
Concept explainers
(a)
Interpretation: The IUPAC name of the following compound should be determined:
Concept Introduction:
The hydrocarbon compounds are the compound containing only hydrogen and carbon atoms, compounds that contain carbon-carbon multiple bond(s) are said to be
In order to give the name to the unsaturated hydrocarbon following steps are followed:
1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.
2. While writing the name of alkene, the suffix “ane” of the corresponding
3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.
4. Hyphen is used to connect the number to the name.
For number of carbons atoms in alkane chain, the prefix is given as:
Carbon-1 meth
Carbon-2 eth
Carbon-3 prop
Carbon-4 but
Carbon-5 pent
Carbon-6 hex
Carbon-7 hept
Carbon-8 oct
Carbon-9 non
Carbon-10 dec
(b)
Interpretation: The IUPAC name of the following compound should be determined:
Concept Introduction:
The hydrocarbon compounds are the compound containing only hydrogen and carbon atoms, compounds that contain carbon-carbon multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.
In order to give the name to the unsaturated hydrocarbon following steps are followed:
1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.
2. While writing the name of alkyne, the suffix “ane” of the corresponding alkane is replaced by “yne”.
3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.
4. Hyphen is used to connect the number to the name.
For number of carbons atoms in alkane chain, the prefix is given as:
Carbon-1 meth
Carbon-2 eth
Carbon-3 prop
Carbon-4 but
Carbon-5 pent
Carbon-6 hex
Carbon-7 hept
Carbon-8 oct
Carbon-9 non
Carbon-10 dec
(c)
Interpretation: The IUPAC name of the following compound should be determined:
Concept Introduction:
The hydrocarbon compounds are the compound containing only hydrogen and carbon atoms, compounds that contain carbon-carbon multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.
In order to give the name to the unsaturated hydrocarbon following steps are followed:
1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.
2. While writing the name of alkene, the suffix “ane” of the corresponding alkane is replaced by “ene”.
3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.
4. Hyphen is used to connect the number to the name.
For number of carbons atoms in alkane chain, the prefix is given as:
Carbon-1 meth
Carbon-2 eth
Carbon-3 prop
Carbon-4 but
Carbon-5 pent
Carbon-6 hex
Carbon-7 hept
Carbon-8 oct
Carbon-9 non
Carbon-10 dec

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Chapter 17 Solutions
EBK BASIC CHEMISTRY
- What alkene or alkyne yields the following products after oxidative cleavage with ozone? Click the "draw structure" button to launch the drawing utility. and two equivalents of CH2=O draw structure ...arrow_forwardH-Br Energy 1) Draw the step-by-step mechanism by which 3-methylbut-1-ene is converted into 2-bromo-2-methylbutane. 2) Sketch a reaction coordinate diagram that shows how the internal energy (Y- axis) of the reacting species change from reactants to intermediate(s) to product. Brarrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). C5H10 H-CI CH2Cl2 CIarrow_forward
- Draw the products of the stronger acid protonating the other reactant. དའི་སྐད”“ H3C OH H3C CH CH3 KEq Product acid Product basearrow_forwardDraw the products of the stronger acid protonating the other reactant. H3C NH2 NH2 KEq H3C-CH₂ 1. Product acid Product basearrow_forwardWhat alkene or alkyne yields the following products after oxidative cleavage with ozone? Click the "draw structure" button to launch the drawing utility. draw structure ... andarrow_forward
- Draw the products of the stronger acid protonating the other reactant. H3C-C=C-4 NH2 KEq CH H3C `CH3 Product acid Product basearrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). C5H10 Br H-Br CH2Cl2 + enant.arrow_forwardDraw the products of the stronger acid protonating the other reactant. KEq H₂C-O-H H3C OH Product acid Product basearrow_forward
- Draw the products of the stronger acid protonating the other reactant. OH KEq CH H3C H3C `CH3 Product acid Product basearrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). Ph H-I CH2Cl2arrow_forward3 attempts left Check my work Draw the products formed in the following oxidative cleavage. [1] 03 [2] H₂O draw structure ... lower mass product draw structure ... higher mass productarrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781285199030Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning

