ or $−NR'2$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCONR'2$ .

Aromatic Compounds: Compounds that are planar, cyclic and having $(4n+2)π$ electrons are known as aromatic compounds.

(b)

Interpretation Introduction

Interpretation:

The carboxylic acid and amine that are needed to form phenacetin has to be drawn.

Concept introduction:

Carboxylic acid: One $−OH$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCOOH$

Amide: One $−NH2$ , $−NHR'$ or $−NR'2$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCONR'2$ .

Amide Formation: Amide is formed when a carboxylic acid reacts with an amine or ammonia.

Primary amide is produce when a carboxylic acid reacts with ammonia.

Secondary and tertiary amide is produce when a carboxylic acid reacts with primary and secondary amine respectively.

Ammonium salt is formed when tertiary amine and a carboxylic acid reacts forming an ionic compound with a carboxylate acid anion and a trialkyl ammonium cation since there is no hydrogen atom in trialkyl amine

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Answer 3

Question

Chapter 17.3, Problem 17.21P

(a)

Interpretation Introduction

Interpretation:

All the functional groups present in phenacetin have to be identified

Concept Introduction:

Carboxylic acid: One $−OH$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCOOH$

Ether: Ether is a group of organic compound where two aryl or alkyl groups are connected by an oxygen atom. It is represented as $ROR'$ .

Amide: One $−NH2$ , $−NHR'$ or $−NR'2$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCONR'2$ .

Aromatic Compounds: Compounds that are planar, cyclic and having $(4n+2)π$ electrons are known as aromatic compounds.

(b)

Interpretation Introduction

Interpretation:

The carboxylic acid and amine that are needed to form phenacetin has to be drawn.

Concept introduction:

Carboxylic acid: One $−OH$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCOOH$

Amide: One $−NH2$ , $−NHR'$ or $−NR'2$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCONR'2$ .

Amide Formation: Amide is formed when a carboxylic acid reacts with an amine or ammonia.

Primary amide is produce when a carboxylic acid reacts with ammonia.

Secondary and tertiary amide is produce when a carboxylic acid reacts with primary and secondary amine respectively.

Ammonium salt is formed when tertiary amine and a carboxylic acid reacts forming an ionic compound with a carboxylate acid anion and a trialkyl ammonium cation since there is no hydrogen atom in trialkyl amine

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Answer 4

Question

Chapter 17.3, Problem 17.21P

(a)

Interpretation Introduction

Interpretation:

All the functional groups present in phenacetin have to be identified

Concept Introduction:

Carboxylic acid: One $−OH$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCOOH$

Ether: Ether is a group of organic compound where two aryl or alkyl groups are connected by an oxygen atom. It is represented as $ROR'$ .

Amide: One $−NH2$ , $−NHR'$ or $−NR'2$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCONR'2$ .

Aromatic Compounds: Compounds that are planar, cyclic and having $(4n+2)π$ electrons are known as aromatic compounds.

(b)

Interpretation Introduction

Interpretation:

The carboxylic acid and amine that are needed to form phenacetin has to be drawn.

Concept introduction:

Carboxylic acid: One $−OH$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCOOH$

Amide: One $−NH2$ , $−NHR'$ or $−NR'2$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCONR'2$ .

Amide Formation: Amide is formed when a carboxylic acid reacts with an amine or ammonia.

Primary amide is produce when a carboxylic acid reacts with ammonia.

Secondary and tertiary amide is produce when a carboxylic acid reacts with primary and secondary amine respectively.

Ammonium salt is formed when tertiary amine and a carboxylic acid reacts forming an ionic compound with a carboxylate acid anion and a trialkyl ammonium cation since there is no hydrogen atom in trialkyl amine

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Answer 5

Chapter 17.3, Problem 17.21P

(a)

Interpretation Introduction

Interpretation:

All the functional groups present in phenacetin have to be identified

Concept Introduction:

Carboxylic acid: One $−OH$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCOOH$

Ether: Ether is a group of organic compound where two aryl or alkyl groups are connected by an oxygen atom. It is represented as $ROR'$ .

Amide: One $−NH2$ , $−NHR'$ or $−NR'2$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCONR'2$ .

Aromatic Compounds: Compounds that are planar, cyclic and having $(4n+2)π$ electrons are known as aromatic compounds.

(b)

Interpretation Introduction

Interpretation:

The carboxylic acid and amine that are needed to form phenacetin has to be drawn.

Concept introduction:

Carboxylic acid: One $−OH$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCOOH$

Amide: One $−NH2$ , $−NHR'$ or $−NR'2$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCONR'2$ .

Amide Formation: Amide is formed when a carboxylic acid reacts with an amine or ammonia.

Primary amide is produce when a carboxylic acid reacts with ammonia.

Secondary and tertiary amide is produce when a carboxylic acid reacts with primary and secondary amine respectively.

Ammonium salt is formed when tertiary amine and a carboxylic acid reacts forming an ionic compound with a carboxylate acid anion and a trialkyl ammonium cation since there is no hydrogen atom in trialkyl amine

Answer 6

Chapter 17.3, Problem 17.21P

(a)

Interpretation Introduction

Interpretation:

All the functional groups present in phenacetin have to be identified

Concept Introduction:

Carboxylic acid: One $−OH$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCOOH$

Ether: Ether is a group of organic compound where two aryl or alkyl groups are connected by an oxygen atom. It is represented as $ROR'$ .

Amide: One $−NH2$ , $−NHR'$ or $−NR'2$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCONR'2$ .

Aromatic Compounds: Compounds that are planar, cyclic and having $(4n+2)π$ electrons are known as aromatic compounds.

Answer 7

Chapter 17.3, Problem 17.21P

(a)

Interpretation Introduction

Interpretation:

All the functional groups present in phenacetin have to be identified

Concept Introduction:

Carboxylic acid: One $−OH$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCOOH$

Ether: Ether is a group of organic compound where two aryl or alkyl groups are connected by an oxygen atom. It is represented as $ROR'$ .

Amide: One $−NH2$ , $−NHR'$ or $−NR'2$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCONR'2$ .

Aromatic Compounds: Compounds that are planar, cyclic and having $(4n+2)π$ electrons are known as aromatic compounds.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The carboxylic acid and amine that are needed to form phenacetin has to be drawn.

Concept introduction:

Carboxylic acid: One $−OH$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCOOH$

Amide: One $−NH2$ , $−NHR'$ or $−NR'2$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCONR'2$ .

Amide Formation: Amide is formed when a carboxylic acid reacts with an amine or ammonia.

Primary amide is produce when a carboxylic acid reacts with ammonia.

Secondary and tertiary amide is produce when a carboxylic acid reacts with primary and secondary amine respectively.

Ammonium salt is formed when tertiary amine and a carboxylic acid reacts forming an ionic compound with a carboxylate acid anion and a trialkyl ammonium cation since there is no hydrogen atom in trialkyl amine

Answer 9

(b)

Interpretation Introduction

Interpretation:

The carboxylic acid and amine that are needed to form phenacetin has to be drawn.

Concept introduction:

Carboxylic acid: One $−OH$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCOOH$

Amide: One $−NH2$ , $−NHR'$ or $−NR'2$ group is attached to the carbonyl carbon atom of the compound. It is represented as $RCONR'2$ .

Amide Formation: Amide is formed when a carboxylic acid reacts with an amine or ammonia.

Primary amide is produce when a carboxylic acid reacts with ammonia.

Secondary and tertiary amide is produce when a carboxylic acid reacts with primary and secondary amine respectively.

Ammonium salt is formed when tertiary amine and a carboxylic acid reacts forming an ionic compound with a carboxylate acid anion and a trialkyl ammonium cation since there is no hydrogen atom in trialkyl amine

Answer 10

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Answer 12

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Answer 13

Ch. 17.1 - Identify the following molecules as a carboxylic...Ch. 17.1 - Prob. 17.2P Ch. 17.1 - Prob. 17.3P Ch. 17.1 - Prob. 17.4P Ch. 17.1 - Prob. 17.5P Ch. 17.1 - Prob. 17.6P Ch. 17.1 - In the following pairs of compounds, which would...Ch. 17.1 - Write both condensed and line structures for (a)...Ch. 17.1 - Prob. 17.9P Ch. 17.1 - Draw structures corresponding to these names: (a)...

Solution Summary: The author explains that all the functional groups present in phenacetin have to be identified.

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